Suppose we have a joint distribution $P(D,X,L) = P(D|X)P(X|L)P(L)$. Here, D and L are discrete but X is a continuous random variable. I want to compute $P(D=d)$. How do I do this numerically? The fact that $X$ is continuous confuses me.
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$\begingroup$ A little bit more complicated version of this problem is at mathoverflow.net/questions/97999/…. Comments/answers needed. $\endgroup$– eakbasMay 26, 2012 at 2:15
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I'm assuming that your "continuous" is actually "absolutely continuous", i.e. $X$ has a density.
$$P(D=d) = E[P(D=d|X)] = \int dx \ P(D=d|X=x) f_X(x) = \int dx \sum_\ell \ P(D=d|X=x) f_{X|L}(x|\ell) P(L=\ell)$$
where the sum is over the possible values of $L$, and $f_{X|L}(x|\ell)$ is the conditional density of $X$ given $L=\ell$.
answered May 25, 2012 at 18:14