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2 votes
1 answer
246 views

Reconstruction of Riemann surface from a germ of holomorphic function

Let $\Sigma$ be a compact Riemann surface of genus $g$, and $f: \Sigma \to \mathbb{C}$ a meromorphic function. Take $U \subset \Sigma$ an open disk in $\Sigma$ biholomorphic to a disk in $\mathbb{C}$, ...
Student's user avatar
  • 5,230
18 votes
2 answers
1k views

Proving algebraicity of compact Riemann surfaces without Chow's theorem

I am trying to write a report for a complex analysis class where I prove Riemann-Roch and apply it to prove algebraicity of compact Riemann surfaces. While writing this, I found that Riemann-Roch ...
Jas Singh's user avatar
  • 283
4 votes
0 answers
229 views

Real part of a holomorphic section of a vector bundle

Let $F\to M$ be a holomorphic vector bundle over a complex manifold $M$ and let $s:M\to F$ be a no-zero section. Let $E$ be the complexification of $F$, and suppose that $E$ admits a holomorphic ...
user158773's user avatar
4 votes
1 answer
279 views

Shrinking the boundary of a Riemann surface

Let $X$ be a compact Riemann surface with boundary. Let us shrink each connected component of the boundary into a point. We get a closed topological surface $Z$ with several marked points (which came ...
asv's user avatar
  • 21.8k
29 votes
7 answers
7k views

Elementary proof of Riemann-Roch for compact Riemann surfaces

I am supposed to give a talk about the Riemann-Roch theorem to a seminar of first and second year graduate students. I want to do Riemann-Roch for compact Riemann surfaces, but I am open to perhaps ...
user avatar
4 votes
3 answers
687 views

Finite covers of punctured Riemann surfaces

Let $X$ be a compact Riemann surface, i.e. compact smooth complex analytic (hence automatically algebraic) curve. Let $A\subset X$ be a finite subset, and $X_0:=X\backslash A$. Let $Y_0$ be a smooth ...
asv's user avatar
  • 21.8k
11 votes
3 answers
3k views

Is a non-compact Riemann surface an open subset of a compact one ?

Let $X$ be a non-compact holomorphic manifold of dimension $1$. Is there a compact Riemann surface $\bar{X}$ suc that $X$ is biholomorphic to an open subset of $\bar{X}$ ? Edit: To rule out the case ...
Qfwfq's user avatar
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