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4 votes
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is a 4-connected planar graph still Hamiltonian after removing an edge?

We know that 4-connected planar graphs are Hamiltonian(by the known Tutte Theorem). Additionally, Thomas and Yu [1] proved that removing two vertices from a 4-connected planar graph still preserves ...
Licheng Zhang's user avatar
1 vote
0 answers
93 views

15-game graph contains a Hamiltonian path ? Lovász conjecture for groupoids, loops, quasigroups , etc?

Typically Cayley graphs are defined for groups and generators sets S. But basically one only needs some set S and another set V and partially defined operation SxV->V, then one defines graph with ...
Alexander Chervov's user avatar
5 votes
2 answers
190 views

Number of Hamiltonian cycles on 24-cell graph

I asked Wolfram Alpha for the number of Hamiltonian cycles on the 24-cell graph. https://www.wolframalpha.com/input?i=number+of+hamiltonian+cycles+on+24-cell+graph It answers 114.9 billion but doesn't ...
Etienne's user avatar
  • 53
0 votes
0 answers
61 views

Clique sizes of generalized Kneser graphs

Are there known bounds for clique size in generalized Kneser graphs $KG(n,k,t)=K(n,k,t-1)$, the graph formed by distinct $k$ subsets of $n$ set so that two subsets with at most $t$ elements in common ...
vidyarthi's user avatar
  • 2,089
0 votes
0 answers
65 views

Cycles in Kneser graphs with three vertices forming triangles

Consider the Kneser graphs $G=K(n,k)$. Is it possible to list how many even cycles, or, at the least, existence of an even cycle of a given order in $G$, such that any three consecutive vertices form ...
vidyarthi's user avatar
  • 2,089
5 votes
0 answers
126 views

Do uniquely Hamiltonian graphs have cycles of a sufficiently long length?

Let $C$ be a Hamiltonian cycle of a graph $G$. Call an edge $e$ of $G$ a chord if $e\not\in C$. Let each edge of $C$ be weighted $1$ and each chord be weighted $2$. The weight of a path or cycle of ...
kabenyuk's user avatar
  • 673
1 vote
1 answer
92 views

Existence of a strongly regular vertex ordering on cubic graphs

Definition: Let $G=(V,E)$ be a cubic (i.e. $3$-regular) graph, and $<$ a total order on $V$. For $v\in V$ let $v^\downarrow$ denote the set of nodes $w\in V$ such that $w<v$, and let $\alpha(v) =...
BHT's user avatar
  • 191
2 votes
0 answers
111 views

Constructing Hamiltonian circuits in acyclic digraphs

Any directed graph $G$ lacking cycles can acquire a Hamiltonian circuit through the addition of a sufficient number of edges. Q. Is there a method to minimize the addition of edges to achieve a ...
ABB's user avatar
  • 4,058
4 votes
0 answers
234 views

How many 20-vertex 2-connected 5-regular non-Hamiltonian graphs are there?

As for the question in title, I attempted to use nauty to obtain them, but it has been running on my computer for nearly three days without producing any results. <...
Licheng Zhang's user avatar
3 votes
1 answer
104 views

Edge coloring of a graph on alternating groups

Let $G$ be the Cayley graph on the alternating group $A_n\,n\ge4$ with generating set $$S=\begin{cases}\{(1,2,3),(1,3,2),\\(1,2,\ldots,n),(1,n,n-1,\ldots,2)\}, &n\ \text{odd}\\ \{(1,2,3),(1,3,2),\\...
vidyarthi's user avatar
  • 2,089
2 votes
2 answers
234 views

Decompose complete directed graph with n vertices into n edge-disjoint cycles with length n−1

I want to know how to decompose a complete directed graph with $n$ nodes into $n$ edge-disjoint cycles with length $n-1$. I found this result was proved in Bermond and Faber - Decomposition of the ...
chunma's user avatar
  • 21
9 votes
2 answers
2k views

Is this graph Hamiltonian?

Let $G$ be a simple $2$-connected graph with $m+n$ vertices ($n>m \geq 3$) with degree sequence $(m-1)^m$, $(n-1)^n$; that is, $G$ is degree-equivalent to two disjoint cliques $K_m$, $K_n$ of ...
Valentin Brimkov's user avatar
6 votes
0 answers
164 views

Hamilton cycles in random graphs with just enough connectivity

What is the asymptotic probability that $G$ has a Hamilton cycle if $G$ is a random $n$ vertex $\frac{4}{3}n$ edge graph, with minimum degree 2 and without degree 2 vertices at distance 1 or 2 to each ...
Dmytro Taranovsky's user avatar
3 votes
0 answers
76 views

Hamiltonian cycles in Cayley graph on alternating group

Let $G=\operatorname{Cay}(A_n,S)$ be the Cayley graph on the Alternating group $A_n\quad n\ge4$ with generating set $S=\{(1,2,3),(1,2,4),\ldots,(1,4,2),(1,3,2)\}$. One Hamiltonian cycle in $G$ for $n=...
vidyarthi's user avatar
  • 2,089
5 votes
0 answers
154 views

How to construct 4-regular graphs with few Hamiltonian decompositions?

A Hamiltonian decomposition of a finite simple graph is a partition of its edge set so that each partition class forms a Hamiltonian cycle. This is only possible if the graph is $2k$-regular. ...
M. Winter's user avatar
  • 13.6k
5 votes
1 answer
279 views

Infinitely many counterexamples to Nash-Williams's conjecture about hamiltonicity?

Question from 2013 gives one counterexample to Nash-Williams's conjecture about hamiltonicity of dense digraphs. Later, we found tens of counterexamples on more than 30 vertices and believe there are ...
joro's user avatar
  • 25.4k
2 votes
0 answers
116 views

Two more counterexamples to a conjecture from 1975 about hamiltonicity of digraphs

Question from 2013 gives one counterexample to Nash-Williams's conjecture 1975 about hamiltonicity of dense digraphs. In the linked answer, @LouisD "reverse engineered" the counterexample ...
joro's user avatar
  • 25.4k
2 votes
1 answer
85 views

The number of Hamiltonian circuits on a convex polytope embedded in $\mathbb{R}^N$

Recently I wondered whether there might be a natural topological complexity measure for convex polytopes embedded in $\mathbb{R}^N$. After some reflection it occurred to me that the number of distinct ...
Aidan Rocke's user avatar
  • 3,871
3 votes
1 answer
138 views

Edge colorability and Hamiltonicity of certain classes of cubic graphs (MO graphs)

Let $G$ be a simple cubic graph (that is, 3-regular). A dominating circuit of $G$ is a circuit $C$ such that each edge of $G$ has an endvertex in $C$. The circuit $C$ is chordless if no edge which is ...
EGME's user avatar
  • 1,018
1 vote
3 answers
6k views

Which are good algorithms for finding Hamiltonian path (not necessarily a circle) up to now?

I am not expertise in graph theory. So have to ask this question here. The term "good" means that the algorithms should be efficient for general undirected simple connected graphs with a higher ...
Licheng Wang's user avatar
12 votes
1 answer
424 views

Quantitatively characterizing the failure of the converse of Dirac's theorem

First, I am an undergraduate so I apologize if this is trivial and certainly understand if it is closed immediately. I am currently in a combinatorics and graph theory class and recently we have ...
1729's user avatar
  • 221
4 votes
0 answers
143 views

Halin Graphs with Highest Number of Hamilton Cycles

Halin graphs contain a Hamilton cycle and have the interesting property, that, also in the case of arbitrary real edge weights, it is possible to report one of the shortest contained Hamilton cycles ...
Manfred Weis's user avatar
  • 13.2k
9 votes
1 answer
399 views

Are bipartite Moore graphs Hamiltonian?

This is motivated by a computer-generated conjecture that bipartite distance-regular graphs are hamiltonian. I decided to check the case of Moore graphs first. The cycles and complete bipartite graphs ...
LeechLattice's user avatar
  • 9,501
9 votes
2 answers
2k views

"Gray code" of all permutations

Informally asking, can we step through all permutations of the set $\{1,\ldots,n\}$ by just using transpositions? More formally: For any $n\in\mathbb{N}$ let $[n] = \{1,\ldots,n\}$ and let $S_n$ be ...
Dominic van der Zypen's user avatar
3 votes
1 answer
233 views

Counting cycle vertex covers on hypercube

Let $Q_n$ be the $n$-dimensional hypercube graph. How many vertex cycle covers exist on $Q_n$? (Presumably the best we can hope for are upper and lower bounds.) To be clear, a single "vertex cycle ...
Bill Bradley's user avatar
  • 3,979
1 vote
1 answer
78 views

Graph gadget related to uniquely hamiltionian regular graphs (question #2)

Related to uniquely hamiltionian graphs. For natural numbers $a,b$ define $(a,b)$ gadget $G$: $G$ is finite simple graph. Two vertices $u,v$ are of degree $b$ and the rest of the vertices are of ...
joro's user avatar
  • 25.4k
5 votes
0 answers
99 views

Graph gadget related to uniquely hamiltionian regular graphs

A graph is uniquely hamiltonian if it has exactly one hamiltonian cycle. According to a conjecture there are no $r$-regular uniquely hamiltonian graphs for $r > 2$ and of special interest is the ...
joro's user avatar
  • 25.4k
6 votes
0 answers
76 views

Cage graphs and even cycles

Let $G$ be a $(\nu,g)$-cage graph of degree $\nu$ with girth $g$ and $n=n(\nu,g)$ vertices. Based on the known examples, I am wondering if the following can be proved/disproved: Is it true that ...
Wolfgang's user avatar
  • 13.4k
15 votes
2 answers
2k views

What is the smallest uniquely hamiltonian graph with minimum degree at least 3?

I would like to know more about uniquely hamiltonian graphs with minimum vertex degree at least 3, and in particular what is the smallest one. (Recall that a graph is hamiltonian if it has a cycle ...
Gordon Royle's user avatar
  • 12.7k
11 votes
1 answer
328 views

How many edges can be added to two circles before the graph becomes Hamiltonian?

Start with two $n$-circles $(v_1\cdots v_n)$ and $(w_1\cdots w_n)$ of vertice sets $V$ and $W$, where $n\ge 5$. Add a number of vertex-disjoint edges between $V$ and $W$ (thus no chords) in a way ...
Wolfgang's user avatar
  • 13.4k
3 votes
1 answer
266 views

What is the densest bipartite graph with unique Hamiltonian cycle?

In a prior post regarding perfect matching, it was stated that the densest graph with a unique perfect matching cannot have more than $n^2$ edges, if graph has $2n$ vertices. Analogously, what is the ...
Turbo's user avatar
  • 13.9k
7 votes
1 answer
734 views

Refinement of Dirac's theorem on Hamiltonian graphs

Dirac's theorem states that if degree of each vertex of a graph $G=(V,E)$ is not less than $|V|/2$, then it has Hamiltonian cycle. It is less known, but still known and not so hard to prove (though I ...
Fedor Petrov's user avatar
4 votes
2 answers
349 views

Can we find 3 disjoint directed Hamiltonian cycles in the cube?

Let $D$ be the digraph on $2^d$ vertices with $d2^d$ edges that we obtain by directing each edge of the $d$-dimensional hypercube in both directions. Can we partition the edges of $D$ into $d$ ...
domotorp's user avatar
  • 18.9k
5 votes
1 answer
1k views

How many hamiltonian cycles can be removed from a complete directed graph before it becomes disconnected?

The question started from a problem brought home by a friend's 5th grader: "How many ways can you seat 5 people around a round table so that the people sitting to the left of any person is different ...
Michael's user avatar
  • 2,205
4 votes
0 answers
257 views

When is an induced subgraph of a Johnson graph hamilton-connected?

The Johnson graph $J(n,k)$ has as its vertices the $k$-subsets of $\{1, 2, \dots, n\}$ where two vertices are adjacent iff their intersection has size $k-1$. A graph is Hamilton-connected if every two ...
jamisans's user avatar
  • 393
6 votes
1 answer
243 views

Hamiltonicity criteria for sparse graphs

Given a sparse graph, how can one go about proving that it is Hamiltonian? (Assuming it actually is, of course). There are three main classes of criteria for Hamiltonicity that I am aware of: Dirac-...
Felix Goldberg's user avatar
3 votes
1 answer
219 views

Regular graphs with $a$ and $b$ Hamiltonian edges

Special case of this question. Let $G$ be $r$-regular Hamiltonian graph. An $a$ edge is an edge which is on every Hamiltonian cycle. A $b$ edge is an edge which is on no Hamiltonian cycle. $a(G)$ ...
joro's user avatar
  • 25.4k
10 votes
2 answers
782 views

Graphs with many edges avoided by Hamiltonian cycles

Let $G$ be a $3$-connected Hamiltonian graph with at least one edge that belongs to each H-cycle of $G$. Some authors (e.g. in the link given here) call such an edge an a-edge and an edge that belongs ...
Wolfgang's user avatar
  • 13.4k
5 votes
1 answer
224 views

Reconstructing the number of Hamiltonian cycles

As is common terminology in graph reconstruction, given a graph $G$, we call a vertex deleted subgraph of $G$, a card, and call the multiset of all cards, the deck of $G$. The graph reconstruction ...
Gjergji Zaimi's user avatar
12 votes
1 answer
2k views

Hobbled rook tour – Hamiltonian cycle on square grid

Consider a square grid of even side length ($2n \times 2n$). It is easy to see that there must exist a Hamiltonian cycle on the corresponding grid graph. Such a cycle is called balanced if the number ...
John's user avatar
  • 121