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Field extensions and completions at possibly infinite places

In Serre's Corps Locaux, Chapter 2 §3, is presented a classical proof. We are in an "ABKL" setup, where $K/L$ is finite, $A$ is Dedekind, $B$ is the integral closure of $A$ and $B$ is $A$-...
Adrien Zabat's user avatar
10 votes
1 answer
243 views

If $E_\text{sep}/F$ is normal, then must $E/F$ be normal?

This question has been asked in Math.StackExchange (see here) for more than a week and I even put a bounty on it. But still it hasn't been correctly answered (the current answer there was written by ...
Z Wu's user avatar
  • 452
3 votes
0 answers
114 views

English translation of Borel-Serre's "Théorèmes de finitude en cohomologie galoisienne"?

Is there an English translation of this text, or at least some English language paper that proves the same results? I especially need a proof of the following fact which is in this paper: Say $k$ is a ...
user2945539's user avatar
1 vote
0 answers
88 views

When does sum of algebraically independent polynomial become dependent?

Given $f_1,...,f_n \in \mathbb{F}[x_1,...,x_n]$ where $f_n = g + h$. Suppose the sets $\{ f_1,...,f_{n-1},g \}$ and $\{ f_1,...,f_{n-1},h \}$ are algebraically independent then is there a ...
Rishabh Kothary's user avatar
0 votes
0 answers
184 views

Degree 6 Galois extension over $\mathbb{Q} $

Let L be the splitting field of $ x^3- 2$ over $ \mathbb{Q}$. Then $ G=\operatorname{Gal}(L/K) \cong S_3$. Let $\sigma\in G$ such that the fixed field of $ \sigma$ is $\mathbb{Q}(2^{1/3})$. Let $x,y\...
Sky's user avatar
  • 923
8 votes
1 answer
639 views

A question on algebraic independence

Let $f_1,f_2,\ldots,f_n, g \in \mathbb{F}_q[x_1,...,x_m]$. Assume that $f_1,\ldots,f_n$ vanish at $0$, so that $\mathbb{F}_q[[f_1,...,f_n]]$ is a subring of $\mathbb{F}_q[[x_1,...,x_n]]$. Suppose that ...
Rishabh Kothary's user avatar
1 vote
1 answer
100 views

Existence of a symmetric matrix satisfying certain irreducible conditions

Let $K$ be a field such that $ \mathrm{char}(K) \neq 2 $. Let $ p(x) $ be an arbitrary irreducible polynomial over $K$ of degree $n$. Using the rational canonical form, we can always construct an $ n ...
Sky's user avatar
  • 923
0 votes
1 answer
147 views

Existence of linear disjointness between an algebraic number field and $p$-cyclotomic field over $ \mathbb{Q}$

Suppose $ K $ be an algebraic number field and $ n $ be an even integer. Is it possible to find atleast one $ p $ such that $ p\equiv 1( \text{mod}~ n)$ and $ \mathbb{Q}(\eta_p) $ is linearly disjoint ...
Sky's user avatar
  • 923
6 votes
1 answer
245 views

If degree $N$ polynomials always have a root, does there still exist an irreducible polynomial of degree $N+1$?

Given that $F$ is a field, let $F_n$ be the completion of $F$ with respect to roots of degree $n$ polynomials. For example this would make $\mathbb{Q}_2$ the field of (ruler and compass) constructible ...
Sam Forster's user avatar
3 votes
1 answer
1k views

irreducibility of the polynomial $ x^4 +1 $

Let $K$ be a field. We consider the polynomial $f(x) = x^4 + 1$. It is known that $f(x)$ is irreducible over $\mathbb{Q}$ but reducible over any finite field. Thus $ f(x)$ is reducible over any field $...
Sky's user avatar
  • 923
6 votes
1 answer
533 views

Construction of a symmetric polynomial in the roots that acts like the discriminant

The discriminant $\Delta(P)$ of a monic polynomial $P(x)=x^n + a_{n-1} x^{n-1} + \dotsb + a_0$ of degree $n$, when expanded (using elementary symmetric polynomials), is a symmetric polynomial of ...
rgvalenciaalbornoz's user avatar
6 votes
2 answers
329 views

Algebraic numbers which prescribed degree which does not belong to some fields

In my research it would be great if the following result is valid. In what follows, $\overline{\mathbb{Q}}$, $\overline{\mathbb{Q}}_n$ and $\overline{\mathbb{Q}}_{<n}$ denotes the set of algebraic ...
Jean's user avatar
  • 515
10 votes
0 answers
452 views

What does Hilbert's 90 theorem tell us about Galois fixed points in projective space?

Consider the following statement: If $K\subseteq L$ is a Galois extension of fields with Galois group $G$ and $x \in \mathbb{P}^n(L)$ is such that $\sigma(x)=x$ for all $\sigma\in G$, then $x \in \...
Gro-Tsen's user avatar
  • 32.5k
4 votes
0 answers
212 views

Reference request: Radicial morphisms & Jacobson-Bourbaki correspondence

My name is Chemy (Przemysław). I am a PhD student at UvA (Amsterdam), and I work on projects related to foliations in algebraic geometry in positive characteristic. Therefore I am avidely reading two ...
P. Grabowski's user avatar
2 votes
0 answers
312 views

Degree $8$ cyclic extension over $\mathbb{Q}$

Actually I am interested in degree $ 8 $ cyclic extension over $ \mathbb{Q} $. Let $ L $ be such extension. At first I was thinking to take basis as normal basis, as we can determine the galois group ...
Sky's user avatar
  • 923
0 votes
0 answers
112 views

Existence of a subspace of having no isotropic 2-plane

Let $V$ be a vector space of dimension $n$ over the field $\mathbb {Q} $. A subspace $W$ is isotropic for a skew-bilinear form $\alpha$ on $V$ if $\alpha(x,y) = 0$ for all $x,y \in W$. More ...
Sky's user avatar
  • 923
5 votes
2 answers
243 views

Restricting maps between strict henselisations

$\require{AMScd}$I am currently thinking about (strict) henselisations but I don't know too much literature about the topic. So I am wondering if there is a natural way to restrict maps between strict ...
Snow bunting's user avatar
1 vote
0 answers
64 views

Resolvent is minimal polynomial for universal splitting algebra

Given a degree $n$ monic $f\in A[x]$ write $\mathrm{Split}_Af$ for its universal splitting algebra, constructed by taking the quotient of $A[x_1,\dots ,x_n]$ by the Vieta formulas. This is the initial ...
Arrow's user avatar
  • 10.5k
1 vote
2 answers
368 views

How to show an invariant subfield of rational function field $\mathbb{Q}(x)$ under a certain group action is actually a simple extension? [duplicate]

Let $K=\mathbb{Q}(x)$ be the rational functions in one variable $x$ and let the automorphisms $\phi,\psi$ of $K$ be defined as $\phi(x)=-\frac{1}{x+1}$ and $\psi(x)=\frac{1}{x}$. Let $G$ be the group ...
user avatar
2 votes
0 answers
221 views

Field whose absolute Galois group is $\mathbb{Z}_p$

Let $L$ be a perfect field. Assume there is an algebraic closure $L\subset \overline{L}$ and a prime $p$ such that $\mathrm{Gal}(\overline{L}/L)\cong \mathbb{Z}_p$ as topological groups. Is there a ...
klmntn's user avatar
  • 53
0 votes
2 answers
757 views

Splitting field of an intermediate field

Consider the following 'wrong' question. Let $f(x) \in F[x]$ be an irreducible polynomial in a polynomial ring of a field $F$. Let $L$ be the splitting field of $f(x)$ over $F$. Assume that $L$ is a ...
seoneo's user avatar
  • 103
2 votes
1 answer
166 views

On a special type of subring of $\mathbb C[x_0,...,x_{q-1}]$

Let $p,q$ be odd primes. Consider the polynomial ring $\mathbb C[x_0,...,x_{q-1}]$. For $m=0,1,...,p-1$, let $$\sigma_m=\sum_{0\le j_0\le p;...;0\le j_{q-1}\le p; j_1+...+j_{q-1}=p; 1.j_1+...+(q-1)...
user521337's user avatar
  • 1,209
2 votes
0 answers
27 views

Does the $G$-norm coincide with the ordinary norm for "quasi-$G$-Galois" extensions

Let $S$ be a commutative ring, let $G$ be a finite group acting on $S$ via automorphisms (not necessarily faithfully), and let $R$ be a subring of $S$ consisting of elements fixed $G$. The extension $...
Uriya First's user avatar
  • 2,928
18 votes
1 answer
987 views

Why does $E\otimes_KE\cong EG$ imply that Galois theory works?

This is a part of statement in the book I do not fully appreciate. Suppose $E/K$ is Galois extension and $G$ the Galois group of $E/K$. $E[G]$ is the group ring formed by finite group $G$. "It is ...
user45765's user avatar
  • 299
6 votes
2 answers
815 views

Why is $K_{\upsilon}|K$ separable for a global field $K$?

I asked this question on math.stackexchange but maybe it fits here better. If not, I apologize in advance and will remove the question. Let $K$ be a global field and $\upsilon$ a prime of $K$. Then ...
Frida's user avatar
  • 111
2 votes
0 answers
171 views

residue fields of smooth $\mathbf{Q}$-algebras

Let $A$ be a $\mathbf{Q}$-algebra. We say $A$ is "residually abelian", if there exists a maximal ideal $\mathfrak{m}$ of $A$ whose residue field $\kappa(\mathfrak{m})$ is a Kummer extension of an ...
user avatar
2 votes
1 answer
485 views

Extending commuting automorphisms of a field

I have a field $L$ and two field automorphisms $f, g: L \to L$ such that $f \circ g = g \circ f$. Under what conditions can they be extended to automorphisms of an extension $K \mid L$ that still ...
Pablo Zadunaisky's user avatar
1 vote
0 answers
128 views

Nielsen--Schreier for fields

Is it true that a subextension of a purely transcendental extension is itself purely transcendental? In symbols, suppose we have field extensions $M/L/K$, with $M/K$ purely transcendental. Must $L/K$ ...
Sean Eberhard's user avatar
1 vote
0 answers
36 views

Quadratic suborders of an imprimitive quartic order

Let $Q$ be an irreducible quartic order; that is, $Q$ is a subring of the ring of integers $\mathcal{O}_K$ in a quartic extension $K$ over $\mathbb{Q}$ such that the fraction field of $Q$ is equal to $...
Stanley Yao Xiao's user avatar
28 votes
4 answers
4k views

What are traces?

Let $A$ be a Noetherian commutative ring and Let $A\rightarrow B$ be a finite flat homomorphism of rings. We can thus form the so called "trace" $\mathrm{Tr_{B/A}}:B\rightarrow A$, which is a ...
Anonymous Coward's user avatar
2 votes
0 answers
192 views

Existence of "splitting objects" and algebraic closures

Definition 0. Let $(\mathbf{C},U)$ denote a concrete category. Let "splits" be a desirable property that pointed $\mathbf{C}$-objects may or may not satisfy. Let $(X,x)$ be a pointed $\mathbf{C}$-...
goblin GONE's user avatar
  • 3,793
11 votes
1 answer
2k views

Galois theory for products of fields (aka finite etale extensions)

Let $F$ be a field. By a Galois algebra over $F$ I mean a finite etale extension, that is, a product $K = K_1 \times \cdots \times K_r$ of finite (separable) field extensions, of total degree $[K : F]...
Evan O'Dorney's user avatar
5 votes
1 answer
339 views

Can completely multiplicative functions be extended to $\overline{\mathbb{Q}}$ or further?

I'm looking for a subject of study that handles the following question. I'm not the most familiar with algebra; I have a strong working knowledge and that's about it, but I've been considering ...
user avatar
1 vote
0 answers
81 views

Geometry of componentially locally strongly separable algebras

Janelidze's categorical Galois theory yields, for nice adjunctions, a good notion of covering morphism. The category of finitely affine schemes admits such an adjunction into the category of ...
Arrow's user avatar
  • 10.5k
20 votes
2 answers
1k views

Automorphisms of the hyperreals over the rationals and nontrivial automorphism groups

A classic result says the automorphism group of $\mathbb{R}$ (over $\mathbb{Q}$) is trivial. The proof is simple: every automorphism preserves squares, and hence fixes the positive reals, so it must ...
Brian Pinsky's user avatar
-2 votes
1 answer
151 views

Quadratic extension and prime ideals

Let $B/A$ be a quadratic Galois extension between local domains. Define ${\mathrm{Gal}}(B/A) = \{e,\sigma\}$. Choose two prime ideals ${\frak P}_1, {\frak P}_2$ of $B$ such that ${\frak P}_2 = {\...
Pierre MATSUMI's user avatar
0 votes
1 answer
232 views

Inverse Galois Problem ; Galois group of some branched cover of $P^{1}$ defined over $\mathbb{Q}$

I was trying to read a paper on Inverse Galois problem . I understands what the inverse Galois problem is. It asks if every finite group is the Galois group of some extension of the rationals. The ...
Tensor_Product's user avatar
12 votes
0 answers
3k views

Algebraic Closure of the field of rational functions

Using the theorem of Puiseux, one concludes that the algebraic closure of $\mathbb C(X)$ is the set of algebraic elements (over $\mathbb C(X)$) of the algebraic closure of $\mathbb C((X))$, which is $\...
Z.A.Z.Z's user avatar
  • 1,891
3 votes
2 answers
243 views

Minimal fields of isomorphism for varieties

Let $V$ be an algebraic variety over a field $K$. Is there a constant $d = d(V) \in \mathbb{N}$ such that for any variety $W$ defined over $K$ and isomorphic to $V$ over the algebraic closure of $K$, ...
Pablo's user avatar
  • 11.3k
6 votes
1 answer
760 views

Complexity of computing the Galois group

There has been some discussion of computing the Galois group of a polynomial over the integers, but I can't seem to find any results, or even a question of what the complexity of this might be. For ...
Igor Rivin's user avatar
  • 96.4k
2 votes
0 answers
60 views

lift isomorphic in a sufficiently thick fiber

Let $P$ and $P'$ two polynomials in $k[[\pi]][t]$ for an algebraically closed field $k$ and let $A=k[[\pi]]$. We consider $ X'=Spec (A[t]/(P'))$ and $X=Spec (A[t]/(P)$. Let $d=val(\Delta(P))$ where $\...
prochet's user avatar
  • 3,472
2 votes
0 answers
173 views

On Artin-Hironaka lemma and Galois theory

Let $A=k[[t]]$ Let $B$ a flat $A$-finite algebra which is etale and Galois at the generic point. Then by Artin lemma 3.12 (ii) in his IHES paper on approximation, we know that there exists an integer ...
prochet's user avatar
  • 3,472
0 votes
0 answers
245 views

Notation Problem, Fixed Rings and Fields

I am trying to make sense of the notation and certain sets in two articles by Annick Valibouze whose results I'm using for my bachelor's thesis, I hope it's relevant enough to merit an answer. In one ...
Erik Vesterlund's user avatar
10 votes
2 answers
2k views

why are subextensions of Galois extensions also Galois?

Generally a Galois extension is defined to be an algebraic extension that is also normal & separable. It is then shown that in the sequence of field extensions $L|M|K$ if $L|K$ is Galois then $L|M$...
Mozibur Ullah's user avatar
8 votes
1 answer
4k views

Example of an algebraic number of degree 4 that is not constructible

The number $b:=\frac{\sqrt{2a}+\sqrt{4\sqrt{a^2-3}-2a}}{2}$ with $a:=\frac{\sqrt[3]{18+2\cdot\sqrt{65}}}{2}+\frac{2}{\sqrt[3]{18+2\cdot\sqrt{65}}}$ is a root of the irreducible polynomial $x^4-6x+...
Joel Adler's user avatar
2 votes
1 answer
652 views

Searching for polynomials with squarefree discriminant

In connection with the Galois theoretic results surrounding the irreducibility of $f(x)= x^{N}-x-1$ over $\mathbb{Q}$, I've been trying to prove for a while that the discriminant of $f$ is actually ...
Cosmin Pohoata's user avatar
11 votes
2 answers
3k views

Is there an alternative formula for solving cubic equations?

It is known that Cardano's formula for solving cubic equations is not good in the case of positive discriminants. In this case it expresses the solution through cubic roots of complex numbers. ...
Ruslan_Sharipov's user avatar
15 votes
3 answers
4k views

Elementary Luroth theorem proof?

Hi, everyone! I'm trying to explain the proof of Luroth theorem (every field $L$, s.t. $K\subset L\subset K(t)$, is isomorphic to $K(t)$) to the high-school audience. I'm not going to use such ...
zroslav's user avatar
  • 1,422
3 votes
0 answers
603 views

Norms in Galois extensions

Let $k$ be a field of characteristic 0, and $\overline k$ be a fixed algebraic closure of $k$. Let $k\subset F\subset E$ be a tower of finite Galois extensions in $\overline k$, where both $\mathrm{...
Mikhail Borovoi's user avatar
24 votes
4 answers
4k views

Is there a Galois correspondence for ring extensions?

Given an ring extension of a (commutative with unit) ring, Is it possible to give a "good" notion of "degree of the extension"?. By "good", I am thinking in a degree which allow us, for instance, to ...
Mauricio's user avatar
  • 1,415