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19 votes
6 answers
3k views

Diffeomorphism of 3-manifolds

Surgery theory aims to measure the difference between simple homotopy types and diffeomorphism types. In 3 dimensions, geometrization achieves something much more nuanced than that. Still, I wonder ...
Tim Perutz's user avatar
  • 13.2k
13 votes
2 answers
534 views

Heegaard splitting of covering hyperbolic manifold.

I am curious about how the Heegaard genus changes after a finite covering. Is there anyone constructing an closed hyperbolic 3-manifold $N$ such that the Heegaard genus of a finite covering of $N$ ...
yanqing 's user avatar
9 votes
1 answer
605 views

Mapping Class Groups and torus (JSJ) decomposition of closed 3-manifolds

I am wondering if some intuitive relation exists between Mapping Class Group (MCG) of a 3-manifold (assume "simple" enough manifolds: closed,compact,irreducible, orientable, non-hyperbolic) and its ...
SKShukla's user avatar
  • 231
6 votes
1 answer
1k views

Dehn surgery on handlebody

Assume $V$ is a handlebody and $C$ be a simple closed curve contained in the interior of $V$. As Sam said, there exists some simple closed curve such that every dehn surgery along it produces a ...
yanqing 's user avatar
6 votes
1 answer
324 views

Computation of $\pi_1$ for a Mazur manifold and its boundary

If we attach a $4$-dimensional $1$-handle $D^1 \times D^3$ to a $4$-dimensional $0$-handle $B^4$, we obtain $S^1 \times D^3$. The null homologous knot in $S^1 \times S^2$ indicated in the picture ...
Max Schumann's user avatar
4 votes
2 answers
536 views

Explicit tetrahedralizations of closed 3-manifolds and connections between convex polytopes and hyperbolic knot complements

There are three consistent ways to glue opposite faces of a dodecahedron to get a closed 3-manifold. With a $\frac{1}{10}$ twist we receive the Poincaré dodecahedral space, with a $\frac{3}{10}$ twist ...
Samuel Reid's user avatar
  • 1,441
3 votes
3 answers
769 views

Reducible 3d torus bundles

Here reducible means that the mapping class for the fiber is a reducible auto-homeomorph in the sense of Nielsen-Thruston. So, could anyone give me a hint to classify them? In contrast, do you agree ...
janmarqz's user avatar
  • 345
2 votes
2 answers
552 views

Is the following 3-manifold irreducible?

We start with product manifold $ X := S_g \times (0,1)$, where $S_g$ is a closed, orientable surface of genus $g \geq 1$. Since this has $\mathbb R^3$ as its universal cover, $X$ is irreducible. Now $...
H1ghfiv3's user avatar
  • 1,255