2
$\begingroup$

The gap of a bounded linear operator on a Hilbert space is defined as $$\operatorname{gap}(A) := \|A\| - r(A),$$ where $r(A)$ denotes the spectral radius of $A$. A natural question to ask is - for which operators is $\operatorname{gap}(A) > 0$ (vs. $\operatorname{gap}(A) = 0$)? A simple but not satisfying fact is that $\operatorname{gap}(A) = 0$ for all normal operators $A$. Even after a detailed search, I could find just one paper that studies gaps to some extent (here.)

Thanks!

$\endgroup$
2
  • 2
    $\begingroup$ I think you need to consider related operators $B = S^{-1}AS$, where $S$ is invertible. The spectral radius for $B$ is the same as for $A$, but the norm may be different. I believe (I read somewhere long ago?) the infimum of all these norms is the spectral radius. $\endgroup$ Commented Apr 4 at 14:48
  • $\begingroup$ Notice that a nilpotent operator $A$ has $r(A) = 0,$ whereas $\|A\|$ can be arbitrarily large, so I wonder what sort of answer you would regard as useful in your context? $\endgroup$ Commented Apr 5 at 9:18

0

You must log in to answer this question.

Browse other questions tagged .