Let $G_1$ and $G_2$ be groups and let $M$ be a vector space equipped with actions of $G_1$ and $G_2$. The free product $G_1 \ast G_2$ thus acts on $M$. How can one compute the twisted group homology $H_{\ast}(G_1 \ast G_2;M)$ in terms of $H_{\ast}(G_1;M)$ and $H_{\ast}(G_2;M)$? Since I doubt that $H_{\ast}(G_1;M)$ and $H_{\ast}(G_2;M)$ are enough to completely determine $H_{\ast}(G_1 \ast G_2;M)$, I guess my question more precisely is what additional information is needed?
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