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What is the quasi-hereditary cover of a quasi-hereditary algebra?

Is the algebra A somehow (always) a quasi-hereditary cover of itself? Or is their a relation to Ringel duality in some way?

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  • $\begingroup$ Do you already know R. Rouquier, q-Schur algebras and complex reflection groups? $\endgroup$ Nov 8, 2011 at 15:24
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    $\begingroup$ Yes, any quasi-hereditary algebra is a cover of itself tautologically. Ringel duality has nothing to do with it. $\endgroup$
    – Ben Webster
    Nov 8, 2011 at 16:36
  • $\begingroup$ Thanks Ben (and Martin) that's what I thought it should be - very helpful. I'd like to give you the "reputation points" but don't understand how this works. $\endgroup$ Nov 8, 2011 at 17:00

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