Borel measures on the Martin boundary and the Poisson-Martin representation theorem

I have been studying the construction of the Martin boundary on a discrete set $$X$$ admitting an irreducible transient random walk $$(X,P)$$ from Wolfgang Woess' book titled "Random Walks on Infinte Graphs and Groups", where I came across the Poisson-Martin representation theorem which has been stated below:

For every positive harmonic function $$h$$ on a $$X$$, there is a positive Borel measure $$\nu^h$$ on the Martin boundary $$\mathcal{M}$$ of $$X$$ such that $$h(x)=\int_{\mathcal{M}} K(x,.) \mathrm{d} \nu^h$$ where $$K(.,.)$$ denotes the Martin kernel corresponding to $$(X, P)$$.

I also read about the Martin boundary on the Encyclopedia of Mathematics, where it is stated that for certain choices of $$X$$ (say $$X$$ is a bounded domain in $$\mathbb{R}^n$$ or a Green space), the Borel measure $$\nu^h$$ is actually a Radon measure. One question that intrigues me is whether we can always expect the Borel measure $$\nu^h$$ occurring in the above theorem to be a Radon measure? If not, can we expect that $$\nu^h$$ is a finite measure on $$\mathcal{M}$$? Is it finite on any compact subset of $$\mathcal{M}$$? Any help or reference is deeply appreciated. Thanks in advance!

There is one more ingredient in the definition of the representing measure $$\nu^h$$ missing in your description. This is a reference point $$o$$ from the state space (more generally, a probability measure on the state space), so that it would be more appropriate to use the notation $$\nu_o^h$$. The functions $$\phi$$ representing the points of the Martin boundary are normalized by requiring that $$\phi(o)=1$$. [In a more invariant language, in order to use the Choquet theory for the convex cone of positive superharmonic functions one has to fix a convex compact base of that cone.] It implies that the representing measure $$\nu^h_o$$ is actually finite, and its mass is $$h(o)$$.