8
$\begingroup$

Let $\; X_0,X_1,X_2,X_3,...\;$ be independent and identically distributed (real-valued) random variables.

1. Suppose $\frac1n \cdot\sum\limits_{m=0}^n X_m$ converges in probability. Does it follow that $\operatorname{E}(X_0)$ exists?

2. Suppose $\operatorname{E}(X_0) = 0$ and that $\frac1{\sqrt n} \cdot\sum\limits_{m=0}^n X_m$ converges in distribution to a normal random variable. Does it follow that $\operatorname{E}((X_0)^2)$ is finite?

(I already found that the converse of the strong law of large numbers holds.)

$\endgroup$
12
  • $\begingroup$ a remark. The weak law fails for the Cauchy distribution. $\endgroup$ Commented Aug 25, 2011 at 12:01
  • 2
    $\begingroup$ A classical example for 1'. is a symmetric integer-valued X with P(X=n)=P(X=-n)=c/(n^2log(n)). Then phi is C^1 but X is not integrable. On the other hand, if phi is C^2 then X^2 is integrable. $\endgroup$
    – Did
    Commented Aug 25, 2011 at 12:44
  • 2
    $\begingroup$ Didier, this gives a counterexample to 1, right? I think the last line in the question means that if one replaces, in 1, convergence in probability by a.s. convergence, then the answer is yes (by say the converse to Borel-Cantelli). $\endgroup$ Commented Aug 25, 2011 at 12:59
  • 5
    $\begingroup$ Necessary and sufficient conditions (in terms close to those you want) for the WLLN and the CLT can be found, e.g., in "Foundations of modern probability" by Kallenberg (Theorems 4.16 and 4.17). $\endgroup$ Commented Aug 25, 2011 at 14:09
  • 2
    $\begingroup$ @Ricky in the 2nd Edition it's Theorems 5.16 and 5.17 $\endgroup$
    – pgassiat
    Commented Aug 25, 2011 at 23:48

1 Answer 1

8
$\begingroup$

(As suggested, I promote my comment to an answer, with pgassiat's complement.)

Necessary and sufficient conditions (in terms close to those you want) for the WLLN and the CLT can be found, e.g., in "Foundations of modern probability" by Kallenberg (Theorems 4.16 and 4.17 in the first edition, Theorems 5.16 and 5.17 in the second edition).

$\endgroup$

You must log in to answer this question.