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Hopf algebras actions

Can you write down a general type of Hopf algebra action? How do you justify the name "action", when it is already used for group actions? There must be a common core, if the same term is ...
user avatar
1 vote
0 answers
110 views

Reference for cocommutative coalgebras

I'm looking for references on cocommutative coalgebras where I can see them as kind of infinitesimal spaces. I'm trying to understand this post Why do Lie algebras pop up, from a categorical point of ...
Lefevres's user avatar
5 votes
1 answer
246 views

Infinite-dimensional, non-unital Frobenius algebras

A Frobenius algebra is a tuple $(A,\mu,\delta,\eta,\varepsilon)$, where $A$ is a vector space over some field, $(A,\mu,\eta)$ a unital associative algebra, and $(A,\delta,\varepsilon)$ a counital ...
Qwert Otto's user avatar
3 votes
1 answer
123 views

Equivalent definitions of pro-unipotent coalgebras

I'm trying to find a reference in the literature for equivalence of the following two definitions of pro-unipotent coalgebras. Definition Let be $H$ a coagumented coalgebra and let $\Delta \colon H \...
Liz Nesterova's user avatar
2 votes
1 answer
152 views

Coproduct for a Frobenius algebra

The definition of a Frobenius algebra given here describes it as a monoid and a comonoid in a monoidal category with a compatability condition. For the special case of the category of vector spaces a ...
Didier de Montblazon's user avatar
1 vote
1 answer
140 views

Morphism of conilpotent coalgebras

I have a stupid question about morphisms of two conilpotent coalgebras $\phi:X\to Y$. Is it a morphism of coaugmented coalgebras such that $\phi(F_n(X))\subseteq F_n(Y)$? Here $F_n$ denotes the ...
HCH's user avatar
  • 359
5 votes
0 answers
114 views

Conilpotent coalgebras as pushouts of trivial coalgebras

Let $K$ be a field and $C$ a non-counital conilpotent coassociative coalgebra over $K$ whose underlying $K$-vector space is finite dimensional. Question: Can one obtain $C$ by iterately taking ...
Hadrian Heine's user avatar
7 votes
2 answers
360 views

Different Bialgebra/Hopf algebra structures on coalgebras

Given a coalgebra $C$, can there exist more than one algebra structure on $C$ giving it the structure of a bialgebra? I will also ask the same question for Hopf algebras.
Alain Rochefort's user avatar
1 vote
1 answer
651 views

What is a coalgebra?

A coalgebra is a triple $(A,\Delta,\epsilon)$ consisting of a vector space, a coproduct, and a counit. Now as we all know, just like the unit in an algebra, the counit of a coalgebra is unique, i.e. ...
johhnyelgerton's user avatar
5 votes
2 answers
343 views

Classifying Hopf algebras that admit a single irreducible comodule

Is it possible to classify Hopf algebras $H$, over a field $k$, which admit a unique (up to isomorphism) irreducible comodule, namely the trivial $1$-dim comodule $$ k \to k \otimes H, ~~ k \mapsto k ...
Spyros Olympopolous's user avatar
3 votes
1 answer
171 views

Show that a certain element is a linear combination of tensors

I posted this question on MSE but got no answer even after putting a bounty on it, so I figured I can try to ask here. Let $(A, \Delta: A \to A \otimes A)$ be bialgebra (unital and counital) such that ...
user avatar
1 vote
1 answer
232 views

$M$ comodule if and only if $N$ and $L$ comodules

Let $k$ be a field, $C$ a $k$-coalgebra, and $M$ a left $C$-comodule. Then, for a short exact sequence $$ 0 \rightarrow N \rightarrow M \rightarrow L \rightarrow 0 $$ of vector spaces, we have that $N$...
bliipbluup's user avatar
2 votes
1 answer
127 views

Non-counital coalgebras

For any unital algebra $A$, we have an associated dual coalgebra $A^{\circ}$. (Recall that it is defined to be the largest subalgebra of the $\mathbf{C}$-linear dual of $A$ such that the coproduct $\...
Bas Winkelman's user avatar
1 vote
1 answer
110 views

On reflexive bialgebras

Let $A$ be a bialgebra. We can consider $A$ as a relfexive algebra (i.e. $A\cong A^{o*}$) or relfexive coalgebra (i.e. $A\cong A^{*o}$ where in each case $o$ denotes what is sometimes called ...
Christoph Mark's user avatar
1 vote
0 answers
49 views

Weakly reflexive algebra vs proper (residually finite-dimensional) algebra

Currently I am reading the book "Hopf Algebras. An Introduction" by S. Dascalescu, C. Nastasescu, S. Raianu. There is a Definition 1.5.20 on page 44 (boldface is mine): An algebra $A$ is called ...
Nik Bren's user avatar
  • 519
4 votes
0 answers
155 views

Do comodules form an exact category?

Let $R$ be a commutative ring, $C$ a coalgebra over $R$. I am asking about the category of $C$-comodules $C$-Comod. It is clear that if $C$ is a flat $R$-module, then $C$-Comod is abelian. Hence, is ...
Bugs Bunny's user avatar
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3 votes
0 answers
99 views

Simple coalgebra under base change

Let $C$ be a simple coalgebra over a field of characteristic $0$. Let $K$ be a field extension of $k$. Is the coalgebra $C\otimes_k K$ over $K$ simple?
G.-S. Zhou's user avatar
9 votes
0 answers
371 views

Duality between coalgebras and (pseudocompact) algebras - uniqueness

The following result is well-known. It can for example be found in [Iovanov: The representation theory of profinite algebras, Theorem 1.0.2]. For definitions, see below. Let $k$ be a field. The ...
Julian Kuelshammer's user avatar
3 votes
0 answers
178 views

Completion of coalgebras

Is it possible to complete commutative dg associative (conilpotent) coalgebras over $\mathbb{Q}$ in a way so that when we complete the symmetric coalgebra $Sym(V)$ it becomes completed with respect to ...
Bashar Saleh's user avatar
2 votes
1 answer
169 views

Variant of co-Tor in a bimodule category

Say $\mathcal{C}$ is a strict monoidal abelian category and $A$ is a coalgebra object in $\mathcal{C}$, with left co-modules $M$ and right co-module $N$ (also in $\mathcal{C}$). Then we have a notion ...
Dmitry Vaintrob's user avatar
5 votes
3 answers
487 views

On a dual of Kaplansky's $2^{nd}$ conjecture: admissible algebras?

Kaplansky's second conjecture (on Hopf algebras) deals with "admissible" coalgebras: He calls a coalgebra admissible, if there is an algebra structure making it a Hopf algebra. The conjecture states ...
Konstantinos Kanakoglou's user avatar
2 votes
2 answers
566 views

Definition of a cosemisimple Hopf algebra

A cosemisimple Hopf algebra is usually defined to a Hopf algebra which is the sum of its cosimple subcoalgebras. Does this definition assume that each cosimple subcoalgebra appears only once in the ...
Lars Pettersen's user avatar
1 vote
0 answers
163 views

An identity satisfied by "Differentiation"

I asked this question in MSE but I did not received any answer. So I repeat it here: Assume that $C$ is a coalgebra with comultiplication $\Delta:C \to C\otimes C$. The higher order ...
Ali Taghavi's user avatar
5 votes
0 answers
246 views

Injectivity criterion for surjective coalgebra maps: does it hold in full generality?

Let $\mathbf{k}$ be a commutative ring. Let $C$ be a filtered $\mathbf{k}$-coalgebra. This means a $\mathbf{k}$-coalgebra equipped with an increasing $\mathbf{k}$-module filtration $C^0 \subseteq C^1 \...
darij grinberg's user avatar
1 vote
0 answers
165 views

Coinduction and corestriction are quasi-inverse equivalences for comodules?

I'm reading http://arxiv.org/abs/math/0310337. There the following statement is given without proof: Let $k$ be a field. Let $C$ be a counitary coaugmented coalgebra, i.e. there is $\eta: C\to k$ ...
Julian Kuelshammer's user avatar
1 vote
1 answer
435 views

(Co)Universal Property of Quotients/Subs

I'm not completely sure if this bunch of questions is the appropriate Level of MO. However at the same time I think that it is at least slightly above the level of stackex. ... The tensor algebra ...
Mark.Neuhaus's user avatar
  • 2,074
2 votes
1 answer
626 views

Reference for the fact that a coderivation of the (non reduced) tensor coalgebra is determined by its corestrictions

If $V$ is a vector space, let us consider the tensor coalgebra $TV=\bigoplus\limits_{k=0}^\infty V^{\otimes^k}$ with coproduct given by $$\Delta (x_1\otimes \dots \otimes x_n):= \sum\limits_{i=0}^{n}(...
yael fregier's user avatar
1 vote
1 answer
171 views

Linear functional kills all primitives of a connected filtered coalgebra => it lies in m^2?

Let $C$ be a connected filtered coalgebra over a field $k$. Maybe $k$ has characteristic $0$ (though I don't know where this can be of use). Let $1$ denote the unique element of $C_0$ mapping to $1\in ...
darij grinberg's user avatar
13 votes
1 answer
1k views

Why not _co_free modules?

Let $R$ be a ring, and $R\text{-Mod}$ its category of all left modules. There is a "forgetful" functor $\operatorname{Forget}: R\text{-Mod} \to \text{AbGp}$, which is additive, continuous, and ...
Theo Johnson-Freyd's user avatar
39 votes
5 answers
4k views

Is there an explicit construction of a free coalgebra?

I am interested in the differences between algebras and coalgebras. Naively, it does not seem as though there is much difference: after all, all you have done is to reverse the arrows in the ...
Bruce Westbury's user avatar