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Analytic continuation and convergence of a Riemann zeta related function

The functions in question are $$L(s)=\sum_{k=1}^\infty \frac{\lambda(k)}{k^s}=\frac{\zeta(2s)}{\zeta(s)} \mbox{ and } L^*(s)=\frac{1}{2}\sum_{k=1}^\infty \frac{\lambda(k)+(-1)^{k+1}}{k^s}=\frac{L(s)+\...
Vincent Granville's user avatar
1 vote
0 answers
381 views

Analytic continuation of Euler product $\phi(s)=\prod_p(1+p^{-s})^{-1}$

I am actually interested in the analytic continuation of $\phi_w(s)=\prod_p(1+w\cdot p^{-s})^{-1}$. Here $w$ is rational, or the imaginary unit multiplied by a rational. Consider for now that $w=1$. ...
Vincent Granville's user avatar
0 votes
2 answers
682 views

On integral relating logarithm of absolute value of Zeta function

Sorry for such a direct question: Consider the following integral: $$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da.$$ How to find the nature of $I(t)$ as $t\rightarrow\infty$?
TPC's user avatar
  • 774
2 votes
1 answer
561 views

On infinite sum containing logarithmic derivative of Zeta function and Möbius function:

Consider the following function: $$F(s)= \sum_m \mu(m) \sum_n \frac{e^{-n/2}\zeta^\prime (mns)}{n \zeta(mns)}$$ Now, we can see, that function has simple poles ${\left[\frac{1}{n}\right]}_{n=1}^\...
Zaza's user avatar
  • 149
14 votes
2 answers
2k views

Is $\pi (x)=\operatorname{R}(x)-\sum_{\rho}\operatorname{R}(x^{\rho})$ correct at all?

It should be the case that, in some appropriate sense $$\pi (x)\sim \operatorname{Ri}(x)-\sum_{\rho}\operatorname{Ri}(x^{\rho}) \tag{4}\label{386213_4}$$ with $\operatorname{Ri}$ denoting the Riemann ...
Wane's user avatar
  • 83
5 votes
1 answer
660 views

Maximal analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}$

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$ What's the maximal analytic continuation of $\varphi(s)?$ Doing this will help me better understand how ...
geocalc33's user avatar
  • 105
0 votes
1 answer
379 views

On some property of the zeros of $\zeta(s)$ in the complex plane

This property is rather elementary, and not at all specific to $\zeta$, so I am wondering if it has any value in studying the zeros of the Riemann zeta function in the critical strip. It is a well ...
Vincent Granville's user avatar
29 votes
1 answer
2k views

Riemann's attempts to prove RH

I read somewhere that Riemann believed he could find a representation of the zeta function that would allow him to show that all the non-trivial zeros of the zeta function lie on the critical line. I ...
Mustafa Said's user avatar
  • 3,699
23 votes
1 answer
3k views

More mysteries about the zeros of the Riemann zeta function

Update on 12/26/2020: I added the Appendix at the bottom: simplified formula for $|\zeta(s)|^2$, when $\frac{1}{2}<\Re(s)<1$. Update on 1/5/2020: I added the section "more interesting ...
Vincent Granville's user avatar
2 votes
0 answers
210 views

Binomial transform of Dirchlet series (2)

Referring to this MO question, i managed to do the following : We denote by $J(k+1,z)$ the sum : $$J(n+1,z)=\sum_{k=0}^{n}(-1)^{k}\binom{n}{k}\frac{\theta(k+1)}{(k+1)^{z}}$$ and by $S(k+1,z)$ the sum :...
mohammad-83's user avatar
2 votes
4 answers
3k views

Prove that the real part of this limit converges to $\frac{1}{2}$

Let $s= 1/3 + 14i$. Prove that the real part of this limit converges to $\frac{1}{2}$: $$ \Re\lim_{n \rightarrow \infty} \left( \left[ 1- \left( \sum _{k=1}^n \frac{(-1)^{k-1} \binom{n-1}{...
Mats Granvik's user avatar
  • 1,183
17 votes
2 answers
2k views

Algebraic independence of shifts of the Riemann zeta function

Let $\zeta(s)$ denote the Riemann zeta function. Is the set $\{ \zeta(s-j)\, \colon\, j\in\mathbb{Z}\}$, or even $\{\zeta(s-z)\, \colon\, z\in\mathbb{C}\}$, algebraically independent over $\mathbb{C}$?...
Richard Stanley's user avatar
0 votes
1 answer
607 views

On Soundararajan's explicit formula

I'm reading Soundararajan's https://arxiv.org/pdf/0705.0723.pdf, and on page 5, one has $$\sum_{n\leq x} \frac{\Lambda(n)}{n^z} \log (x/n) = -\frac{\zeta'}{\zeta}(z)\log x - \Big(\frac{\zeta'}{\zeta}(...
Q_p's user avatar
  • 1,019
5 votes
0 answers
161 views

On the asymptotics of some sum involving the Mertens function

Let $a_n$ be a sequence of nonnegative real numbers such that $\sum_{n\leq x} a_n \gg \frac{\sqrt x}{\log x}$ for large enough $x$. Denote by $\mu$ the Mobius function, and let $M(N)=\sum_{n\leq N} \...
Q_p's user avatar
  • 1,019
14 votes
1 answer
1k views

What is the analytic continuation of $\varphi(s)=\sum_{n \ge 1} e^{-n^s}?$

My research has lead me to the following function that I'm trying to continue. 3 Months ago I posted this question to MSE, and have placed 3 bounties on the question, but haven't received an answer, ...
geocalc33's user avatar
  • 105
7 votes
2 answers
788 views

Reference request for the explicit formula for $\sum_{n\leq x} \Lambda(n)n^{-s}$

Denote by $\Lambda(n)$ the von Mangoldt function, which is equal to $\log p$ if $p\geq 2$ is a prime, and $0$ otherwise. Let $\rho$ denote a complex zero of the Riemann $\zeta$-function. If I recall ...
Q_p's user avatar
  • 1,019
4 votes
1 answer
924 views

A question on the use of fractional derivatives in Riemann Hypothesis

We already know that Riemann-zeta function on the critical band is defined as follows: $$(1-2^{1-\alpha})\zeta(\alpha) = \sum_{k=1}^{\infty} (-1)^{k+1}k^{-\alpha},\quad \Re(\alpha) \in ]0, 1[ $$ Is ...
Tahar Nguira's user avatar
4 votes
0 answers
126 views

What is the closed form of this integral?

Consider the Chebyshev first function $\psi(y):=\sum_{p^j \leq y} \log p$, where $p$ is a prime. Define $$F(s, k) = s\int_{1}^{\infty} \psi(x + x^k)x^{-s-1} \mathrm{d}x$$ for $ \Re(s) >$ max $(1, ...
user156584's user avatar
9 votes
1 answer
939 views

A question on the Riemann zeta function

Yesterday, a certain very talented and passionate young student from Southern Africa asked me the following question about the Riemann zeta function $\zeta(s)$. He says he "thinks" he knows the answer,...
non-number theorist's user avatar
4 votes
4 answers
514 views

Does there exist a rational polynomial $P(x)\in{\mathbb Q}[x]{}$ such that $P(\zeta(s))=\zeta(P(s))$?

let $P(x)\in{\mathbb Q}[x]{}$ be a rational polynomial with $P(1) >1$ and $\zeta $ be the Riemann zeta function , I want to know if there exist a rational polynomial such that $P(\zeta(s))=\zeta(P(...
zeraoulia rafik's user avatar
0 votes
0 answers
108 views

A line integral involving $\zeta(s)$

Let $x>1$ and $\zeta$ denote the Riemann zeta function. Is the equality $$\int_{\sigma - i \infty}^{\sigma + i \infty} \frac{\zeta(s)x^{s}}{s(s+1)(s+2)\cdots (s+k)} \mathrm{d}s = 2\pi i$$ possible ...
user152442's user avatar
1 vote
0 answers
105 views

sum involving Riemann zeta function

In my work arose the following series: $$g(s) = \sum_{n = 0}^\infty \frac{\log(\zeta(n+2))}{n+2}s^{n}.$$ It has radius of convergence $2$ and converges for $|s| \leq 2$ except at $s = 2$. I'm ...
Jesse Elliott's user avatar
1 vote
0 answers
131 views

Looking for a citation for a result of Littlewood

I see that it is proven by Hardy in 1914 that there are an infinite number of zeros on the critical line. I also see that the Hardy and Littlewood conjectures appear in some papers they wrote ...
Jimmy Rankerman's user avatar
2 votes
0 answers
180 views

Multiple zeta values related to fractional calculus and an Appell polynomial sequence

There is an Appell sequence of polynomials $p_n(z)$ related to an infinitesimal generator for one rep of the fractional calculus that have coefficients involving the Riemann zeta function values at ...
Tom Copeland's user avatar
  • 10.5k
-1 votes
1 answer
512 views

Does $\int_{2}^{\infty} (\pi(x)-Li(x))x^{-s-1} \mathrm{d}x$ converge on the real axis for $s>1/2$? [closed]

Consider the prime zeta function, defined for $\Re(s)>1$, by the infinite series $$\sum_{p} p^{-s} = \sum_{m=1}^{\infty}\frac{\mu(m)}{m}\log \zeta(ms)$$ where $p$ denotes a prime, $\mu$ the Mobius ...
user avatar
3 votes
2 answers
1k views

On the Dirichlet series for $1/\zeta(s)$ for real $s$ and the zeros of zeta

For $\Re(s)>1$, it is well known that $$\frac{1}{\zeta(s)} = \sum_{n=1}^{\infty} \frac{\mu(n)}{n^s}$$ where $\mu$ denotes the Mobius function and $\zeta$ is the Riemann zeta function. I have heard ...
Rafik1's user avatar
  • 39
1 vote
0 answers
62 views

Example of an integer $n_0$ such that $1+\sum_{k=2}^{n_0} \zeta(k)^s=0$ has repeated roots

After I was studying the exercise Problem 4.20 from [1] I was inspired to ask about next problem, where $\zeta(k)$ denotes, for integers $k>1$, particular values of the Riemann zeta function. And $...
user142929's user avatar
4 votes
1 answer
925 views

On a possible equivalent of Riemann hypothesis

I've read in a Bombieri's paper on official problem statement of Riemann hypothesis for Clay Math institute's millennium problems, a statement and what I understood of it is the following : The ...
TPC's user avatar
  • 774
35 votes
7 answers
6k views

Heuristic argument for the Riemann Hypothesis

Is there a heuristic argument that supports the validity of the Riemann hypothesis or are we just relying on numerical evidence? Moreover, what is the strongest theorem that supports the validity of ...
Mustafa Said's user avatar
  • 3,699
2 votes
1 answer
2k views

Books on complex analysis for self learning that includes the Riemann zeta function?

I am searching for an introductory book in the field of complex analysis for self learning, that would contain the following: Analytic number theory : the connection between complex analysis and ...
user144435's user avatar
6 votes
2 answers
784 views

On some analytic property of the Riemann zeta function

Denote by $\zeta$ the Riemann zeta function. For $\Re(s)=\sigma>0$, it is well known that $$\sum_{n\leq x} n^{-s} = \zeta(s) + \frac{x^{1-s}}{1-s}+ O(x^{-\sigma}).$$ But do there exist infinitely ...
user avatar
0 votes
0 answers
126 views

On an integral involving $\zeta(1/2 + i\tau)$

Denote by $\zeta$ the Riemann zeta function. Define $$F_{y}(x)= \int_{-\infty}^{\infty} \frac{x^{iu}\zeta(1/2 + it + iu)}{u^2 + y^2} \mathrm{d}u.$$ For some fixed real number $t$, is there any $y&...
user avatar
6 votes
1 answer
383 views

Tight error terms for partial sums $\sum_{n\leq x} 1/n^s$

(a) Let $s>1$, $x>0$ be real. Then it is not hard to see that $$\sum_{n\leq x} \frac{1}{n^s} \leq \zeta(s) - \frac{1}{(s-1) x^{s-1}} + \frac{1}{2 x^s},$$ basically because $x\mapsto 1/x^s$ is ...
H A Helfgott's user avatar
  • 20.1k
5 votes
2 answers
850 views

Local phase statistics of the nontrivial Riemann zeros

(The question is inspired by Owen Maresh's post) The local phase of a nontrivial zero $s$ of the Riemann $\zeta$ is the argument of $\zeta'(s)$. Numerical results on the first 10000 zeros suggest ...
LeechLattice's user avatar
  • 9,501
-1 votes
1 answer
243 views

On a certain representation of the Riemann zeta function

Let $\zeta$ denote the Riemann zeta function. In this answer: https://mathoverflow.net/a/314066/133634, @Paul Garret considers the representation $$\frac{\zeta(s)}{s} = \int_1^\infty (\sum_{1 \le n \...
OneTwoOne's user avatar
  • 105
1 vote
1 answer
756 views

An integral involving the argument of the Gamma function and the Riemann Hypothesis

Evaluate $$I=\int_{0}^{\infty} \frac{t\arg \Gamma(\frac{1}{4}+\frac{it}{2})}{(\frac{1}{4}+t^2)^2}\mathrm{d}t$$ where $\Gamma(s)=\int_{0}^{\infty}e^{-x}x^{s-1}\mathrm{d}x.$ Note that $I$ converges ...
OneTwoOne's user avatar
  • 105
-2 votes
1 answer
270 views

A curious relationship betwen $|\zeta(\sigma+it)|$ and $|\zeta(1-\sigma - it)|$

By use of the Riemann functional equation, it can be shown (see corollary 10.5 of Montgomery-Vaughan) that $$|\zeta(\sigma + it)| \asymp |t|^{\sigma-1/2}|\zeta(1-\sigma - it)|$$. where $\zeta$ ...
sigma's user avatar
  • 35
3 votes
3 answers
273 views

Asymptotics for $\int_{0}^{T} \zeta(\sigma+ it) \mathrm{d}t$

Denote by $\zeta$ the Riemann zeta function. It is known that $$\int_{0}^{T} \zeta(1/2 + it) \mathrm{d}t = T + O(T^{1/2}).$$ But is a similar result for $\int_{0}^{T} \zeta(\sigma + it) \mathrm{d}...
sigma's user avatar
  • 35
3 votes
1 answer
528 views

Does the Riemann Xi function possess the universality property?

Here is the question.   Does the Riemann Xi function possess the universality property,  or something similar to Voronin's universality property?  Here is why the answer to this question is important. ...
Cristian Dumitrescu's user avatar
-3 votes
1 answer
245 views

An interesting phenomenon of the analytic continuation of Riemann zeta function [closed]

It is known that $$\Gamma (s) \zeta (s)=\int_0^{\infty} \frac{x^{s-1}}{e^x-1}dx$$ this function is valid only for $\Re{s}>1$. However, if we ignore this restriction, and integrate by using $$\frac{...
Milin's user avatar
  • 395
0 votes
4 answers
715 views

On the real part of the Riemann zeta function inside the critical strip

Denote by $\zeta$ the Riemann zeta function. Does $\Re\zeta(s)$ ever vanish for $\frac{1}{2}<\Re(s)\leq 1$ ?
Q_p's user avatar
  • 1,019
4 votes
2 answers
448 views

Is Riemann zeta function injective in some strips $a<\Re(s)<b$, where $0\leq a<b \leq 1$?

Or more generally, are L-functions injective in some strips $a<\Re(s)<b$, where $0\leq a<b \leq 1$?
Milin's user avatar
  • 395
52 votes
3 answers
6k views

Is the Riemann zeta function surjective?

Is the Riemann zeta function surjective or does it miss one value?
Shimrod's user avatar
  • 2,375
0 votes
0 answers
158 views

On reasonable asymptotic estimates for some integral involving the logarithm of the Riemann zeta function

Let $$I(T) = \int_{-T}^{T} \frac{\log|\zeta(\frac{1}{2} + it|)|}{\frac{1}{4}+t^2}\mathrm{d}t$$ where $\zeta$ denotes the Riemann zeta function. What are the reasonable asymptotic estimates for $I(T)...
user avatar
0 votes
2 answers
339 views

Error term in França-LeClair approximation of zeta zeros

The imaginary part of the $n$th critical zero of the Riemann zeta function with positive imaginary part (in increasing order) is asymptotically $$ t_n \sim 2\pi\frac{n}{\log n} $$ and has been ...
Charles's user avatar
  • 9,114
12 votes
2 answers
1k views

Has there been further work on Bender-Brody-Müller approach to RH?

Earlier this year (April 4, 2017), a seemingly tantalizing approach of the Riemann Hypothesis based on ideas dating back to Hilbert and Pólya by Bender, Brody and Müller was made publicly available. I ...
Sylvain JULIEN's user avatar
12 votes
2 answers
555 views

$\zeta^{(k)}(s) < 0$ for $s\in (0,1)$

A bit of plotting suggests that $\zeta^{(k)}(s) < 0$ for all $s\in (0,1)$ and all integers $k\geq 0$. (Or, what is the same: $\zeta^{(k)}(s)$ has no zeroes on $(0,1)$.) Is there a brief, clean ...
H A Helfgott's user avatar
  • 20.1k
0 votes
0 answers
194 views

Simple proof for Riemann/Hurwitz ζ functional equation

For the purpose of formalisation, I am looking for a simple proof of the function equation of the Riemann ζ function or the generalisation thereof, the Hurwitz's formula for the Hurwitz ζ function. ...
Manuel Eberl's user avatar
  • 1,241
0 votes
1 answer
169 views

Analytic extension of the Hurwitz ζ function

For the purpose of formalisation in a theorem prover, I am looking for a simple definition of the analytic extension of the Hurwitz ζ function $\zeta(s,q)$ valid for all $s\in\mathbb{C}\setminus\{1\}$ ...
Manuel Eberl's user avatar
  • 1,241
3 votes
1 answer
571 views

On the series $\sum_{\rho}x^{\rho}\Gamma(\rho)/\Gamma(\rho+k),\,0<k<1$

Let $x>1$ be a real number. For a work I need to find an uniform estimation of the series the series $$\sum_{\rho}x^{\rho}\frac{\Gamma\left(\rho\right)}{\Gamma\left(\rho+k\right)}\tag{1}$$ where $\...
User's user avatar
  • 219