Questions tagged [continuum-theory]

For questions from continuum theory. A continuum is a compact connected metric space (sometimes this term is used for a compact connected Hausdorff space).

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Planar compact connected set whose boundary has a finite length is arcwise connected

Let $K \subset \mathbb{R}^{2}$ be a compact connected set such that $\mathcal{H}^{1}(\partial K)<+\infty$. Is $K$ arcwise connected?
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3 votes
1 answer
113 views

The number of components of the preimage of a continuum for a polynomial

Given a polynomial f with degree d, we can define a dynamical system $(\mathbb{C}, f)$. If we have a proper continuum $N \subset \mathbb{C}$, it is known that the set $f^{-1}(N)$ has at most $d$ ...
Yee Neil's user avatar
4 votes
1 answer
224 views

Why is this continuum circle-like?

A continuum is a compact connected metrizable space. A continuum $X$ is called arc-like if for every $\varepsilon>0$ there is an open cover $U_1,\ldots,U_n$ of $X$ such that the diameter of $U_i$ ...
Alessandro Codenotti's user avatar
11 votes
1 answer
355 views

Is the Mandelbrot set Suslinian?

The Mandelbrot set is known to be (path-)connected and compact. A non-degenerate space with these properties is called a continuum. A continuum $X$ is Suslinian if every collection of non-degenerate ...
D.S. Lipham's user avatar
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3 votes
0 answers
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Does the pseudo-arc contain Erdős space?

The pseudo-arc is the unique hereditarily indecomposable chainable continuum. The Lelek fan is the unique compact, connected subset of the Cantor fan (the cone over the Cantor set) with a dense ...
D.S. Lipham's user avatar
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4 votes
0 answers
113 views

Find at least one square-boxed subcontinuum

Recall that a plane continuum is a closed, bounded, connected subset of the plane. It is non-degenerate if it contains at least two points. (We may sometimes just say "continuum" even if we ...
Mirko's user avatar
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2 votes
0 answers
156 views

Are there hereditarily square-boxed plane continua?

A plane continuum is a bounded, closed and connected subset of the plane. A bounding box $B$ for a plane continuum $C$ is a rectangle $B=[a,b]\times[c,d]$ (including sides and interior) such that $C$ ...
Mirko's user avatar
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14 votes
1 answer
555 views

How “disconnected” can a continuum be?

A continuum is a compact connected metrizable topological space. Given a cardinal $\kappa$, a topological space $X$ is called $\kappa$-connected if it is not possible to write $X$ as the disjoint ...
Alessandro Codenotti's user avatar
9 votes
0 answers
155 views

Irreducible subcontinuum without Zorn's lemma

In continuum theory we frequently use the fact that two points in a continuum are contained in an irreducible subcontinuum. A continuum $X$ is a compact connected metric space. A subcontinuum $K\...
D.S. Lipham's user avatar
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2 votes
0 answers
98 views

$n$-connected spaces (terminology)

A graph is called $n$-connected if it remains connected after removal $\le n$ vertices. Question. What is the name of an analogous property of topological spaces: a space that remains connected after ...
Taras Banakh's user avatar
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2 votes
1 answer
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For which continua $X$ does $X^\mathbb{N}$ have the fixed-point property?

A topological space $X$ has the fixed-point property if any continuous map $f : X \to X$ has a fixed point (i.e., an $x$ such that $f(x) = x$). It's well known that certain topological spaces, such as ...
James Hanson's user avatar
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5 votes
0 answers
232 views

Is a circle of circles necessarily a 2-manifold?

Let $X$ be a continuum (a compact connected metric space). Suppose that there is a collection of simple closed curves $\mathcal C$ which partitions $X$ into pairwise-disjoint, nowhere dense sets. ...
D.S. Lipham's user avatar
  • 3,055
11 votes
1 answer
330 views

Examples of continua that are contractible but are not locally connected at any point

A continuum is a compact, connected, metrizable space. What are examples of continua that are contractible but nowhere locally connected, meaning that no point has a neighbourhood basis consisting of ...
TopologicalDynamitard's user avatar
4 votes
0 answers
197 views

Is there an uncountable family of "hereditarily unembeddable" continua?

Define a family $\{C_i\}_{i\in I}$ of continua, that is compact connected metrizable spaces, to be hereditarily unembeddable (a name I just made up) iff for all $i\neq j$ no nontrivial subcontinuum of ...
Alessandro Codenotti's user avatar
2 votes
1 answer
241 views

Two maps into $[0,1]$ are equal at some point

In the paper below, there appears the following theorem: whose proof is left to the reader. It's not immediately obvious how I would prove this. How about the special case $X=Y=[0,1]$? It seems to be ...
D.S. Lipham's user avatar
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8 votes
1 answer
266 views

When does $C(X)$, $X$ a continuum, admit a continuous choice function?

Given a continuum $X$ (compact metrizable connected $X$) let $K(X)$ denote the hyperspace of nonempty compact subspaces of $X$ with the Vietoris topology and let $C(X)$ denote the (closed) subspace of ...
Alessandro Codenotti's user avatar
3 votes
0 answers
79 views

Isotopy Classes and Embeddability of Products in $\mathbb{R}^2$

On MSE I asked if the plane contains an uncountable collection of mutually disjoint copies of the Warsaw Circle; it seems to be false, and is probably already known but I'm not sure that anybody has ...
John Samples's user avatar
0 votes
1 answer
101 views

(Seeking Definition) What Does it Mean for a Space to have Rim-Type $\alpha$? Or the 'derivative' of a Countable Set?

I've encountered a definition in several papers, but literally none of them define the term. They all instead reference a book by Menger that has never been printed in English. The term is "rim-...
John Samples's user avatar
3 votes
1 answer
108 views

Shrinkable homogeneous compact and connected $T_2$-space

A topological space $(X,\tau)$ is said to be homogeneous if for any $x,y\in X$ there is a homeomorphism $\varphi:X\to X$ such that $\varphi(x) = y$. Moreover, we say that $(X,\tau)$ is shrinkable if ...
Dominic van der Zypen's user avatar
1 vote
1 answer
79 views

Isotopy Classes of Non-Connected Planar Sets

I was just looking through some of my old questions on StackExchange and noticed that this one went totally unresolved. I still think it'd be useful as a lemma for plane topology if it were true, and ...
John Samples's user avatar
10 votes
3 answers
543 views

Can an "almost injective'' function exist between compact connected metric spaces?

Let $\pi: X\to Y$ be a surjective continuous function between the compact, metric and connected spaces $X$, $Y$, and $Y_0 = \{y\in Y: \#\pi^{-1}(y)>1\}$. Suppose that: $Y_0$ is dense in $Y$, $Y\...
RB1995's user avatar
  • 265
10 votes
2 answers
249 views

Which compact metrizable spaces have continuous choice functions for non-empty closed sets?

Let $X$ be a compact metrizable space and let $\mathcal{K}_{ne}(X)$ be the collection of non-empty closed subsets of $X$ with the Vietoris topology (i.e. the topology induced by the Hausdorff metric ...
James Hanson's user avatar
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4 votes
0 answers
97 views

Is every locally compact connected homogeneous metric space a manifold cross a continuum?

Suppose that $(X,d)$ is a locally compact connected homogeneous metric space, where by homogeneous I mean that for any $x_0,x_1 \in X$ there exists an isometry $f:X\rightarrow X$ such that $f(x_0)=x_1$...
James Hanson's user avatar
  • 10.3k
7 votes
0 answers
96 views

Rough classification of Peano Curves

By Peano curve I mean a continuous map from the unit interval that fills the unit square in $\mathbb R^2$. In the paper: Shchepin, E. V.; Bauman, K. E., Minimal Peano curve, Proc. Steklov Inst. Math....
Ivan Meir's user avatar
  • 4,792
5 votes
0 answers
236 views

Polish transversals

A subset of $X$ an indecomposable continuum $Y$ is called a composant transversal if $X$ has exactly one point from each composant of $Y$. So a continuum has a composant transversal precisely when ...
D.S. Lipham's user avatar
  • 3,055
15 votes
1 answer
549 views

A continuum which is both Suslinean and non-Suslinean?

Continuum means compact connected metrizable with more than one point. A continuum is Suslinean if every collection of pairwise disjoint subcontinua is countable. There is an apparent contradiction ...
D.S. Lipham's user avatar
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13 votes
0 answers
252 views

Planar arc on a topologically embedded sphere or disk in $\mathbb{R}^3$

An arc is a set homeomorphic to the unit interval $[0,1]$; an arc in $\mathbb{R}^3$ is planar if it is contained in some plane. The following questions are motivated by Anton Petrunin's Disc bounded ...
Wlodek Kuperberg's user avatar
11 votes
1 answer
475 views

Do solenoids embed into Möbius strips?

I found a strange attractor which looks a lot like a solenoid. The attractor continuum is the closure of a continuous line which limits onto itself, and it is locally homeomorphic to Cantor set times ...
Forever Mozart's user avatar
2 votes
0 answers
71 views

Topological Shape Operator More Sensitive than Inverse Limits

This is a very general sort of question, and the use of the phrase 'shape operator' is a bit sloppy since there is already an established "shape theory." But what I have are topological spaces that ...
John Samples's user avatar
9 votes
0 answers
184 views

Is each Peano continuum a topological fractal?

Problem. Is each Peano continuum a topological fractal? A compact Hausdorff space $X$ is a topological fractal if $X=\bigcup_{i=1}^n f_i(X)$ for some continuous maps $f_1,\dots,f_n:X\to X$ such that ...
Lviv Scottish Book's user avatar
4 votes
1 answer
145 views

Does every cut-point space embed into the plane?

Let $X$ be a connected separable metrizable topological space. Call it a cut-point space if $X\setminus \{x\}$ is disconnected for every $x\in X$. Then does $X$ embed into the plane? My thoughts: (...
D.S. Lipham's user avatar
  • 3,055
4 votes
1 answer
110 views

Does each separator between points of a continuum contain an irreducible separator?

Definition. A closed subset $S$ of a topological space $X$ is called a separator between points $x,y\in X\setminus S$ if the points $x$ and $y$ belong to different connected components of $X\setminus ...
Taras Banakh's user avatar
  • 40.9k
13 votes
1 answer
548 views

Limit of homeomorphisms from square to square

Let $\square=[0,1]\times[0,1]$ be the unit square and $f\colon\square\to \square$ is a continuous map that fixes the points on the boundary. Assume $f$ is a limit of homeomorphisms $\square\to \...
Anton Petrunin's user avatar
4 votes
0 answers
209 views

Is each metric continuum $\ell_p$-chain connected?

This problem was motivated by the MO problems: "Running most of the time in a connected set", "Is every metric continuum almost path connected?" and "Are $\varepsilon$-connected components dense?". ...
Taras Banakh's user avatar
  • 40.9k
6 votes
1 answer
166 views

Are $\varepsilon$-connected components dense?

Let $X$ be a connected compact metric space. Given a positive $\varepsilon$ and two points $x,y\in X$ we write $x\sim_\varepsilon y$ if there exists a sequence $C_1,\dots,C_n$ of connected subsets of ...
Taras Banakh's user avatar
  • 40.9k
10 votes
1 answer
513 views

Is every metric continuum almost path-connected?

The question was motivated by this question of Anton Petrunin. By a metric continuum we understand a connected compact metric space. Let $p$ be a positive real number. A metric continuum $X$ is ...
Taras Banakh's user avatar
  • 40.9k
29 votes
1 answer
803 views

Running most of the time in a connected set

Let $P$ be a compact connected set in the plane and $x,y\in P$. Is it always possible to connect $x$ to $y$ by a path $\gamma$ such that the length of $\gamma\backslash P$ is arbitrary small? ...
Anton Petrunin's user avatar
7 votes
1 answer
505 views

Example of a non-locally connected continuum

Continuum $=$ compact connected metric space. Let $X$ be a continuum. $X$ is indecomposable means that every proper subcontinuum of $X$ is nowhere dense in $X$. It is easy to see that if $X$ is ...
Forever Mozart's user avatar
3 votes
2 answers
308 views

A minimal continuum

A continuum $X$ is called minimal if it is not a single point and is homeomorphic to all its nontrivial subcontinua. Here a trivial continuum is a single point. What is an example of a minimal ...
Ali Taghavi's user avatar
26 votes
1 answer
823 views

Disc bounded by a plane curve

Let $\Sigma$ be a sphere topologically embedded into $\mathbb{R}^3$. Is it always possible to find a disc $\Delta\subset\Sigma$ which is bounded by a plane curve? It is easy to find an open disc ...
Anton Petrunin's user avatar