coarse moduli space and $\pi_0$ I've been reading this really nice paper by Alper http://math.columbia.edu/~jarod/good_moduli_spaces.pdf, and there's a question that doesn't seem to be answered (perhaps it's not relevant).
Any stack F has a corresponding `sheaf of connected components' (or sheaf of isomorphism classes), by taking $\pi_0^{pr}(F)(S) = \pi_0 (F(S))$ and then sheafifying. (where $\pi_0$ of a groupoid, or more generally a category, is the set of isomorphism classes)
If $X$ is an Artin stack (although I'm currently more interested in DM stacks) and $X$ admits a good moduli space, then is $X \to \pi_0(X)$ a good moduli space?
Also, when is the good moduli space a scheme (and not just an algebraic space)?
And finally, if $X$ = $Spec R$ is affine and $G$ acts on it (I'm mainly interested in the $G$ finite case), is $\pi_0([X/G]) = Spec R^G$? 
 A: You have probably already come up with the answer yourself, but I just thought the question shouldn't
hang around unanswered in the forum.
What you call "the sheaf of connected components", I would call the coarse sheaf of the stack or the 
sheaf associated to the stack. It is usually not representable by an algebraic space. When it is,
the stack is called a gerbe and the map to the coarse sheaf is called the structure morphism of the gerbe.
A gerbe with structure morphism $X \to Y$ is fppf locally on $Y$ of the form $B_YG := [Y/G]$, where $G$ is
a group-algebraic space which is fppf over $Y$, and the action on $Y$ is trivial.
(In fact, it is even étale locally on this form, since the structure morphism $X \to Y$ of a gerbe is smooth.)
Although gerbes certainly have at lot of good properties, the structure morphisms of a gerbe need not be a
good moduli space in the sense of Alper. It is, exactly when $G$ above is linearly reductive.
The property of being a gerbe as a very strong property. Thus good (or a coarse) moduli spaces
are seldom coarse sheaves. In particular $Spec\ R^G$ will usually not be the coarse sheaf of $[Spec\ R / G]$.
Taking the stack quotient and then taking the associated sheaf, is the same as taking the sheaf quotient
directly. The result is seldom (never?) representable unless the action of $G/N$ is free, where $N$ is the kernel
of the action.
