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Questions tagged [binomial-coefficients]

For questions that explicitly reference the binomial coefficients, Pascal's Triangle, and Binomial identities.

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5 votes
2 answers
379 views

Asymptotic rate for $\sum\binom{n}k^{-1}$

This MO question prompted me to ask: What is the second order asymptotic growth/decay rate for the sum $$\sum_{k=0}^n\frac1{\binom{n}k}$$ as $n\rightarrow\infty$?
T. Amdeberhan's user avatar
5 votes
1 answer
685 views

Summing ratio of ratio of partial sums of binomial coefficients

I would like to approximate the following when $n \gg k$. $\sum_{y = k + 1}^n \frac{\sum_{m = 0}^{k - 1} {y - 2 \choose m} (y - 1)}{\sum_{m = 0}^k {y - 1 \choose m}}.$ The formula can be re-written ...
ELW's user avatar
  • 83
4 votes
0 answers
168 views

How to prove the following equation (which involves binomials and determinant of 2×2 matrices)?

I have tried many ways to prove the following equation, such as the method of induction and expanding all the terms in the summation,but things got more complicated.I could not find an appropriate ...
tongjun's user avatar
  • 41
4 votes
1 answer
505 views

How to calculate this summation $\sum_{k=0}^m a^k b^{m-k} {n_1\choose k} {n_2\choose m-k} $?

Question: How to calculate this summation $S=\sum_{k=0}^m a^k b^{m-k} {n_1\choose k} {n_2\choose m-k} $? Where $m<n_1,m<n_2$ Remark1: When $a=b$, I know the above summation $S=a^m\sum_{k=0}^m {...
Dian's user avatar
  • 57
4 votes
0 answers
312 views

Positivity of a finite sum involving Stirling numbers of the first kind

Past days I've been trying to prove that certain polynomials have positive coefficients. After a lot of thinking, I came up with a formula for each coefficient individually, and they are not that ugly....
Luis Ferroni's user avatar
  • 1,889
4 votes
2 answers
7k views

Partial Sum of the Binomial Theorem [duplicate]

The binomial theorem states $\sum_{k=0}^nC_n^kr^k=(1+r)^n$. I am interested in the function \begin{equation} \sum_{k=0}^mC_n^kr^k, \quad m<n \end{equation} for fixed $n$ and $r$, and both $m$ and $...
Jian's user avatar
  • 41
3 votes
1 answer
194 views

Effective Realization of GCD of middle binomials?

So, it is well-known that $$ \gcd \left(\binom{m}{k}\mid 1\leq k\lt m \right) = e^{\Lambda(m)}$$ which can incidentally be sparsified for prime $p$ $$ \gcd \left(\binom{p^{r+1}}{1},\binom{p^{r+1}}{p^...
Jesse C. McKeown's user avatar
3 votes
0 answers
144 views

Flat polynomials with factors of big height

Let $p(x)$ be a polynomial of degree $n$ with all coefficients in $\{-1,0,1\}$ (such polynomials are sometimes called flat). I am wondering how big the coefficients of a factor of $p$ can be. Call ...
Wolfgang's user avatar
  • 13.4k
3 votes
0 answers
151 views

Combinatorial interpretation of inverse modulo $2$ binomial transform of A284005

My question is related to the following: Sum with products turned into subsequences We have an identity $$a(n, -1) = \sum\limits_{j=0}^{2^{\operatorname{wt}(n)}-1}(-1)^{\operatorname{wt}(n)-\...
Notamathematician's user avatar
3 votes
3 answers
493 views

Show that the ratio of limits converges to the nearest Riemann zeta zero except when the ratio is a singularity

Let $h(s,n)$ be: $$h(s,n)=\lim_{c\to 1} \, \frac{(-1)^{n-2}}{(n-2)!}\zeta (c)^{n-2} \sum _{k=1}^{n-1} \frac{(-1)^{k-1} \binom{n-2}{k-1}}{\zeta ((c-1) (k-1)+s)}$$ and let $g(s,n)$ be: $$g(s,n)=\lim_{c\...
Mats Granvik's user avatar
  • 1,183
3 votes
0 answers
585 views

Sum of binomial coefficients weighted by a lower incomplete regularized gamma function

The following summation turned up in the course of my research: $$S_n=\sum_{k=0}^n {n \choose k}\lambda^k P(k,t)$$ where $P(k,t)=\frac{1}{\Gamma(k)}\int_{0}^t e^{-x}x^{k-1}dx$ is the lower ...
Bullmoose's user avatar
  • 907
2 votes
1 answer
909 views

Upper bound of sum of binomial coefficients

I am looking for an upper bound - up to constant factor - for: $\sum_{k=t}^{t+l} {n \choose k} \cdot 2^{-n}$ where: The values of $t$ are between: $\frac{n}2+\sqrt{n} \leq t \leq \frac{9n}{10}$. (...
Nissan Levi's user avatar
2 votes
1 answer
236 views

An integer sequence related to Pascal’s triangle

We need someone expert in binomial coefficients (subject 11B65) to recognize the integer sequence generated by an iterative formula we have encountered while working on a project about Pascal’s ...
Monk's user avatar
  • 125
2 votes
1 answer
344 views

Show that $\sum_{i=0}^{2k} [ {n\choose i+1} + (-1)^{i+1}{n+i+1\choose i+1} ] \sum_{j=0}^i {i\choose j}(-1)^j (i+1-j)^{2k} =0.$

Let $u(k,j) = 1$ if $j=0$, $0$ if $j > k$, or else it is $j*u(k-1,j-1) +(j+1)*u(k-1,j) $. Prove that $ \sum_{i=0}^{2k} {n \choose i+1} u(2k,i) +\sum_{i=0}^{2k} {-n-1 \choose i+1} u(2k,i)=0. $ ...
Benjamin L. Warren's user avatar
2 votes
1 answer
147 views

Tight sublinear estimates for a triple partial binomial summation

Is there tight estimates for the following logarithmic summation ($\gamma,\gamma'\in(0,1)$ and $\mu,\mu'>0$) $$\log_2\Bigg(\sum_{t=\frac{n^{}}2-n^\gamma\sqrt{\mu\ln n}}^{\frac{n^{}}2+n^\gamma\sqrt{...
VS.'s user avatar
  • 1,826
2 votes
1 answer
235 views

Sum of squares of middle binomial sums or 'Truncated mean' of binomial coefficients under binomial distribution

$\mu=1+\epsilon$ where $\epsilon>0$ holds. 1.Is there a good bound for $$T=\frac{\sum_{i=-\sqrt{\mu n\ln n}}^{\sqrt{\mu n\ln n}}\binom{n}{\frac n2 +i}^2}{2^n}?$$ This quantity can be ...
VS.'s user avatar
  • 1,826
1 vote
1 answer
3k views

Coefficients in the sum $\sum_{k=0}^{n-1}\sum_{j=0}^{m}A_{j,m}(n-k)^jk^j=n^{2m+1}, \ m=1,2,....$

Consider a sum $$\sum_{k=0}^{n-1}\sum_{j=0}^{m}A_{j,m}(n-k)^jk^j$$ which returns an odd power $n^{2m+1}$ of $n$, for $\ m=0,1,2,...$ given fixed $A_{0,m}, \ A_{1,m}, \ ..., \ A_{m,m}$. The ...
Petro Kolosov's user avatar
1 vote
0 answers
95 views

On level-$12$ of the McKay-Thompson series of the Monster and the Domb numbers

(This continues from level 10.) Given some moonshine functions $j_{N}$. There are nice descending and consistent relations for levels $6m$ with $m= 2,3,5,$ $$j_{12A} = \left(\sqrt{j_{12H}} + \frac{\...
Tito Piezas III's user avatar
1 vote
0 answers
116 views

On level $6$ of the McKay–Thompson series of the Monster and Apéry numbers, et al

After the McKay–Thompson series of levels $1$, $2$, $3$, $4$ of the Monster were mentioned in this MO post, level $6$ has very interesting relations as well. (Level 10 is in this post.) I. Level-6 ...
Tito Piezas III's user avatar
1 vote
2 answers
165 views

A conjecture on 'truncated joint moments' of binomial coefficients under binomial distribution

This is similar in spirit to Sum of squares of middle binomial sums or 'Truncated mean' of binomial coefficients under binomial distribution but gives some total estimates. Though the other ...
VS.'s user avatar
  • 1,826
1 vote
1 answer
124 views

Tight estimates for binomial summation

Is there tight estimates for the following logarithmic summation ($\gamma\in(0,1)$) $$\ln\Bigg(\sum_{t=\frac{n^{}}2-\gamma n^\gamma}^{\frac{n^{}}2+\gamma n^\gamma}\sum_{\ell=\frac{n^{}}2-\gamma n^\...
VS.'s user avatar
  • 1,826
1 vote
1 answer
2k views

How to calculate such sum of product of binomial coefficient?

..I wonder if the following formula can be calculated? $ \sum_{k=0}^m {m \choose k} {2k \choose n} $
user18717's user avatar
  • 351
1 vote
2 answers
368 views

Closed form of $ \sum_{i=1}^{n-k} {n-1-i\choose k-1}i^a + \sum_{i=1}^k {n-1-i\choose n-1-k}$

For all natural numbers $a$, is there a known closed form of $ \sum_{i=1}^{n-k} {n-1-i\choose k-1}i^a + \sum_{i=1}^k {n-1-i\choose n-1-k}$, where $k$ is fixed? For example, letting $k=1$ gives the ...
Benjamin L. Warren's user avatar
0 votes
1 answer
705 views

Asymptotic behaviour of Binomial Sum

I am interested in the behaviour of: $\gamma_k=\sum_{i=0}^{k} {n \choose i}$ as n becomes large and where $k$ could potentially be a function of $n$ rather than a constant. One line of attack I can ...
Stan's user avatar
  • 103
0 votes
1 answer
330 views

Sum of the first m terms of the expansion $(x+y)^n$

Let $S(x, y, m, n) = \sum\limits_{i=0}^m \binom{n}{i}x^i y^{n-i}$, where $0 < m < n$. I want to derive the relation between $S(x, y, m, n)$ and $S(x, y, m, n-1)$. Is there any formulas I can use?...
one user's user avatar
  • 113
0 votes
2 answers
328 views

Closed form for a binomial product sum

Is there any closed formula for the binomial product sum \begin{align*} \sum\limits_{\substack{i_1> i_2> \cdots > i_k\\i_1, i_2, \cdots, i_k \in \{n-j+1, n-j+2, \cdots, n-1\}}}\binom{n}{i_1}\...
Vishnu Namboothiri K's user avatar
0 votes
0 answers
174 views

3D generalization of Gaussian q-binomial coefficient

It is known that the coefficient of $q^t$ in Gaussian binomial coefficient $\binom{m+n}m_q$ equals the number of permutations of the multiset $\{0^m, 1^n\}$ with $t$ inversions. Is there a closed ...
Max Alekseyev's user avatar
0 votes
1 answer
208 views

Local behavior of the Vandermonde convolution

An interesting combinatorial identity is the Vandermonde convolution identity: $$ \sum_k {n\choose k}{m\choose s-k} = {n+m \choose s},$$ which can be proved by considering the coefficients in $(x+1)^{...
Student's user avatar
  • 5,230
-1 votes
3 answers
312 views

Binomial Coefficients sum [closed]

Any idea on whether or not $$\sum_{i = 0}^b(-1)^i\binom{b}{i}\binom{a+b-i-1}{a-i}$$ has a closed formula on $a$ and $b$ (and on what it is, in case it does)? It is supposed that $b \le a$.
Valentino's user avatar
  • 369

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