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Probability of satisfying the congruent mod equation

I'm wondering about the probability of picking three different numbers $x,y,z$ out of the set $[50]=\left\{ 1,2,3,...,50\right\}$ satisfying the equation: $$xyz\equiv \gcd(x,y,z)\mod 7$$ I started out ...
Marek Kryspin's user avatar
1 vote
0 answers
154 views

An explicit solution to the congruence $x^2\equiv 14(\frac 3p)-(\frac p3)-12\pmod {p}$?

Let $p>3$ be a prime, and let $(\frac{\cdot}p)$ be the Legendre symbol. Then $$14\left(\frac 3p\right)-\left(\frac p3\right)-12=\begin{cases}1&\text{if}\ p\equiv1\pmod{12}, \\-25&\text{if}\ ...
Zhi-Wei Sun's user avatar
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18 votes
0 answers
755 views

Two curious series for $1/\pi$

On Jan. 18, 2012 I conjectured that for any prime $p>3$ we have $$R_p^2\equiv\frac1{10}\left(512\left(\frac{10}p\right)-27\left(\frac{-15}p\right)-475\right)\pmod p,$$ where $(\frac{\cdot}p)$ ...
Zhi-Wei Sun's user avatar
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7 votes
0 answers
183 views

Some conjectural congruences involving Domb numbers

The Domb numbers are given by $$D_n=\sum_{k=0}^n\binom{n}{k}^2\binom{2k}k\binom{2(n-k)}{n-k}\ \ \ (n=0,1,2,\ldots).$$ Such numbers have combinatorial interpretation, see, e.g., http://oeis.org/A002895....
Zhi-Wei Sun's user avatar
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6 votes
0 answers
192 views

A conjecture involving $P_n=\prod_{k=1}^np_k$

For each positive integer $n$ let $P_n=\prod_{k=1}^n p_k$, where $p_k$ is the $k$th prime. Question. Is my following conjecture true? Conjecture. For any integer $n>1$, there are $k,m\in\{1,\...
Zhi-Wei Sun's user avatar
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2 votes
0 answers
152 views

On the smallest solution of a linear congruence

I have the following question. First, consider the following congruence for primes $p\geq 5$: $24x\equiv -1\;(\mbox{mod}\;p)$. The smallest $x$, that is, $1\leq x\leq p-1$ for which the above ...
Jimoni's user avatar
  • 21
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0 answers
180 views

When is $\phi(a^n+b^n+c^n)=0\mod n$?

A corollary Zsigmondy's Theorem leads to the following congruence (one can look to $(24)$),$\phi(a^n+b^n)=0\mod n$ whenever $a, b$ are coprime and $n \neq 2$ and $(a,b)\neq(1,1)$. (Here $\phi$ is the ...
user avatar
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90 views

Set of primes $p_{1}\equiv 3 \bmod p_{2}$ such that $\phi(2^{\frac{{p_1}-3}{p_2}}-1)\equiv 0 \bmod p_1$ with $p_1,p_2\equiv 3\bmod 4$?

let $p_1$ and $p_2$ be positive primes such that $p_1,p_2 \equiv 3\bmod 4$ and $\phi$ is the Euler totiont function , I want to find the Set of primes $p_{1}\equiv 3 \bmod p_{2}$ such that $\phi(2^...
zeraoulia rafik's user avatar
0 votes
1 answer
243 views

Solve congruence equation where unknown variable is in both sides of congruent operator

I am trying to solve the following equation: $(a*n + c) \mod (b-n) \equiv 0$ and $n$ must be the lowest value in $[0, b-1]$ for example $a=17$, $c=-59$ and $b=128$, the solution is $n=55$ $n=b-1$ ...
Jose Maria's user avatar
4 votes
0 answers
142 views

Is it true that $|\{k^{k+1}+(k+1)^k\pmod p:\ k=0,\ldots,p-1\}|=(1-e^{-1})p+O(\sqrt{p})\ ?$

For each prime $p$, let us define $$w_p:=|\{k^{k+1}+(k+1)^k\pmod p:\ k=0,\ldots,p-1\}|,$$ where $a\pmod p$ denotes the residue class $a+p\mathbb Z$. Based on my computation, I conjecture that $$w_p=...
Zhi-Wei Sun's user avatar
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7 votes
1 answer
342 views

Corollaries of the halo conjecture that do not involve the eigencurve

In the theory of p-adic modular forms there is a certain construction called the Coleman-Mazur eigencurve. The spectral halo conjecture roughly states that if you remove a closed subdisc of the weight ...
user avatar
3 votes
0 answers
183 views

Congruences of modular forms modulo other modular forms

Congruences between modular forms are certainly a big topic in number theory, maybe with $$E_{p-1}\equiv 1 \mod p \qquad \text{for a prime }p\geq 5$$ as the easiest example. Sometimes, $p$ might be ...
Lennart Meier's user avatar
6 votes
0 answers
217 views

Two conjectural congruences for Franel numbers

Recall that the Franel numbers are given by $$f_n:=\sum_{k=0}^n \binom{n}{k}^3\ \ \ (n=0,1,\ldots).$$ Question. How to prove my following conjecture? Conjecture. For each odd prime $p$, we have $$\...
Zhi-Wei Sun's user avatar
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7 votes
0 answers
213 views

Does Morley's congruence characterize primes greater than $3$?

In 1895 Morley showed that $$\binom{p-1}{(p-1)/2}\equiv(-1)^{\frac{p-1}2}4^{p-1}\pmod{p^3}$$ for any prime $p>3$. In 2009, I formulated the following conjecture concerning the converse of Morley's ...
Zhi-Wei Sun's user avatar
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2 votes
0 answers
67 views

Is it possible to deduce statements for odd perfect numbers from the convolution sums involving divisor functions or other arithmetic functions?

Dividing and using some identities of [1] I've deduced the following facts, see also the remarks below. After these introductory paragraphs, to motivate our question, I am asking if we can deduce some ...
user142929's user avatar
1 vote
1 answer
218 views

Chinese Remainder Theorem for Remainder Intervals

Given $n$ natural numbers $m_1,\dots,m_n$ and $n$ remainder intervals $[a_1,b_1],\dots,[a_n,b_n]$ holding $a_i < b_i$ for all $i\leq n$ the task is to search for the smallest natural number $x$ ...
MaxPower's user avatar
3 votes
0 answers
299 views

An attempt to get a variant of Agoh–Giuga conjecture

The idea of this post is an attempt to explore a variant of the so-called Agoh–Giuga conjecture. In past days, and today, I tried to think about variants of this conjecture exploring congruences about ...
user142929's user avatar
7 votes
0 answers
217 views

How to prove the identity $\sum_{k=1}^\infty\frac{3H_{k-1}^2+4H_{k-1}/k}{k^2\binom{2k}k}=\frac{\pi^4}{360}$?

For each $n=0,1,2,\ldots$, the harmonic number $H_n$ is given by $$H_n:=\sum_{0<k\le n}\frac1k.$$ In 2016 I conjectured that $$\sum_{k=1}^\infty\frac{3H_{k-1}^2+4H_{k-1}/k}{k^2\binom{2k}k}=\frac{...
Zhi-Wei Sun's user avatar
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2 votes
0 answers
100 views

$\varphi(m+n)\mid n$ for some positive integer $n$

Let $\varphi$ be Euler's totient function. If $p$ is a prime, then $\varphi(1+n)=n$ for $n=p-1$. Question. Is it true that for each integer $m>1$ there is a positive integer $n\le m^2-m$ such that ...
Zhi-Wei Sun's user avatar
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1 vote
1 answer
257 views

A divisibility problem involving Catalan numbers

The Catalan numbers in combinatorics are given by $$C_n=\frac1{n+1}\binom{2n}n=\binom{2n}n-\binom{2n}{n+1}\ \ (n=0,1,2,\ldots).$$ In 2014 I formulated the following conjecture. Conjecture. For each $...
Zhi-Wei Sun's user avatar
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5 votes
0 answers
272 views

Is an algebraic number satisfying certain super-congruences a root of unity?

Let $K|\mathbb{Q}$ be a number field, $D$ its discriminant and $\mathcal{O}$ the ring of integers in $K$. Let $x\in K$ (or maybe $\in \mathcal{O}[\frac 1D]$) such that for all primes $p$ in $\mathbb{Q}...
LFM's user avatar
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48 views

Efficient scissors congruence between efficiently describable convex polytopes and simplex?

Is there a convex polytope in $\mathbb R^n$ describable by only $O(poly(\log n))$ half-plane inequalities with positive volume (so at least $n+1$ vertices) such that the standard simplex has a ...
VS.'s user avatar
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5 votes
1 answer
329 views

Reversing the CRT: Is $5$ tough?

Given odd primes $p\ne q$, by the CRT we can find an integer $x$ such that $x\equiv 2^{p-1}\pmod q$ and $x\equiv 2^{q-1}\pmod p$. Can this procedure be reversed? For which integers $x$ there exist ...
W-t-P's user avatar
  • 550
1 vote
0 answers
70 views

Wieferich primes and arithmetic prgressions

Let $p$ be an odd prime number. Let $K$ be a number field with Galois group $G$ and $H$ be a subgroup of $G$ stable under conjugation. Then the Cebotarev density theorem gives that $$\mathcal{L}=\{\...
Zakariae.B's user avatar
1 vote
1 answer
111 views

Density of a set of numbers dividing a fixed number with polynomial exponent

Fix a positive integer $a>1$ and let $f\in\mathbb{Z}[x]$ be a polynomial with positive leading coefficient. We define a set $S$ of positive integers, $$ S=\{n\in\mathbb{Z}^+:n\mid a^{f(n)}-1\}. $$ ...
hookah's user avatar
  • 1,096
2 votes
1 answer
215 views

Number of odd elements in a vanishing sum of binomial coefficients

Let $n$ be a positive integer, $k$ a non-negative integer and $N(n,k)$ be the number of odd elements among the numbers $\binom{n+k}{j}\binom{-n-k}{n-j}$, $0\le{j}\le{n}$, which sum to $0.$ It seems ...
Johann Cigler's user avatar
12 votes
4 answers
3k views

Prove that $\sum_{n = 1}^{p - 1} n^{p - 1} \equiv (p - 1)! + p \pmod {p^2}$ with $p$ being an odd prime

First, I have to admit that I have already asked the same question on MSE several days ago. If I am bending any rules, I apologize for that and moderator can delete or close this question without ...
Oldboy's user avatar
  • 223
9 votes
1 answer
357 views

On the permanent $\text{per}[i^{j-1}]_{1\le i,j\le p-1}$ modulo $p^2$

Let $p$ be an odd prime. It is well-known that $$\det[i^{j-1}]_{1\le i,j\le p-1}=\prod_{1\le i<j\le p-1}(j-i)\not\equiv0\pmod p.$$ I'm curious about the behavior of the permanent $\text{per}[i^{j-...
Zhi-Wei Sun's user avatar
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3 votes
2 answers
538 views

On the sum $\sum_{\pi\in S_{n}}e^{2\pi i\sum_{k=1}^{n}k\pi(k)/n}$

Motivated by Question 316142 of mine, I consider the new sum $$S(n):=\sum_{\pi\in S_{n}}e^{2\pi i\sum_{k=1}^{n}k\pi(k)/n}$$ for any positive integer $n$, where $S_n$ is the symmetric group of all the ...
Zhi-Wei Sun's user avatar
  • 15.6k
4 votes
2 answers
553 views

Non-torsion part of the abelianisation of congruence subgroups

I've posted this question on math.stackexchange, but haven't gotten any responses so I'm trying here instead. Let $A = F_q[T]$ be the ring of polynomials in one variable with coefficients in a finite ...
Liam Baker's user avatar
2 votes
1 answer
199 views

On the function $f_m(p)=\left|\left\{1\leqslant k<\frac p2:\ \left\{\frac{k^m}p\right\}>\frac12\right\}\right|$

Let $m>1$ be an integer and let $p$ be an odd prime. Can we say something nontrivial about $$f_m(p):=\left|\left\{1\leqslant k<\frac p2:\ \left\{\frac{k^m}p\right\}>\frac12\right\}\right|$$ (...
Zhi-Wei Sun's user avatar
  • 15.6k
7 votes
1 answer
290 views

On $\prod^{(p-1)/2}_{i,j=1\atop p\nmid 2i+j}(2i+j)$ and $\prod^{(p-1)/2}_{i,j=1\atop p\nmid 2i-j}(2i-j)$ modulo a prime $p>3$

QUESTION: Is my following conjecture true? Conjecture. Let $p>3$ be a prime and let $h(-p)$ be the class number of the imaginary quadratic field $\mathbb Q(\sqrt{-p})$. Then $$\frac{p-1}2!!\prod^{...
Zhi-Wei Sun's user avatar
  • 15.6k
4 votes
1 answer
204 views

On the solvability of the congruence $p^m\equiv m\pmod{n}$

Let $n,p\geq 1$ be integers, and assume that $p$ is a prime. Question. Does there always exist an integer $m\geq 1$ such that $p^m\equiv m\pmod{n}$?
Samvel Safaryan's user avatar
4 votes
0 answers
407 views

Congruence for the product of quadratic residues + the product of quadratic non-residues

My question has been here on MSE for a long time, but it has not received a full answer. I bring it here: Find a prime $p$ such that $p \equiv 1 \bmod 4$ and such that the product in the range $[...
René Gy's user avatar
  • 505
1 vote
0 answers
84 views

Equivalent condition for Poincare polynomial

I have found a statement in the introduction of the paper 'Sets of Recurrence and Generalized Polynomials' by Bergelson & Haland, which is Result: Given a polynomial $p \in \mathbb{R}[x]$ such ...
Surajit's user avatar
  • 73
7 votes
1 answer
421 views

On $\varphi(m)\varphi(n)\equiv0\pmod{m+n}$

Euler's totient function $\varphi$ is multiplicative, and it plays important roles in number theory. QUESTION: Is it true that for each integer $m>6$ we have $\varphi(m)\varphi(n)\equiv0\pmod{m+n}$...
Zhi-Wei Sun's user avatar
  • 15.6k
4 votes
0 answers
344 views

Number of power residues modulo prime power [closed]

Suppose you have a prime $p$ (not necessarily odd) and you have $\tau$ defined by $p^\tau \| k$ for some integer $k$. Then you define \begin{equation} y = \begin{cases} \tau + 1 &, p > 2 \...
Annemie's user avatar
  • 71
8 votes
1 answer
407 views

Cardinality of the image of a polynomial modulo $p^n$

Let $f \in \mathbb{Z}[x]$ be a nonconstant polynomial and let $p$ be a prime number. I'm looking for results about $$N_f(p^k) := \#\{(f(n) \bmod p^k) : n \in \mathbb{Z}\},$$ as $k \to +\infty$, where $...
OhhiMark's user avatar
1 vote
0 answers
254 views

Presentation of amalgamated sum as a quotient of the direct sum

I am currently reading Arthur Ogus' "Lectures on Logarithmic Algebraic Geometry" (https://math.berkeley.edu/~ogus/preprints/log_book/logbook.pdf). I'm trying to understand why the amalgamated sum of ...
gmp's user avatar
  • 65
7 votes
1 answer
185 views

2-adic valuation of $L(0,\chi)$ for a Dirichlet character

Let $\chi : (\mathbb Z/f\mathbb Z)^\times \to K = \mathbb Q(\mu_{\phi(f)})$ be a primitive Dirichlet character. Assume moreover that it is not quadratic, that is, $\chi^2$ is not the trivial character....
Asvin's user avatar
  • 7,736
1 vote
3 answers
342 views

Finding a solution for this system of two diophantine equations (depending on a parameter) [closed]

I propose the following problem (Maybe it has a trivial solution): Let $n$ be a positive integer such that $$n\equiv1 \pmod 4.$$ Then the problem is to find a rational $x$ as a function of $n$ such ...
Safwane's user avatar
  • 1,197
5 votes
4 answers
374 views

When does the following congruence identity hold?

Let $m$,$l$ be coprime integers where $m,l\geq 2$. For any integer $a$ and positive base $b \ (b\geq 2)$, let $ [a]_b $ denote the element of $\{0,\ldots, b-1\}$ that satisfies the equivalence $[a]...
Andrey Rukhin's user avatar
9 votes
2 answers
276 views

For which values of $k$ is it known that there are infinitely many $n$, such that $2^{n+k}\equiv 1\pmod{n}$?

I know that there are no solutions to $2^n\equiv 1\pmod{n}$ for $n>1$ and I can prove that there are infinitely many $n$ such that $2^{n+1}\equiv1\pmod{n}$. My question is: Do we know other ...
Konstantinos Gaitanas's user avatar
13 votes
1 answer
3k views

A good reference to the general Chinese Remainder Theorem

I am writing a paper on the topology of the Golomb space and need a good (standard) reference to the following General Chinese Remainder Theorem. For integer numbers $a_1,\dots,a_n$ and positive ...
Taras Banakh's user avatar
  • 41.8k
2 votes
0 answers
110 views

"Close" roots of polynomials and Pillai property

A sequence of integers $a(n)_{n \geq 0}$ has the Pillai property if there exists an integer $G \geq 2$ such that for all integers $k \geq G$ there exists an integer $n \geq 0$ such that none of the $k$...
MacNamara's user avatar
35 votes
2 answers
2k views

Is the sum of digits of $3^{1000}$ divisible by $7$?

Is the sum of digits of $3^{1000}$ a multiple of $7$? The sum of the digits of $3^{1000}$ can be computed using a computer. It is equal to $2142$, so the answer is positive. Is there a short proof ...
Lezraf's user avatar
  • 453
11 votes
2 answers
369 views

Harmonic congruence

There are a number of interesting congruences for harmonic sums, not the least of which is Wolstenholme's theorem: $H_{p-1}:=\sum_{j=1}^{p-1}\frac1j\equiv 0\mod p^2$. It appears that $\sum_{j=1}^{p-1}...
Lewi_Sol's user avatar
  • 309
4 votes
1 answer
321 views

Matrix congruence

Let $A$ be an $n\times n$ matrix with integer entries and let $d_1,...,d_n|q$ all be given natural numbers (I am happy to assume that $q$ is a prime power). How many solutions $x_1,...,x_n$ modulo $q$...
tomos's user avatar
  • 1,381
3 votes
1 answer
314 views

Probability in $GL_2(\mathbb{Z}/p^{r}\mathbb{Z})$

My question may be not interesting or easy to answer ! but I am really not familiar with proba. Let $p$ be an odd prime number. and let $r\geq1$ an integer. choose an element $A\in\mathrm{GL}_2(\...
Zakariae.B's user avatar
1 vote
1 answer
161 views

What is the general formula for $\# \{ 1 \leq a \leq q-2,| (a,q)=1, (a+2,q)=1 \}$

Let $q=\prod P_i^{k_i}.$ I have learned here that $\# \{ 1 \leq a \leq q-1| (a,q)=1, (a+1,q)=1 \}= F(q)=\prod (p_i-2)pi^{k_i-1} = q\prod (1-2/p_i)$ Here was the idea behind it : For any $p_i$, there ...
usere5225321's user avatar