0
$\begingroup$

Given n vectors $w_1,\dots, w_n$ in $R^d$ we consider the functional $\phi$ defined on polynomials by $\phi(p)= \partial_{w_1}\dots \partial_{w_n}p(0)$ where $\partial_{w}$ is the directional derivative toward $w$. The question is: Is there a measure $\mu_{w_1,\dots,w_n}$ such that $\phi(p)=\int_{R^d}p(z)d\mu_{w_1,\dots,w_n}(z)$.

$\endgroup$
1
  • $\begingroup$ You would at least need a signed measure: if $d=1$, $w_1=1$, $p=(x-1)^2$, then $\phi(p)$ is negative but $p$ is non-negative. $\endgroup$ Commented May 23, 2011 at 10:57

1 Answer 1

2
$\begingroup$

No: the Dirac delta distribution at a point is a measure but its derivatives are not.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .