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It turns out that a very important idea to derive properties for a bigger space is to try to foliate the space, derive the same property for each leaf and patch everything up to get the desired conclusion.

My question is: Is it possible/Is there any reference about the possibility of foliating the Euclidean space with boundaries of strictly convex sets (like with boundaries of balls?).

Is there any characterization of a Riemannian manifold so that it can be foliated by leaves made by boundaries of convex sets?

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Without specifying additional properties for your leaves this is likely not a very interesting question. An open half-space in Euclidean space is convex and its boundary is a hyperplane. The set of hyperplanes that is orthogonal to a given line trivially foliates Euclidean space. Something tells me that is likely not what you meant?

The added strict convexity requirement doesn't pose much of a challenge either. Firstly, you probably mean that the leaves should be boundaries of sets whose closure is strictly convex, otherwise the above example is still valid. A construction for such a foliation in 2D would be the boundary $y=x^2$ of the strictly convex halfspace $y\geq x^2$ and its vertical translates. In higher dimensions, use this same idea to generate a radially symmetric such foliation (symmetric around one of the coordinate axes).

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  • $\begingroup$ You are right, I had in mind at least some strict convexity $\endgroup$ Commented Oct 12, 2023 at 7:05
  • $\begingroup$ I totally agree the Euclidean setting case is kind of trivial. I am asking now if there is some characterization on Riemannian manifolds so that one can be always able to find such a foliation (think about closed manifolds like the two- or three- sphere, they do not admit a foliation by convex sets either). (Thanks for your answer by the way) $\endgroup$ Commented Oct 14, 2023 at 22:51

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