3
$\begingroup$

The totality of all holomorphic functions on the unit disk forms some sort of infinite-dimensional complex manifold, where the coefficients of the Taylor expansion might serve as coordinates for the space.

Passing from the functions to their zero-sets fibers this set over the space of infinite discrete subsets of the disk, also some sort of infinite-dimensional complex manifold.

I'd like to know if there's a general obstruction to the existence of any kind of holomorphic cross-section. Perhaps even there are no non-constant holomorphic functions on the base space at all?

I understand that there's no naive generalization available from the usual elementary symmetric polynomials to infinitely many variables. Indeed the delicate nature of the Weierstrass factorization theorem reflects that. So I suppose I'm looking for a general principle that would imply that any Weierstrass-like theorem must involve, in an essential way, putting something like an order on the zero set, so that the output can't vary nicely across all zero-sets.

$\endgroup$
5
  • $\begingroup$ What topology on the discrete subsets of $D$ do you have in mind here? $\endgroup$ Commented Oct 5, 2023 at 13:43
  • $\begingroup$ I was trying not to be too specific in case someone knew a relevant theorem. But I'd be happy with the Hausdorff metric. I'd be happy with considering first sequences, considering them in the product (topology) of countably many disks, then taking a quotient by the action of the full symmetric group. $\endgroup$ Commented Oct 5, 2023 at 17:00
  • $\begingroup$ I don't see why the Weierstrass factorization theorem can't apply in a canonical way. You can just choose an ordering on the zero set in order of nondecreasing modulus, and choose your elementary factors $E_{p_n}$ with $p_n = n$. See Conway, Functions of One Complex Variable, theorems VII.5.12 and VII.5.15. For whatever natural complex structure you choose on the spaces involved I expect this section would be analytic. $\endgroup$
    – Vik78
    Commented Oct 7, 2023 at 18:51
  • $\begingroup$ If you have a tie between the modulus of two zeros, then a perturbation could flip how they stand in the order, causing a discontinuity in the choice of elementary factors, right? $\endgroup$ Commented Oct 8, 2023 at 16:41
  • $\begingroup$ In general a path in ordered-zero-set space space that induces a permutation on the zeros, so a loop in unordered-zero-set space will drag along an discrete invariants attached to the zeros. $\endgroup$ Commented Oct 8, 2023 at 18:10

0

You must log in to answer this question.

Browse other questions tagged .