All Questions
1 question
1
vote
0
answers
276
views
Does the Hochschild cohomology of an $A_{\infty}$-algebra have an algebra structure?
For an algebra $A$ we can define its Hochschild cohomology (see this Wikipedia page) $HH^{\cdot}(A,A)$. It is well-known that the cup product makes $HH^{\cdot}(A,A)$ a (graded-commutative) algebra.
...
- 9,019