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While reading the article [1], I noticed I don't understand part of the proof of regularity. For the Schrödinger eigenvalue problem,

\begin{cases} -\Delta u+Vu=\lambda u, &\text{in } \Omega \\ \Vert u\Vert_{0,\Omega}=1 \end{cases} where

  • $\Omega$ is a bounded domain in $\mathbb{R}^3$ and
  • $V =\frac{1}{|x|}$.

Define $$a(u,v)=\int_\Omega \nabla u\nabla v+Vuv,\ u,v\in H_0^1(\Omega)$$ A number $\lambda$ is called an eigenvalue of the form $a(\cdot, \cdot)$ relative to the form $(\cdot, \cdot)$ if there is a nonzero vector $u\in H_0^1(\Omega)$, called an associated eigenfunction, satisfying $$ a(u,v) = \lambda(u,v)\quad\forall v \in H_0^1(\Omega).$$ Now, if $(\lambda, u) \in \mathbb{R}\times H_0^1(\Omega)$ and $Vu \in L^2(\Omega)$, can we deduce from the regularity of the Poisson equation that $u=(-\Delta )^{-1} (Vu+\lambda u) \in H^2(\Omega)$?

[1] Gong, Xingao; Shen, Lihua; Zhang, Dier; Zhou, Aihui, "Finite element approximations for Schrödinger equations with applications to electronic structure computations", J. Comput. Math. 26, No. 3, 310-323 (2008). MR2421883, Zbl 1174.65047.

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    $\begingroup$ satisfying what? Your text ends abruptly. $\endgroup$
    – gmvh
    Commented Dec 10, 2023 at 16:19
  • $\begingroup$ Also isn't your equation the one for the hydrogen atom? $\endgroup$
    – lcv
    Commented Dec 10, 2023 at 19:11
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    $\begingroup$ Sorry, I saved it incorrect. I have edited the question. $\endgroup$
    – Du Xin
    Commented Dec 11, 2023 at 2:06
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    $\begingroup$ it's a simple schrodinger equation which can describe the hydrogen atom. $\endgroup$
    – Du Xin
    Commented Dec 11, 2023 at 2:06
  • $\begingroup$ If you want to use elliptic regularity for the Laplacian to bootstrap the regularity of $u$, then you need to assume suitable smoothness of the boundary of the domain. $\endgroup$
    – Hannes
    Commented Dec 11, 2023 at 15:40

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