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Theorem III.8.7 in Sharpe and Chern's "Differential Geometry: Cartan's Generalization of Klein's Erlangen Program" states:

If $M$ is a simply connected manifold, $\mathfrak{g}$ is a Lie algebra, and $\omega\in\Omega^1(M,\mathfrak{g})$ is such that

  1. $\mathrm{d} \omega+\frac12[\omega,\omega]=0$;
  2. $\omega_x:T_xM\to \mathfrak{g}$ is an isomorphism for each $x\in M$;
  3. $\omega$ is complete (i.e. each constant vector field is complete),

then $M$, with any choice of identity, has a unique Lie group structure whose Maurer-Cartan form is $\omega$.

My issue is with the proof: it never explicitly uses $\omega$'s completeness. In fact, it cites a "Fundamental Theorem" that doesn't directly apply:

Fundamental Theorem:

If $(M,x_0)$ is simply connected, $G$ is a Lie group with Maurer-Cartan form $\theta_G$, and $\eta\in \Omega^1(M,\mathfrak{g})$ satisfies the structure equation $\mathrm{d}\eta+\frac12[\eta,\eta]=0$, then for any $g\in G$ there is a unique smooth map $f:M\to G$ such that $f(x_0)=g$ and its logarithmic derivative $\delta f:=f^\ast\theta_G$ coincides with $\eta$.

The idea is to construct maps $m:M\times M\to M$ and $i:M\to M$ that act as the multiplication and inversion map. For that, they construct $1$-forms $\eta$ that are expressed in terms of $\omega$ the same way log-derivatives of a multiplication or an inversion map would be in terms of the MC form, and then check that $\mathrm{d}\eta+\frac12[\eta,\eta]=0$. Then they cite the Fundamental Theorem to reconstruct two unique maps $m:M\times M\to M$ and $i:M\to M$. However, the Fundamental Theorem obviously doesn't apply because the target manifold, $M$, isn't a Lie group yet.

This seems to be the place where completeness should come in. I suppose one needs to show that the Fundamental Theorem holds not just for Lie group targets, but for all targets with a $1$-form $\omega$ that satisfies all 3 conditions above. The book skips over this part, proving that the Maurer-Cartan form can be developed along any path before they even discuss the concept of completeness.

Does anyone have intuition for what is necessary to complete the proof?

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    $\begingroup$ Sharpe is the only author of the cited book. Chern is not an author. $\endgroup$ Commented Jun 28 at 18:23
  • $\begingroup$ @DmitriPavlov ah, indeed, just foreword. $\endgroup$ Commented Jun 28 at 18:32
  • $\begingroup$ You correctly pointed out that the fundamental theorem should be generalized in the way you described. Completeness is necessary to prove the analogous generalization of Theorem 7.1. The second paragraph of its proof implicitly uses the fact that there is a unique primitive taking the given value at some fixed point in the interval. The analogous statement for arbitrary M uses the completeness property of the 1-form precisely at this point. $\endgroup$ Commented Jun 28 at 19:20
  • $\begingroup$ @DmitriPavlov do you know how to show the existence of a unique primitive? On Lie groups, I can just take a finite number of local primitives and stitch them together by translating their values. But without a group structure it seems like I would need to show that any automorphism of $(G,\omega)$ is uniquely determined by its value at one point. And I'm not sure how to do that. $\endgroup$ Commented Jun 28 at 22:59
  • $\begingroup$ @DmitriPavlov oh, is the argument for developments simply that $\omega^{-1}(\eta(\dot\gamma(t)))$ is a time-dependent vector field, which at every $t$ is complete, and hence is complete itself? I'm not sure if such a theorem for flows of time-dependent vector fields actually holds though. $\endgroup$ Commented Jun 29 at 2:40

1 Answer 1

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On $M\times G$, the Pfaffian system $\omega-g^{-1}dg$ arises from a foliation, by the Frobenius theorem. Let $\tilde{M}$ be a leaf, i.e. a maximal integral manifold of the foliation, through some point $(m_0,1)\in M\times G$. The constant vector fields then live on $\tilde{M}$, pulled back from both local diffeomorphisms to $M$ and to $G$, since locally $\tilde{M}$ is the graph of a local diffeomorphism matching the Maurer-Cartan forms, so matching the constant vector fields. By a theorem of Ehressman (Theorem B.2 in my Introduction to Cartan geometries, but the proof is very easy), the completeness of the vector fields ensures that both $\tilde{M}\to M$ and $\tilde{M}\to G$ are covering maps. This is where the completeness is needed: a local diffeomorphism matching up complete vector fields on connected manifolds is a covering map.

Every connected covering space of a connected Lie group is a Lie group for a unique Lie group structure for which the covering map is a local isomorphism of Lie groups. I think you can find the proof of that statement in many textbooks on Lie groups. The covering map $\tilde{M}\to G$ makes $\tilde{M}$ a Lie group. The covering map $\tilde{M}\to M$ is a diffeomorphism, because $M$ is connected and simply connected.

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  • $\begingroup$ That's a cool proof, although I'm a bit perplexed as to why Sharpe didn't include it (the Ehresmann theorem is already in the book!). Nevertheless, the proof via developments also seems quite valuable. $\endgroup$ Commented Jul 8 at 16:01
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    $\begingroup$ @AlexBogatskiy: I agree that the proof by developments is valuable. I am ashamed that even after reading Sharpe's book (when I was his master's student), I wrote a paper proving Ehresmann's theorem, without noticing that it was already known. $\endgroup$
    – Ben McKay
    Commented Jul 8 at 17:46
  • $\begingroup$ By the Frobenius theorem, the developments lie on the leaves. We can look at the developments as just lifting each curve in $M$ by the covering map $\tilde{M}\to M$, then mapping each point of that lifted curve by $\tilde{M}\to G$. $\endgroup$
    – Ben McKay
    Commented Jul 8 at 17:56
  • $\begingroup$ ah, of course. Thank you! I have yet to understand developments in more general Cartan geometries, so this is a very nice prototype. $\endgroup$ Commented Jul 8 at 22:22
  • $\begingroup$ The latest draft of my Introduction to Cartan geometries (arxiv.org/abs/2302.14457) gives the proof I gave above, with much more detail. $\endgroup$
    – Ben McKay
    Commented Jul 9 at 12:15

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