primary regular sequences

Let $$R$$ be commutative regular local ring. Is it true, that for every $$\mathfrak p \in \mathrm{Spec}(R)$$, there is a $$\mathfrak p$$-primary $$R$$-regular sequence? (I.e. an $$R$$-regular sequence $$\bf x$$ such that the ideal $$({\bf x})$$ is $$\mathfrak p$$-primary.)

• Try $p=0$. Commented Nov 21, 2010 at 23:16
• @Martin: it is a matter of convention. See the Remark here jstor.org/pss/2160211 Commented Nov 22, 2010 at 9:23

EDIT: here is a counter-example for the question in general. Let $P \subset R= \mathbb C[[x,y,z,a,b,c]]$ be generated by the $2$ by $2$ minors of the obvious $2$ by $3$ matrix. Then the local cohomology module $H_P^3(R) \neq 0$ (see page 201 of this book), so $P$ can't be a radical of a $2$-generated ideal.
This is a hard question even for small rings. Let $R=\mathbb C[[x,y,z]]$ and $P$ a prime ideal of height $2$. Your question is the same as asking if the curve $X= \text{Spec} (R/P)$ is always a set-theoretic complete intersection. This is widely open even in this case (space curves over complex numbers).
An amazing partial result is obtained by Cowsik-Nori: every curve in affine space over a field of characteristic $p>0$ is a set-theoretic complete intersection! See this paper by Hartshorne for some relevant references.