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Some other people and I have noticed that the following seems to be true.

Fix an integer polynomial $P \in \mathbb{Z}[x]$. Let $a_n$ be the number of roots of $z^n + P(z) = 0$ that lie in the unit disk, ie $|z| \le 1$. Then there exists positive integer $k$ and nonnegative integer $m$ such that $a_{n+k} = a_n + m$ holds for all sufficiently large $n$.


Here's some graphs of small examples. $k$ here is the suspected value.

As such, the question we have is whether this conjecture holds. If it does not, then the followup question becomes why it seems to be periodic for small $n$, as well as for what, if any, subset of $\mathbb{Z}[x]$ it holds. If it is does end up being true, then we wonder if there's any nice relation between $P$ and $k, m$ (though $93$ being the period suggests not).

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1 Answer 1

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I am afraid that this is too good to be true. Consider the polynomial $P(z)=2z+2$. There are two points on the unit circle, $\alpha$ and $\bar{\alpha}$, for which $|P(\alpha)|=|P(\bar{\alpha})|=1$. Also note that $\alpha$ is not a root of unity (it solves the equation $(2z+2)(2/z+2)=1$, i.e., $4(z+1/z)=-7$, so, it is not even an algebraic integer).

$\alpha$ and $\bar{\alpha}$ partition the unit circle onto two arcs $D_+$ and $D_-$, on $D_+$ we have $|P(z)|>1$, on $D_-$ we have $|P(z)|<1$. Let's count the number of roots of $z^n+P(z)$ inside the unit circle by the argument principle. On $D_+$ we have $z^n+P(z)=P(z)(1+z^n/P(z))$, the second factor lies in the right half-plane, thus, its argument is changed by $O(1)$ when we go along $D_+$. The same holds for the argument change of $P(z)$. On $D_-$, we write $z^n+P(z)=z^n(1+P(z)/z^n)$, again the second factor has bounded change of the argument, while the first factor has the change of argument $\theta\cdot n$, where $\theta$ is the length of $D_-$. But $\theta/\pi$ is irrational (that is equivalent to $\alpha$ not being a root of unity), thus, $\lim a_n/n$ is irrational. This contradicts to the existence of such $k$ and $m$.

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