I've asked this question at stat-exchange and at the "Semnet"-mailing list of professionals in statistics. The reference to some articles in Psychometrica (for instance ten Berge 1995, Jennrich 2001) were insofar helpful, that I saw, that reasons for nonsuccessful rotation were handled - but the explicite statement, whether the iteration with plane-wise rotations using the Varimax- or Quartimax-criterion is always converging /can always be made converging was not made/referred to. (This is different for instance for the case of using the principal components-criterion, for which I think I've come across an explicite proof ~20 years ago).
The reason to ask this is an approach to the Hadamard-matrix-problem: the Hadamard-matrix is defined to consist of entries +1 and -1 only and being orthogonal.
Being orthogonal means to have the form of a rotation-matrix, simply scaled by one scalar factor such that all entries have the desired value -1 or +1. That means, the variance of the squared entries is zero. So if I begin with any initial rotation-matrix, and rotate to minimal (instead of maximal) variance using the inverse of the "varimax" or of the "quartimax"-criterion, say "varimin" or "quartimin", I should arrive at a proper Hadamard-matrix, scalar scaled by the reciprocal of the square of the number of rows/columns.
Indeed this works for small sizes (up to n=20, so nxn=20x20) and "sometimes" for n=24, but then the Hadamard-form is found extremely seldom.
Ten Berge (1995) gave insight in the rotation procedure, noting, that sometimes convergence is not reached because of systematic missing of optimization of some planes in the iterative process, but which might be overcome by some workaround. The global convergence question however was not explicitely mentioned as solved.
Question: is a proof for the convergence to the global optimum by the iterative, plane-wise rotation using the quartimax/varimax-rotation known? Or is it known, that it does not always converge?) (If it is simple enough it might be done here, or else a reference were good. I've it -surprisingly- not seen in the monographies on factor analysis of for instance S.Mulaik(74) or K.Überla(68) .
(This "varimin"-rotation-approach to the Hadamard-matrix problem has its further charme, because it is also applicable to matrices which have other dimensions than n=4*m, and is thus some more general formulation/notion for that problem: "the lower bound for the variance of the squared entries of orthogonal matrices of size nxn where n=4m is zero" )
Examples
//commands in "Matmate" to reproduce the approach
n=8
A = gettrans(randomu(n,n),"drei") // creates a random rotation-matrix in A
A = sqrt(n) * A // rescales it with the scalar sqrt(n)
T = gettrans(A,"-varimax") // gets the rotationmatrix T which rotates A
// using the optimization criterion "Varimin"
H = A * T // gets the Hadamardmatrix of size 8x8
// by column-rotation
$\qquad \small \text{ A =} \begin{array} {rrrrrrrr} 0.95& 0.24& 1.32& 0.34& -0.87& -1.08& 1.54& -0.94\\\ 1.45& 0.06& -1.03& -0.57& 1.71& -0.41& 0.05& -1.19\\\ 1.29& -0.91& -0.50& 1.41& -0.98& 1.29& -0.54& -0.59\\\ 1.02& 1.14& -1.36& 0.36& -0.67& -0.75& 0.35& 1.60\\\ 0.53& -0.28& 1.21& 1.36& 1.14& -0.97& -1.14& 0.86\\\ 0.20& 1.76& 0.72& 0.57& 0.87& 1.69& 0.62& 0.13\\\ 0.64& 1.26& 0.62& -1.03& -0.92& -0.11& -1.84& -0.57\\\ 1.26& -1.03& 0.85& -1.48& 0.08& 0.78& 0.36& 1.31 \end{array} $
and the Hadamardmatrix H
$\qquad \small \text{ H =} \begin{array} {rrrrrrrr} -1.00& -1.00& 1.00& 1.00& -1.00& -1.00& 1.00& -1.00\\\ 1.00& -1.00& -1.00& -1.00& 1.00& -1.00& 1.00& -1.00\\\ 1.00& -1.00& -1.00& 1.00& -1.00& 1.00& -1.00& -1.00\\\ 1.00& 1.00& -1.00& 1.00& -1.00& -1.00& 1.00& 1.00\\\ 1.00& -1.00& 1.00& 1.00& 1.00& -1.00& -1.00& 1.00\\\ 1.00& 1.00& 1.00& 1.00& 1.00& 1.00& 1.00& -1.00\\\ 1.00& 1.00& 1.00& -1.00& -1.00& -1.00& -1.00& -1.00\\\ 1.00& -1.00& 1.00& -1.00& -1.00& 1.00& 1.00& 1.00 \end{array} $
For a dimension not a multiple of 4 we do not get the variance of the
squares of the matrix-entries to equal zero but I think, we get the solution
of minimal variance, and the squares of the entries are not 1.
Example n=6:
$\qquad \small
\text{ A =} \begin{array} {rrrrrr}
1.00& 1.29& 1.32& -1.10& 0.33& 0.52\\\
0.48& 0.23& 1.14& 1.56& -1.39& -0.22\\\
1.51& -1.51& -0.08& 0.09& 0.12& 1.18\\\
1.38& 0.62& -1.39& -0.40& -0.85& -0.94\\\
0.74& -0.32& 0.49& 0.63& 1.55& -1.52\\\
0.21& 1.22& -0.88& 1.34& 0.89& 1.04
\end{array}
$
and
$\qquad \small
\text{ H =} \begin{array} {rrrrrr}
0.00& 1.10& 1.10& -1.10& 1.10& 1.10\\\
1.10& 1.10& 1.10& 1.10& -1.10& 0.00\\\
1.10& -1.10& -0.00& -1.10& -1.10& 1.10\\\
1.10& 1.10& -1.10& -1.10& 0.00& -1.10\\\
1.10& -1.10& 1.10& 0.00& 1.10& -1.10\\\
1.10& -0.00& -1.10& 1.10& 1.10& 1.10
\end{array}
$
where the nonzero entries are exactly $\small \pm \sqrt{6 / 5} $
[update] For the n=6-case I've got one alternate solution, which is not optimal but which is stationary under the varimin/quartimin-criterion. This is
$\qquad \small \text{ H =} \begin{array} {rrrrrr} 0.75580438&0.75580439&1.32408152&1.12540822&-1.12540822&-0.75580438\\\ 1.32408152&-1.12540822&-0.75580438&0.75580439&-0.75580438&1.12540822\\\ 1.12540822&-1.32408152&0.75580439&-0.75580438&0.75580438&-1.12540822\\\ 1.12540822&1.12540822&0.75580438&-0.75580438&0.75580439&1.32408152\\\ 0.75580439&0.75580438&-1.12540822&-1.32408152&-1.12540822&-0.75580438\\\ 0.75580438&0.75580438&-1.12540822&1.12540822&1.32408152&-0.75580439 \end{array} $
This is just plain vanilla-"varimin", I did not yet include the ten Berge-workaround here.