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15 votes
3 answers
2k views

Disintegrations are measurable measures - when are they continuous?

This is a sequel to another question I have asked. The notion of disintegration is a refinement of conditional probability to spaces which have more structure than abstract probability spaces; ...
Tom LaGatta's user avatar
  • 8,512
5 votes
1 answer
403 views

Nonlinear Nuclear Operators ?

Is there a "right" definition of the nuclear operator in the nonlinear framework ? Of course, such an operator must be compact, while a linear operator should be "nonlinearly" nuclear iff it is ...
Ady's user avatar
  • 4,060
4 votes
2 answers
340 views

Embeddings of Weighted Banach Spaces

Let be $d$ a positive integer, $\Omega=\mathbb{R}^{\mathbb{Z}^d}$ and fix $R\geq 2$. We define weighted Banach spaces $$ \Omega_p:=\left\{ x\in \Omega\left| \left[\sum_{i\in\mathbb{Z}^d}\frac{|x_i|^...
Leandro's user avatar
  • 2,044
6 votes
2 answers
3k views

Dense inclusions of Banach spaces and their duals

This seems like a really simple question, but I'm struggling with it. Let $X$ be a separable Banach space, $H$ be a separable Hilbert space, and suppose $i : H \hookrightarrow X$ is a dense, ...
Tom LaGatta's user avatar
  • 8,512
4 votes
1 answer
822 views

What is the tensor product of $L^p(\bf R)$ with $L^q(\bf R)$?

I'm wondering: What is the tensor product of $L^p({\bf R})$ with $L^q({\bf R})$? (For p=q=2, the answer clearly should be $L^2({\bf R}^2)$; for other values of $p$ and $q$, it is not at all obvious ...
Anonymous's user avatar
7 votes
2 answers
684 views

Yet more on distortion

I would like to elaborate a little bit on my previous question which can be found here. Firstly, let me recall that a separable Banach space $(X, \| \cdot \|)$ is said to be arbitrarily distortable ...
Pandelis Dodos's user avatar
7 votes
4 answers
946 views

On operator ranges in Hilbert & Banach spaces

Lemma 1 from Anderson & Trapp's Shorted Operators, II isLet $A$ and $B$ be bounded operators on the Hilbert space $\mathcal H$. The following statements are equivalent: (1) ran($A$) $\subset$ ...
Tom LaGatta's user avatar
  • 8,512
4 votes
3 answers
2k views

Algebraic Dual / Continuous Dual

Let $E$ be an infinite dimensional Banach space, let $E^{\ast}$ denote its continuous (i.e., Banach space) dual, and let $E'$ be its algebraic dual. Clearly, $E^{\ast}$ is a proper vector subspace of $...
Ady's user avatar
  • 4,060
11 votes
3 answers
1k views

Continuous automorphism groups of normed vector spaces?

Consider the metric space on, say, ℝ2 induced by the various $L^p$ norms, and the group of isometries from that space into itself that preserve the origin. When $p=2$ I get the continuous group ...
Jason Reed's user avatar
6 votes
0 answers
639 views

Hilbert subspaces of indefinite inner product spaces

Let $E$ be a real linear space, endowed with a non-degenerate symmetric bilinear form $(.,.)$. Suppose that the [indefinite] inner product space $(E,(.,.))$ satisfies the following [sequential] ...
Ady's user avatar
  • 4,060
16 votes
0 answers
1k views

Finite Rank Commutators

My former student Detelin Dosev and I are interested in classifying the commutators in $L(X)$, the bounded linear operators on the Banach space $X$ (see our joint paper on my home page or the ArXiv ...
Bill Johnson's user avatar
  • 31.5k
10 votes
0 answers
609 views

Asymptotic non-distortion of the separable Hilbert space

By the work of E. Odell and Th. Schlumprecht, we know that the separable Hilbert space $\ell_2$ is arbitrarily distortable. But I don't know if an "asymptotic" version of their result is true. To ...
Pandelis Dodos's user avatar
34 votes
8 answers
9k views

When is a Banach space a Hilbert space?

Let $\mathcal{X}$ be a real or complex Banach space. It is a well known fact that $\mathcal{X}$ is a Hilbert space (i.e. the norm comes from an inner product) if the parallelogram identity holds. ...
Teiko Heinosaari's user avatar
3 votes
2 answers
416 views

Which Banach spaces have categorical duals?

I was looking carefully at all the definitions, trying to understand exactly what was going on in this question on categorical duals in Banach spaces. It seems that in the category of Banach spaces ...
Andrew Stacey's user avatar
9 votes
1 answer
996 views

Topological "Interpolation" ?

Let E be a normed space, and let $T$:E * $\rightarrow$ E * be a nonlinear operator. Suppose that : 1) $T$ is continuous from (E *, ||.||) to itself (i.e., it is norm-continuous). and 2) $T$ is ...
Ady's user avatar
  • 4,060
9 votes
4 answers
1k views

Boundedness of nonlinear continuous functionals

Let $K$ be the closed unit ball of $C[0,1]$, and let $f$ in $C(K,\mathbb{\, R})$. Is it true that there exists an infinite dimensional reflexive subspace $E$ of $C[0,1]$ s.t. $f(K\cap E)$ is bounded ? ...
Ady's user avatar
  • 4,060
13 votes
4 answers
2k views

Is the category of Banach spaces with contractions an algebraic theory?

Consider the category of Banach spaces with contractions as morphisms (weak, so $\|T\| \le 1$). Is this an algebraic theory? I suspect that this is true. The "operations" will be weighted sums, ...
Andrew Stacey's user avatar
5 votes
2 answers
765 views

Can we distinguish the algebraic and continuous duals of a Banach space without choice (or HBT)?

The algebraic dual of a normed vector space is the space of all linear functionals to the ground field (either $\mathbb{R}$ or $\mathbb{C}$ for this question). The continuous dual is the subspace of ...
Andrew Stacey's user avatar
18 votes
3 answers
2k views

What are the right categories of finite-dimensional Banach spaces?

This is inspired partly by this question, especially Tom Leinster's answer. Let me start with some background. I apologize that this will be rather long, since I'm hoping for input from people who ...
Mark Meckes's user avatar
  • 11.4k
6 votes
2 answers
1k views

Closed, complemented subspaces of $l^1(X)$ when $X$ is uncountable

... are all isomorphic to $l^1$ on some other index set. At least, that much I "know" from 2nd-hand sources, since the original proof is apparently in a paper of Köthe from the 1930s 1960s (in ...
Yemon Choi's user avatar
  • 25.8k
9 votes
1 answer
611 views

opposite Banach space

I heard this from Haskell Rosenthal many years ago. If V is a complex vector space, say the opposite of V is the complex vector space with the same elements, the same operations except switch scalar ...
Gerald Edgar's user avatar
  • 41.1k
21 votes
5 answers
4k views

Isomorphisms of Banach Spaces

Suppose $X$ and $Y$ are Banach spaces whose dual spaces are isometrically isomorphic. It is certainly true that $X$ and $Y$ need not be isometrically isomorphic, but must it be true that there is a ...
Mike Hartglass's user avatar

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