A well-known theorem of Caratheodory states that any point in the convex hull of a set $X\subset R^n$ lies in the convex hull of at most $n+1$ points of $X$. I am wondering about a version of this phenomenon where $X$ changes continuously and we want to select the points continuously.

Specifically, suppose that we have a continuous family of curves $\Gamma_t\subset R^n$, $t\in[0,1]$, such that the origin $o$ of $R^n$ is always contained in the convex hull of $\Gamma_t$. Can one find a finite number of points $x_i(t)\in\Gamma_t$ so that $t\mapsto x_i(t)$ is continuous, and $o$ is contained in the convex hull of $x_i(t)$?

By continuity here I mean that there exists a family of continuous maps $\gamma_t\colon[a,b]\to R^n$, with $\gamma_t([a,b])=\Gamma_t$, such that $t\mapsto\gamma_t$ is continuous with respect to the standard norm on $C^0([a,b],R^n)$. This is finer than the topology induced by Hausdorff distance.

**Note 1:** The answer is yes if the convex hull of each $\Gamma_t$ has interior points, and $o$ is one of them. Then, by Steinitz refinement of Caratheodory's theorem, for each $t$ there are $2n$ points $x_i(t)\in\Gamma_t$ which contain $o$ in the interior of their convex hull. So by continuity we can always select a finite number of points for a short time interval, and compactness of $[0,1]$ completes the argument.

**Note 2:** Anton Petrunin gives an example below which shows that the answer is no if the space of curves is equipped with Hausdorff topology. In particular there exists a family of intervals in the circle $S^1$ converging to $S^1$ from which one cannot select a point continuously (the intervals spin around $S^1$ faster and faster as they get longer).

**Note 3:** Pietro Majer gives an example below which shows that even when the points $x_i(t)$ can be chosen continuously, we cannot in general find continuous coefficients $c_i(t)$ such that $\sum c_i(t)x_i(t)=o$.