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congruences of level 1 and level p modular forms

I've been carrying out some experiments on the computer and I noticed the following congruence phenomenon: fixing a prime $p$, it seems that any modular form over $SL_2(\mathbb{Z})$ and of weight $k \...
Nadim Rustom's user avatar
4 votes
0 answers
179 views

Congruences between hypergeometric functions coming from modular forms

Consider the formal power series $${}_2F_1(1/12,5/12;1;z)^{24}-{}_2F_1(1/12,7/12;1;z)^{24}=-z/3-z^2/2-(320293/559872)z^3-\cdots$$ It follows from a theorem on modular forms that for $p\ge5$ the ...
Henri Cohen's user avatar
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3 votes
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63 views

Congruences regarding $4n$-dimensional lattices

A sequence of integers $(a_n)_{n\geq 1}$ satisfies Gauss congruence if $$\sum_{d\mid n}\mu(d)a_{n/d}\equiv 0\pmod{n}$$ for every $n\geq 1$. Such sequences are also called Dold sequences, Newton ...
fern-gossow's user avatar
3 votes
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When are modular forms linearly independent modulo $p$?

Let $M_2(\Gamma_0(N))$ be the space of weight $2$ modular forms for $\Gamma_0(N)$ and let $f_1, \dots, f_r$ be a basis of normalized eigenforms for $M_2(\Gamma_0(N))$. Given a rational prime $p$, I'll ...
Adithya Chakravarthy's user avatar
3 votes
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183 views

Congruences of modular forms modulo other modular forms

Congruences between modular forms are certainly a big topic in number theory, maybe with $$E_{p-1}\equiv 1 \mod p \qquad \text{for a prime }p\geq 5$$ as the easiest example. Sometimes, $p$ might be ...
Lennart Meier's user avatar