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1 answer
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Partial sums of binomial coefficients and related family of polynomials

Let $a(n)$ be A302117. Here $$ a(n) = 4(n-1)a(n-1) - \frac{1}{3}\prod\limits_{k=0}^{n-1}(2k-3), \\ a(0) = 0. $$ Let $$ T(n,k) = \sum\limits_{i=0}^{k} \binom{n}{i}. $$ Let $P_n(z)$ be the family of ...
Notamathematician's user avatar
0 votes
1 answer
98 views

Only special permutations result in a constant expression when permuting coefficients in a sum involving binomials?

Fix $n\geq 1$ and let $p_k(x) := x^k(x-1)^{n-k}$. Suppose $\pi$ is a permutation on $\{0,1,\dotsc,n\}$, such that $$ \sum_{k=0}^n (-1)^k \binom{n}{k} p_{\pi(k)}(x) \text{ is a constant}. $$ Must it be ...
Per Alexandersson's user avatar
5 votes
0 answers
183 views

On the polynomials $\sum_{k=0}^n\binom{n+k}k^m q^k$

A sequence of polynomials $$P_0(q),\ P_1(q),\ P_2(q),\ \ldots$$ with real coefficients is called $q$-log-convex if for each $n=1,2,3,\ldots$ every coefficient of the polynomial $P_{n+1}(q)P_{n-1}(q)-...
Zhi-Wei Sun's user avatar
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4 votes
0 answers
134 views

Irreducibility of polynomials associated to binomial coefficients

Let $n \geq 2$. Let $M_n$ be the $(n+1) \times (n+1)$ matrix with entries $\binom{l}{k}$ for $0 \leq l,k \leq n$ and $U_n=M_n + M_n^T$ and let $f_n(x)$ denote the characteristic polynomial of $U_n$. ...
Mare's user avatar
  • 26.5k
0 votes
1 answer
167 views

Restrictions on exponents in multinomial formula

From the multinomial formula we have $$(x_1 + x_2 + \dotsb + x_m)^n = \sum_{k_1+k_2+\dotsb+k_m=n, \ k_1, k_2, \dotsc, k_m \geq 0} {n \choose k_1, k_2, \dotsc, k_m} \prod_{t=1}^m x_t^{k_t}\,.$$ I ...
eyejay's user avatar
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3 votes
0 answers
144 views

Flat polynomials with factors of big height

Let $p(x)$ be a polynomial of degree $n$ with all coefficients in $\{-1,0,1\}$ (such polynomials are sometimes called flat). I am wondering how big the coefficients of a factor of $p$ can be. Call ...
Wolfgang's user avatar
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3 votes
3 answers
396 views

Chebyshev polynomials and ballot numbers

I have asked this question a short time ago on mathstackexchange, but it has already fallen into the abyss of answered and uncommented questions. So I take the risk to ask it on mathoverflow. Playing ...
Libli's user avatar
  • 7,300
21 votes
2 answers
2k views

Real rootedness of a polynomial

Let's consider $m$ and $n$ arbitrary positive integers, with $m\leq n$, and the polynomial given by: $$ P_{m,n}(t) := \sum_{j=0}^m \binom{m}{j}\binom{n}{j} t^j$$ I've found with Sage that for every $...
Luis Ferroni's user avatar
  • 1,889
0 votes
1 answer
296 views

Showing equality of Eberlein polynomials

I have thought about the following question a long time and still got no progress. Currently I am writing my master thesis about association schemes in combinatorics and need an equality which seems ...
McRatchet's user avatar
18 votes
3 answers
860 views

$\prod_k(x\pm k)$ in binomial basis?

Let $x$ be an indeterminate and $n$ a non-negative integer. Question. The following seems to be true. Is it? $$x\prod_{k=1}^n(k^2-x^2)=\frac1{4^n}\sum_{m=0}^n\binom{n-x}m\binom{n+x}{n-m}(x+2m-n)^...
T. Amdeberhan's user avatar
8 votes
3 answers
642 views

Combinatorial identity with connection coefficients and falling factorial $\langle i x\rangle_n$

Let $j, k ,n$ be nonnegative integers such that $0 \leq j, k \leq n \leq k +j $. Pick integer $m$ such that $0 \leq m \leq k + j - n$. Let $\langle x \rangle_m$ denote the falling factorial $x(x-1)\...
Nick R's user avatar
  • 1,187
47 votes
1 answer
4k views

How to prove this polynomial always has integer values at all integers?

Let $m$ be any positive integer. $$ P_m(x)=\sum_{i=0}^{m}\sum_{j=0}^{m}{x+j\choose j}{x-1\choose j}{j\choose i}{m\choose i}{i\choose m-j}\frac{3}{(2i-1)(2j+1)(2m-2i-1)}. $$ Question: $P_m(x)$ always ...
Chitsai Liu's user avatar
  • 2,183
2 votes
3 answers
634 views

Variant of binomial coefficients

I've recently come across a variant of the binomial polynomials, and I'm curious if anyone has seen these before. If so, I'd love a reference, a name, etc. First recall the following. If z is a ...
Daniel Erman's user avatar
  • 2,955