Interesting examples of flasque sheaves? Does anyone know any interesting examples of flasque sheaves? Ideally, I would like to see one that both arises naturally and is geometric in some sense. On the other hand, I know so few examples other than direct products of stalks that I would be happy to see anything new.
 A: In the spirit of Georges' beautiful example, note that the usual computation of cohomology of an invertible sheaf on a complete curve proceeds largely by means of the simplest types of flasque sheaves.  Recall given L, the natural map from rational sections of L to the "principal parts" of those sections, is a flasque resolution of L, so computes H(L). I.e. the induced map on global sections is a linear map of infinite dimensional spaces with finite dimensional kernel and cokernel: H^0(L) and H^1(L).  In particular, since this is a 2 step complex, H^r(L) = 0 if r > 1. 
To compute more one typically approximates this resolution by a smaller one. Restricting to a fixed divisor D, we get a subresolution L(D)-->L(D)|D, with finite diml global sections, hence more useful for computing H(L).  Since L(D) restricted to D is also flasque, we get the formula chi(L(D)) - chi(L) = deg(D), for all L,D.  Using the result in Georges' answer above, this includes weak Riemann Roch: chi(L) - chi(O) = deg(L).
This is as far as we can go with only flasque sheaves since L(D) is not flasque.  But if we choose D with H^1(L(D)) = 0, we have an acyclic subresolution L(D)-->L(D)|D, of the original flasque resolution of L.  This gives a map of fairly explicit finite dimensional spaces with kernel and cokernel isomorphic to H^0(L), H^1(L).  
Thus most of the standard theory of invertible sheaves on curves arises from these concrete examples of the simplest flasque sheaves, i.e. constant sheaves of rational sections as in Georges' answer, and direct sums of stalks, illustrating further how useful those apparently trivial cases can be. (see Kempf, Abelian Integrals.) 
A: I don't think that they could be very geometric unless you regard spaces with Zariski-like topology as geometric. For example, sheaves naturally arising on smooth manifolds are rather soft, not flasque.
But on an irreducible topological space (e.g. an algebraic variety), there are examples. For example, any locally constant sheaf is flasque. 
A useful example is that of injective modules. Assume your space $X$ is endowed with a sheaf of local rings $\mathcal{O}_X$. Then any injective $\mathcal{O}_X$-module is flasque. I don't think that this is geometric though, because injective modules are rather artificial monsters used to define derived functors than naturally arising objects.
Edit. Concerning the title of your question, I think of a flasque sheaf as a synonym for a very very uninteresting sheaf (i.e. for which most statements become trivial).
A: An exemple of flasque sheaf is the sheaf of hyperfunction. It has important application in the theory of D-modules.
A: the field of rational functions $\mathcal K_X$  on an integral scheme $X$ ( for example an algebraic variety)  is flasque and so is the sheaf of its invertible elements $\mathcal K^\ast_X$. This has as a nice consequence that the  divisor class group $CaCl(X)$ of Cartier divisors on $X$ is isomorphic to the Picard group $Pic(X)$ of isomorphism classes of line bundles on $X$. Indeed we have an exact sequence of sheaves of abelian groups on $X$:
$$0\to \mathcal O^\ast_X  \to \mathcal K^\ast_X  \to       \mathcal K^\ast_X/ \mathcal O^\ast_X    \to0   $$
Taking the associated long exact sequence of cohomology we get the portion
$$\Gamma (X,\mathcal K^\ast_X)  \to      \Gamma (X, \mathcal K^\ast_X/ \mathcal O^\ast_X )   \to H^1(X,\mathcal O^\ast_X)  \to H^1(X,\mathcal K^\ast_X)$$
The cokernel of the first arrow is precisely $CaCl(X)$, whereas  the  cohomology group $H^1(X,\mathcal O^\ast_X)$ is the Picard group $Pic(X)$.  And now for the sting:  $H^1(X,\mathcal K^\ast_X)=0$
because $\mathcal K^\ast_X$ is flasque, hence acyclic ! And we have our isomorphism 
$CaCl(X) \simeq Pic(X)$,  the paraphrase  of which being that every line bundle on $X$  comes from a Cartier divisor, unique up to linear equivalence..
