About the asymptotics of LCM Let $g(x,c)$ be a uniformly random integer in the range $(x,x+c)$ and $LCM[x_1,x_2...x_i]$  the lowest common multiple of the integers $x_i$.
A) Does the limit of (the asymptotics of $LCM[g(3^1,c),g(3^2,c),...,g(3^x,c)]$ as $x→∞$) as $c→∞$ exist?
B) How to find the limit of A) if it exists ?
C) Given any strictly increasing unbounded function $f(n)>O(n)$, how to find the asymptotics of $LCM[g(f(1)),g(f(2))...g(f(x))]$ as $x→∞$, and then as $c→∞$?
Alternatively, is there any reference that seeks an answer to above questions?
Which tools can be used to solve the above?
 A: There are some basic results about LCM that you can use.  Here's one:
for any increasing sequence of positive integers $a_1 \lt \ldots \lt a_n$, one has
$a_n \leq LCM(a_1 , \ldots, a_n) \leq a_1 \times \ldots \times a_n$ .  So if $a_n$ increases quickly enough, the difference between the logs of the upper and lower bounds will be small compared to the log of the LCM, so the logarithm of the logarithm of the LCM may have a computable limit.
There may be a statistical difference between using $x$ and using $g(x,c)$, but I am having a hard time seeing it for general $x$.  Letting $b_n = LCM(a_1, \ldots, a_n), a_{n+1}$ will have to be pretty special in order for $b_n$ not to be coprime to any number between $a_n$ and $a_n + c$ inclusive even when c is smaller than $\log(b_n)$; even then, most such numbers will have a small factor in common with $b_n$, so you might as well replace $g(a_{n+1},c)$ by a number coprime to $b_n$ that looks like a small multiple or factor of $a_{n+1}/log(b_n)$.
Given that the limiting probability of two positive integers being coprime is $6/\pi^2$,
I would suspect that $b_n$ will "look like" a small multiple of the product of perhaps 2/3 of the members of the increasing sequence in the case that the increase in a_n is exponential or near exponential.  If your sequence increases slowly, the LCM will most likely increase in a fashion similar to the factorial or primorial function.
If you provide some motivation, I may be able to give some definite answers toward the motivating problem.
Gerhard "Ask Me About Jacobsthal's Function" Paseman, 2011.10.13
