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Q: What is the area of rectangle with a length of 6 and a width of 5 feet?

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The area of the rectangle is 72 square feet

The area of a rectangle is length x width.

Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63

The width is 6 feet. The length is 8 feet.

The length is 7 feet and the width is 5 feet

Area of a rectangle = length * width = 72 feet-squared

The width is 16 feet

width=16 and length=20

area of rectangle=120 square feet

Area = length x width, so the area of this rectangle would be 15 feet x 9 feet which equals 135 square feet.

width is 5 feet

The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.

If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.

area = length x width width = area/length 16/8 = 2 feet

Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet

Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet

48 feet. You just multiply the width times the length.

The area of a rectangle is the length times the width. In this case, 15' x 9' = 135 ft2.

area = length x width = 125 x 50 = 6250 square feet

Area = Length * Width so Width = Area / Length = 72 sq feet / 12 feet = 72/12 feet = 6 feet.

Area is length times width: 140 square feet.

Convert all unit length (width and length) to feet and then find the area (width * length) as normal.

(8x5)-(7x4)=12cubic feet

Area=length x width, A=lxw=10ft x 12ft=120ft2

Area of a rectangle = (length) times (width) = 10-ft x 12-ft = 120 square feet