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Closed form for $\sum\limits_{k=0}^{n} [\operatorname{wt}(k) = m]$ where $\operatorname{wt}(n)$ is the binary weight of $n$

Let $\operatorname{wt}(n)$ be A000120 (i.e., number of $1$'s in binary expansion of $n$). Let $a(n,m)$ be the family of integer sequences such that $$ a(n,m) = \sum\limits_{k=0}^{n} [\operatorname{wt}(...
Notamathematician's user avatar
0 votes
0 answers
85 views

How to prove the following equation (involving multiple binomial coefficients sum)?

I encountered the equation below, encountered a problem that has been bothering me for a long time Does anyone have an idea how to prove it? I would be extremely grateful to you if you come up with an ...
tongjun's user avatar
  • 41
0 votes
1 answer
168 views

Partial sums of binomial coefficients and related family of polynomials

Let $a(n)$ be A302117. Here $$ a(n) = 4(n-1)a(n-1) - \frac{1}{3}\prod\limits_{k=0}^{n-1}(2k-3), \\ a(0) = 0. $$ Let $$ T(n,k) = \sum\limits_{i=0}^{k} \binom{n}{i}. $$ Let $P_n(z)$ be the family of ...
Notamathematician's user avatar
0 votes
2 answers
115 views

Upper bounds on quotients of binomial coefficients

Let $\gamma>1$ be a real number and let $n\in \mathbb{N}$. Define $f\colon\mathbb{N}\to[0,1]$ $$ f(n_0) = \frac{\binom{n-n_0}{m}}{\binom{n}{m}}, $$ where $$ m = \Big\lfloor{\frac{n}{\lceil\gamma ...
xabialgebra's user avatar
0 votes
1 answer
98 views

Only special permutations result in a constant expression when permuting coefficients in a sum involving binomials?

Fix $n\geq 1$ and let $p_k(x) := x^k(x-1)^{n-k}$. Suppose $\pi$ is a permutation on $\{0,1,\dotsc,n\}$, such that $$ \sum_{k=0}^n (-1)^k \binom{n}{k} p_{\pi(k)}(x) \text{ is a constant}. $$ Must it be ...
Per Alexandersson's user avatar
5 votes
0 answers
183 views

On the polynomials $\sum_{k=0}^n\binom{n+k}k^m q^k$

A sequence of polynomials $$P_0(q),\ P_1(q),\ P_2(q),\ \ldots$$ with real coefficients is called $q$-log-convex if for each $n=1,2,3,\ldots$ every coefficient of the polynomial $P_{n+1}(q)P_{n-1}(q)-...
Zhi-Wei Sun's user avatar
  • 15.6k
0 votes
1 answer
170 views

Summation of binomial coefficients with alternating signs

For a fixed $\alpha > 1$ and integer $n$, I want to provide some bounds or scaling results for the following summations $$S_1(n,\alpha) = \sum_{k = 1}^{n} {n \choose k} (-1)^{k + 1} k / (\alpha k + ...
yfful's user avatar
  • 25
6 votes
0 answers
751 views

For all $n\in \mathbb{N}$, How to find $\min\{ m+k\}$ such that $ \binom{m}{k}=n$?

I asked this question on MSE here. Most numbers in pascal triangle appear only once (excluding the duplicates in the same row of the Pascal's triangle) but certain numbers appear multiple times. ...
pie's user avatar
  • 541
1 vote
1 answer
141 views

Asymptotics on sum of product of binomial coefficients

I'm interested in the behavior of the summation $$S(a,b)=\sum_{k\ge 0}\binom{a-k}{k}\binom{b}{k}.$$ For a fixed $\delta>0$, I would like asymptotic bounds on $S(a,\delta a)$. With $\delta=1$, this ...
TheBestMagician's user avatar
4 votes
0 answers
205 views

Who first considered "Pascal Triangle"? [closed]

Arnold was used saying in his talks, "Pascal’s triangle, so called, because it was by Chinese discovered"! How much is he right?
Al-Amrani's user avatar
1 vote
0 answers
73 views

Alternating sum of integer coefficients of the triangles related to Eulerian numbers and binomial transforms

Let $W(n, k, m)$ be an integer coefficients defined for $n > 0, 1 \leqslant k \leqslant n, m > 0$ with $W(n,k,m)=0$ for $n \leqslant 0$ or $k \leqslant 0$ such that $$ W(n, k, m) = (k+m-1)W(n-1,...
Notamathematician's user avatar
0 votes
1 answer
157 views

Generalized Multinomial Formula

During a computation, the following came up, and I was wondering if there is a generalized multinomial formula which can handle expressions of the following form: Let $n\in \mathbb{N}_+$ and $w_1,\...
ABIM's user avatar
  • 5,405
7 votes
1 answer
527 views

Suitable closed form for the A079501

Let $a(n)$ be A079501 (i.e., number of compositions of the integer $n$ with strictly smallest part in the first position). The sequence begins with $$ 1, 1, 2, 2, 4, 5, 8, 12, 19, 28, 45, 70, 110, ...
Notamathematician's user avatar
3 votes
1 answer
829 views

binomial coefficients are integers because numerator and denominator form pairs?

I've heard of a claim that when calculating the binomial formula with integer input: $\mathrm{Bin}(n,k):=\prod^k_{i=1}\frac{n+1-i}{i}\in \mathbb{N}\ (\forall n,k\in\mathbb N)$ each denominator divides ...
user11566470's user avatar
11 votes
1 answer
681 views

Solve $\binom{n}{k}=m$ for $(n,k)$

For an integer $m>0$, put $X(m)=\{(n,k):4\leq 2k\leq n \text{ and } \binom{n}{k}=m\}$. Is there an efficient method to calculate $X(m)$? Is there a uniform upper bound for $|X(m)|$? By ...
Neil Strickland's user avatar
13 votes
1 answer
468 views

Four new series for $\pi$ and related identities involving harmonic numbers

Recently, I discovered the following four new (conjectural) series for $\pi$: \begin{align}\sum_{k=1}^\infty\frac{(5k^2-4k+1)8^k\binom{3k}k}{k(3k-1)(3k-2)\binom{2k}k\binom{4k}{2k}}&=\frac{3\pi}2,\...
Zhi-Wei Sun's user avatar
  • 15.6k
8 votes
1 answer
319 views

Why does this combinatorial sum vanish?

We define the coefficients $c_{k,k-i}$ of ${n \choose k}$ by the following easy expansion: \begin{align*} & {n \choose k} = \frac{1}{k!} n(n-1) \dots (n-k+1) = \frac{1}{k!} \prod\limits_{t=...
Ben Deitmar's user avatar
  • 1,295
1 vote
1 answer
336 views

sum of binomial coefficient approximation by geometric series

I follow a subject almost like this link: Sum of 'the first k' binomial coefficients for fixed $N$ $$ f(N,k) = \sum^{k}_{i=0} \binom{N}{i} . $$ Michael Lugo suggest a way with geometric series ...
tess35's user avatar
  • 21
2 votes
2 answers
238 views

Sign-reversing involution for $q$-binomial coefficient at $q=-1$

Consider the q-binomial coefficient $\binom{n}{k}_q$. One combinatorial way to define it is as follows. Let $W_{n,k}$ be the set of binary words of length $n$ with $(n-k)$ 0's and $k$ 1's. An ...
Sam Hopkins's user avatar
  • 24.2k
8 votes
3 answers
921 views

Alternating Sum Involving Catalan Numbers

I was wondering if anyone knew how to obtain a simpler closed form of the following sum(or had any other insights regarding it): $$\sum_{k=0}^n (-1)^k{n \choose k} C_{2n-2-k} $$ Here $C_n = \frac{1}{n+...
interstice's user avatar
0 votes
0 answers
92 views

Solving a Catalan-like recursion of polynomials, related to the KdV energies

I am working on a PDE problem. The goal is to connect the higher order energies of the Gross-Pitaevskii equation to those of the Korteweg-de-Vries equation. As these higher order energies are ...
Robert Wegner's user avatar
0 votes
0 answers
244 views

Looking for a combinatorial proof of an identity

I've come up with an interesting combinatorial identity (thanks to P. Belmans who precomputed the numbers and pointed out to me that they correspond to OEIS A002697): $$ \sum_{i=0}^{n-1}\binom{n+1-i}{...
Anton Fonarev's user avatar
0 votes
0 answers
174 views

3D generalization of Gaussian q-binomial coefficient

It is known that the coefficient of $q^t$ in Gaussian binomial coefficient $\binom{m+n}m_q$ equals the number of permutations of the multiset $\{0^m, 1^n\}$ with $t$ inversions. Is there a closed ...
Max Alekseyev's user avatar
3 votes
1 answer
392 views

A combinatorial identity involving binomial coefficients

When I was reading an article by CHUN-GANG JI (A SIMPLE PROOF OF A CURIOUS CONGRUENCE BY ZHAO), he mentioned in the acknowledgement the following identity $$\sum_{i+j+k=p,\text{ } i,j,k\gt 0}{p\choose ...
wkmath's user avatar
  • 53
0 votes
0 answers
302 views

An alternating sum involving a product of binomial coefficients

I encountered the sum below, where $c_{1}$, $c_{2}$, $c_{3}$, $c_{4}$ and $d$ are some given positive constants. Does anyone have an idea how to simplify it? $$ \sum\limits_{k=1}^{d} \frac{(-1)^{k-1}k}...
sdd's user avatar
  • 109
4 votes
0 answers
134 views

Irreducibility of polynomials associated to binomial coefficients

Let $n \geq 2$. Let $M_n$ be the $(n+1) \times (n+1)$ matrix with entries $\binom{l}{k}$ for $0 \leq l,k \leq n$ and $U_n=M_n + M_n^T$ and let $f_n(x)$ denote the characteristic polynomial of $U_n$. ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
70 views

Integer coefficients such that $T(n,k)=R(n,k)-R(n,k-1)$

Let $a(n)$ be A000085, i.e., the number of self-inverse permutations on $n$ letters, also known as involutions; number of standard Young tableaux with $n$ cells. Here $$a(n) = a(n-1) + (n-1)a(n-2), a(...
Notamathematician's user avatar
7 votes
1 answer
286 views

A reference for a sum found in Gould's Combinatorial Identities book

On p. 49 in Gould's book Combinatorial Identities, the author states that the sum $$\sum_{k=0}^{n-1}(-1)^k\binom{n}{k}\binom{2n}{2k}^{-1}$$ "... arises naturally in a statistical problem; it ...
Sela Fried's user avatar
1 vote
0 answers
81 views

Maybe with the multinomial theorem

I'm looking for some idea to prove \begin{equation*} \sum_{\substack{ \left( s_{0},\ldots ,s_{r-1}\right) \in \left\{ \mathbb{N}% \cup \left\{ 0\right\} \right\} ^{r}, \\ \sum_{a=0}^{r-1}\left( a+1\...
IVG's user avatar
  • 11
4 votes
2 answers
268 views

(Conceptual) proof and/or interpretation of a $q$-binomial identity

There is a $q$-binomial identity that I encountered in one paper I am reading (https://arxiv.org/abs/1910.06193) which probably admits a very simple proof that I do not see: for two nonnegative ...
Vladimir Dotsenko's user avatar
1 vote
0 answers
78 views

Closed-form expression for combinatorial summation with a quadratic exponent?

In a current project, I have encountered sums of the form $$A_N(\theta_1,\theta_2) = \sum_{x=0}^{N}{N \choose x} \theta_1^x \theta_2^{x^2}$$ for $\theta_1$ and $\theta_2$ positive reals. My current ...
MeanLearner's user avatar
1 vote
1 answer
318 views

How to calculate this limit (if exist)?

I have just asked the calculation of the following summation see here $$S(a,b,m,n_1,n_2)=\sum_{k=0}^m a^k b^{m-k} {n_1\choose k} {n_2\choose m-k}, $$ which is motivated by the calculation of the ...
Dian's user avatar
  • 57
4 votes
1 answer
505 views

How to calculate this summation $\sum_{k=0}^m a^k b^{m-k} {n_1\choose k} {n_2\choose m-k} $?

Question: How to calculate this summation $S=\sum_{k=0}^m a^k b^{m-k} {n_1\choose k} {n_2\choose m-k} $? Where $m<n_1,m<n_2$ Remark1: When $a=b$, I know the above summation $S=a^m\sum_{k=0}^m {...
Dian's user avatar
  • 57
7 votes
1 answer
167 views

A formula for the generating function of Hoggatt binomials or of some Young tableaux

Let ${\left\langle\matrix {n \cr k}\right\rangle}_r$ denote the $r-$Hoggatt binomials defined by $${{\left\langle\matrix {n \cr k}\right\rangle}_r=\frac{\langle n \rangle_r!}{\langle k \rangle_r! \...
Johann Cigler's user avatar
5 votes
3 answers
441 views

How to calculate the sum of general type $\sum_{k=0}^n {n\choose k} {n\choose k+a} {2 k- n + a \choose r }$?

QUESTION. How to calculate the sum of such general type? $$\sum_{k=0}^n {n\choose k} {n\choose k+a} {2 k - n + a \choose r }. $$ Some particular examples $$\sum_{k=0}^n {n\choose k} {n\choose k+a} = ...
Sergii Voloshyn's user avatar
29 votes
1 answer
2k views

Reason for breakdown of a nice binomial identity

One has the nice identities $${xy\choose 1}={x\choose 1}{y\choose 1},$$ $${xy+1\choose 2}={x+1\choose 2}{y+1\choose 2}+{x\choose 2}{y\choose 2}$$ and $${xy+2\choose 3}={x+2\choose 3}{y+2\choose 3}+4{x+...
Roland Bacher's user avatar
0 votes
1 answer
150 views

Number of ways to write a finite set of cardinality n as the union of r distinct binary subsets [closed]

I want to know the number of ways to write a finite set of cardinality $n$ as the union of $r$ distinct two-element subsets. Is there a nice formula in binomial coefficients?
liu_c_6's user avatar
  • 11
1 vote
1 answer
171 views

Counting spanning trees of $K_{b+1,w+1}$ with certain properties or calculating a combinatorial sum

For $b,w \geq 0$ let $K_{b+1,w+1}$ be the complete bipartite graph with vertices $a_1,...,a_{b+1}$ on the left hand side and $c_1,...,c_{w+1}$ on the right hand side. For given $1 \leq d \leq w$ and $...
Ben Deitmar's user avatar
  • 1,295
0 votes
1 answer
199 views

upper bound on sum of product of binomial coefficients

For positive integers $\ell < m < n$, consider a partition of $[2n]$ into two $n$-element sets $(X,Y)$. How many ways are there to choose an $m$-subset $A \subset [2n]$ such that the size of the ...
wandering_lambda's user avatar
3 votes
0 answers
274 views

Inequalities for Motzkin polynomials

Let us denote by $M_{n}(t)$ the $n$-th Motzkin polynomial. It is defined by $M_1(t) = M_2(t) = 1$ and $$ M_{n}(t) = \sum_{i=0}^{\lfloor n/2\rfloor } \frac{1}{n-1-i} \binom{n-1-i}{i} \binom{n-1}{i+1} t^...
Luis Ferroni's user avatar
  • 1,889
0 votes
1 answer
403 views

Could you please confirm or deny two identities involving weighted Stirling numbers of the second kind?

In the paper [1] below, among other things, Carlitz introduced weighted Stirling numbers of the second kind $R(n,k,r)$. He also proved that the numbers $R(n,k,r)$ can be generated by \begin{equation*}%...
qifeng618's user avatar
  • 1,091
4 votes
1 answer
377 views

Counting permutations with a fixed number of descents and an extra condition

I am computing the volumes of certain polytopes and it turns out that knowing a "closed formula" for the following number would help a lot. Determine the number of permutations $\sigma\in \...
Luis Ferroni's user avatar
  • 1,889
2 votes
1 answer
383 views

Lower bound and limit of a sum with binomial coefficients

Let $$A_k = \sum_{i=1}^k i {3k-2i-1 \choose i-1} {2i-2 \choose k-i}$$ $$B_k = \sum_{i=1}^k i {3k-2i-2 \choose i-1} {2i-1 \choose k-i}$$ $$C_k = \sum_{i=1}^k (3k-2i-2) {3k-2i-3 \choose i-1} {2i\...
macat's user avatar
  • 155
5 votes
4 answers
917 views

Limit of a sum with binomial coefficients

Let $$A_k = \frac{\sum_{i=1}^ki{2k-i-1 \choose i-1}{i-1 \choose k-i}}{k{2k-1\choose k}}$$ $$B_k = \frac{\sum_{i=1}^ki{2k-i-2 \choose i-1}{i \choose k-i}}{k{2k-1\choose k}}$$ $$C_k = \frac{\sum_{i=1}^k(...
macat's user avatar
  • 155
0 votes
1 answer
167 views

Restrictions on exponents in multinomial formula

From the multinomial formula we have $$(x_1 + x_2 + \dotsb + x_m)^n = \sum_{k_1+k_2+\dotsb+k_m=n, \ k_1, k_2, \dotsc, k_m \geq 0} {n \choose k_1, k_2, \dotsc, k_m} \prod_{t=1}^m x_t^{k_t}\,.$$ I ...
eyejay's user avatar
  • 1
1 vote
1 answer
332 views

Inequalities between sums of products of certain binomial coefficients

I am a PhD student. During my researches, I often have to deal with inequalities involving sums of binomial coefficients, where the sums are indexed by some set of integer compositions. For example, ...
eti902's user avatar
  • 891
0 votes
1 answer
260 views

Proof for alternating binomial sum over even powers

I have numerical evidence that $$ \sum_{k=1}^n (-1)^k\frac{k^{p}}{n+k}\binom{2n-1}{n-k}=0 $$ For $p=2,4,6...2n-2$. How could this be proved?
Matt Majic's user avatar
3 votes
0 answers
144 views

Flat polynomials with factors of big height

Let $p(x)$ be a polynomial of degree $n$ with all coefficients in $\{-1,0,1\}$ (such polynomials are sometimes called flat). I am wondering how big the coefficients of a factor of $p$ can be. Call ...
Wolfgang's user avatar
  • 13.4k
1 vote
1 answer
211 views

A binomial product sum that turns out to be 1

The binomial product sum \begin{align*} \sum\limits_{\substack{i_1> i_2> \cdots > i_k\\i_1, i_2, \cdots, i_k \in \{1, 2, \cdots, n-1\}}}\binom{n}{i_1}\binom{i_1}{i_2}\binom{i_2}{i_3}\cdots\...
Vishnu Namboothiri K's user avatar
2 votes
3 answers
742 views

Asking for a proof for a sum of products of binomials: an "interesting" identity?

The following identity must have received alternative proofs, including a combinatorial argument by David Callan as found at Bijections for the Identity $4^n = \sum_{k = 0}^n \binom{2k}k\binom{2(n - k)...
T. Amdeberhan's user avatar

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