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3 votes
1 answer
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Aspherical amalgamations without injective maps

The situation I find myself in is as follows: I have a CW complex $X$ which is covered by two subcomplexes $A$ and $B$ and I know that $A$, $B$ and $A \cap B$ are connected and aspherical. The term ...
James Griffin's user avatar
5 votes
3 answers
411 views

Computability and complexity of computing $|Hom(G,H)|$ for finitely presented groups G, H.

In the general case, I want to say that determining $|Hom(G,H)|$ is incomputable, arguing that you could use the number to test for simplicity of a presentation, but I am new to this area and I keep ...
Edgar A. Bering IV's user avatar
6 votes
2 answers
765 views

Cup products and the transfer map

Let $G_1$ be a finite-index subgroup of $G_2$. Let $i : H^{\ast}(G_2) \rightarrow H^{\ast}(G_1)$ be the induced map of rings. There is then a transfer homomorphism $\tau : H^{\ast}(G_1) \rightarrow ...
Troy A's user avatar
  • 63
7 votes
2 answers
957 views

Computations in group cohomology

Hello, Given a finitely presentable group $G$, I'm interested in the cup-product from $H^1$ to $H^2$ with real coefficients. I want to know if this is explicitly computable (with a computer) with a ...
mister_jones's user avatar
1 vote
1 answer
156 views

Sufficient Conditions for Free Indecomposability

An interesting fact was relayed to me in another question of mine that If $M$ is any closed manifold with universal cover homeomorphic to $R^n$ for $n>1$ then $\pi_1(M)$ is freely ...
JeremyKun's user avatar
  • 726
3 votes
0 answers
423 views

Cohomologies associated to residually torsion-free nilpotent groups

This question is related to my previous question: Relationship between the cohomology of a group and the cohomology of its associated Lie algebra. A group $G$ is ${\it residually \ torsion \ free \ ...
Peter Goetz's user avatar
5 votes
2 answers
754 views

explicit linear representations of fundamental groups of surfaces

I am looking for an explicit representation of the fundamental group of a closed orientable surface of genus >1. I guess they should be abundant in degree 2. Did anyone see the explicit matrix ...
mathreader's user avatar
  • 1,050
1 vote
3 answers
553 views

Homomorphisms of the free group $F_n$ to $GL_k(\mathbb{R})$ [closed]

Is there something known about the set of all homomorphisms from the free group on $n$ generators $F_n$ to the real general linear group $GL_k(\mathbb{R})$ modulo conjugation, i.e. $$ Hom(F_n, GL_k(\...
berl13's user avatar
  • 471
28 votes
2 answers
6k views

What group is $\langle a,b \,| \, a^2=b^2 \rangle$?

In teaching my algebraic topology class, this group showed up as part of an easy fundamental group computation: $\langle a,b\mid a^2=b^2\rangle$. My first instinct was that this must be $\mathbb{Z}*\...
Greg Friedman's user avatar
4 votes
1 answer
328 views

Algebraic K-groups and braids

This is (I think) a reference request: Are there calculations of any algebraic K-groups for the (group ring of) the Artin braid groups?
Dr Shello's user avatar
  • 1,180
7 votes
1 answer
433 views

Associativity with infinite nesting

I was trying to understand the Eilenberg-Mazur swindle (which I learned about here) especially as it could be used to show that if $A, B$ are compact (topological) $n$-manifolds whose connect sum is $...
Rbega's user avatar
  • 2,299
20 votes
4 answers
3k views

Relationship between the cohomology of a group and the cohomology of its associated Lie algebra

Let $G$ be a group and let $k$ be a field (characteristic 0 if you want). Let $L$ be the graded Lie ring associated to the lower central series of $G$, that is, $L$, as a graded abelian group is $\...
Peter Goetz's user avatar
7 votes
1 answer
859 views

How commutative is Quillen's Plus-Construction?

This question is inspired by this question about the dependence of K-theory on the order of multiplication in the ring. I did not think long about it, so maybe the answer really lies on the surface; ...
Andreas Thom's user avatar
  • 25.5k
3 votes
2 answers
1k views

presentations of the trivial group

I just came across this statement in Bowditch's notes on geometric group theory that $\langle a,b\ |\ aba^{-1}b^{-2},a^{-2}b^{-1}ab \rangle$ is a presentation of the trivial group. Does anyone know if ...
Mike's user avatar
  • 31
22 votes
1 answer
1k views

Word maps on compact Lie groups

Let $w=w(a,b)$ be a non-trivial word in the free group $F_2 = \langle a,b \rangle$ and $w_G \colon G \times G \to G$ be the induced word map for some compact Lie group $G$. Murray Gerstenhaber and ...
Andreas Thom's user avatar
  • 25.5k
-1 votes
1 answer
421 views

How does the discrete group act on simplicial set level by level

Suppose that we know a discrete group acts on the geometric realization of a simplicial set. Is there some way to understand how the corresponding action works on the simplicial set? For example, if ...
Gao 2Man's user avatar
  • 681
3 votes
3 answers
1k views

Another group cohomology cup product question

I am wondering if there is a way to see the cup product, in some cases, without using cochain complexes. The situation I am interested in is the following: Let $G=F/R$ be a finitely presented group ...
Josh's user avatar
  • 1,422
8 votes
2 answers
596 views

Infinite loop space maps into or out of BAut(F_n)

There is an inclusion $S_n \to Aut(F_n)$ from the symmetric group into the automorphism group of a free group. After applying the Quillen +-constriction, both $BS_{\infty}$ and $BF_{\infty}$ become ...
Romeo's user avatar
  • 2,734
7 votes
2 answers
537 views

Residually finite + torsion free + finite index = finite complex?

Suppose $G$ is a residually-finite group and $H < G$ a torsion-free subgroup of finite index. What characterizes such $G$ such that $BH$ is homotopic to a finite complex? I believe Serre showed ...
Romeo's user avatar
  • 2,734
11 votes
9 answers
1k views

Proving the impossibility of an embedding of categories

A number of topological invariants take the form of functors $\mathscr{T}\to\mathscr{G}$, where $\mathscr{T}$ is the category of all topological spaces and continuous functions, and $\mathscr{G}$ is ...
Daniel Miller's user avatar
8 votes
1 answer
1k views

Beyond an intro to topological graph theory...

I'm looking to find out what active areas of research there are in topological graph theory, particularly those that interface strongly with other areas of math (say, group theory, algebraic topology, ...
Dr Shello's user avatar
  • 1,180
2 votes
2 answers
617 views

Comparing lower central series and augmentation ideal completions

Let G be a group. Let $G^p$ be the completion of G with respect to the mod p lower central series of G.i.e. $G^p=\varprojlim_{q} G/\gamma_qG$, where $\gamma_qG$ is generated by all $\{[x_1,\cdots,x_s]^...
user avatar
11 votes
2 answers
843 views

covers of $Z^\infty$

Is it possible to cover $Z^\infty$ (the infinite direct sum of $Z$'s with the $l_1$-metric) by a finite set of collections of subsets $U^0,...,U^n$ such that each collection $U^i$ consists of ...
user avatar
15 votes
3 answers
14k views

How to demonstrate $SO(3)$ is not simply connected?

A quote from Wikipedia's article on the Rotation group: Consider the solid ball in $\mathbb{R}^3$ of radius $\pi$ [...]. Given the above, for every point in this ball there is a rotation, ...
Brinjal's user avatar
  • 153
10 votes
1 answer
635 views

Self-homomorphisms of surface groups

Let $X$ be a closed, orientable surface of genus at least 2, and let $\phi: \pi_1(X) \to \pi_1(X)$ be a surjective homomorphism. Is $\phi$ necessarily injective?
Lucas Culler's user avatar
25 votes
3 answers
2k views

Are fundamental groups of aspherical manifolds Hopfian?

A group $G$ is Hopfian if every epimorphism $G\to G$ is an isomorphism. A smooth manifold is aspherical if its universal cover is contractible. Are all fundamental groups of aspherical closed smooth ...
Sergei Ivanov's user avatar
2 votes
1 answer
2k views

Is a normal subgroup of a finitely presented group finitely generated or normal finitely generated?

Let $G$ be a finitely presented group and $N$ a normal subgroup. Is $N$ finitely generated or normally finitely generated? Here normally finitely generation means that for some finite set $S$ of ...
yeshengkui's user avatar
  • 1,373
3 votes
3 answers
6k views

Homology of Surfaces with Holes

The classification theorem for surfaces says that the complete set of homeomorphism classes of surfaces is { $S_g : g \geq 0$ } $ \cup$ { $N_k : k \geq 1$ }, where $S_g$ is a sphere with $g$ ...
Tony Huynh's user avatar
  • 32.1k
7 votes
1 answer
672 views

How does this geometric description of the structure of PSL(2, Z) actually work?

There is a beautiful way to see that the congruence subgroup $\Gamma(2)$ is free on two generators: the action of $\Gamma(2)$ on $\mathbb{H}$ is free and properly discontinuous, and there is a modular ...
Qiaochu Yuan's user avatar
62 votes
9 answers
9k views

Fundamental groups of noncompact surfaces

I got fantastic answers to my previous question (about modern references for the fact that surfaces can be triangulated), so I thought I'd ask a related question. A basic fact about surface topology ...
Andy Putman's user avatar
  • 44.8k
22 votes
6 answers
2k views

Is any interesting question about a group G decidable from a presentation of G?

We say that a group G is in the class Fq if there is a CW-complex which is a BG (that is, which has fundamental group G and contractible universal cover) and which has finite q-skeleton. Thus F0 ...
Chad Groft's user avatar
  • 1,219
28 votes
4 answers
4k views

Classifying Space of a Group Extension

Consider a short exact sequence of Abelian groups -- I'm happy to assume they're finite as a toy example: $$ 0 \to H \to G \to G/H \to 0\ . $$ I want to understand the classifying space of $G$. Since ...
Aaron Bergman's user avatar
16 votes
7 answers
2k views

two conjugate subgroups and one is a proper subset of the other? plus, a covering space interpretation.

Recently I've been reading J.P. May's A Concise Course in Algebraic Topology. In the section on the classification of covering groupoids, he mentions that sometimes a group G may have two conjugate ...
Aaron Mazel-Gee's user avatar
5 votes
2 answers
666 views

HNN extensions which are free products

which HNN-extensions are free products? this question is related with another still unsolved about Nielsen-Thruston-reducibility and connected-sum-irreducibility of 3d-torus- bundles...
janmarqz's user avatar
  • 345
23 votes
9 answers
4k views

What methods exist to prove that a finitely presented group is finite?

Suppose I have a finitely presented group (or a family of finitely presented groups with some integer parameters), and I'd like to know if the group is finite. What methods exist to find this out? I ...
Gabe Cunningham's user avatar
24 votes
3 answers
4k views

Subgroups of free abelian groups are free: a topological proof?

There is a well-known topological proof of the fact that subgroups of free groups are free. Many people, myself included, think it is easier and more natural than the purely algebraic proofs which ...
Pete L. Clark's user avatar
21 votes
8 answers
4k views

Cogroup objects

Pretty much anyone who does algebra is familiar with group objects in categories, but what about cogroup objects? Most of what I've been able to find about them is that they "arise naturally in ...
Charles Siegel's user avatar
21 votes
5 answers
1k views

Explanation for E_8's torsion

To study the topology of Lie groups, you can decompose them into the simple compact ones, plus some additional steps, such as taking the cover if necessary. After that, the structure of $SO(n)$'s is ...
Ilya Nikokoshev's user avatar

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