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Let suppose that $S_t$ is a process defined as:

$$ \begin{cases}dS_t = \mu S_t\,dt+m(v_t)\,dW^1_t\\ dv_t = \mu_v(v_t)\,dt + \sigma_v(v_t)\,dW^2_t\end{cases}$$

where the two Brownian motions have correlation $\rho$. In an article, a property is mentioned and says:

Let $\delta>0$ and $n\in\mathbb{N}^*$, then we have: $$\begin{cases}\mathbb{E}\bigg(\ln^n(S_{t+\delta}/S_t)\bigg|\sigma(S_s,v_s),0\leq s \leq t\bigg) \perp S_t, \\ \frac{\partial}{\partial S_t} \bigg[\mathbb{E}\bigg( \ln^n(S_{t+\delta}/S_t) \bigg| \sigma(S_s,v_s),0\leq s \leq t\bigg)\bigg] = 0. \end{cases}$$

Does anyone have an idea about a proof of this statement ?

Thank you very much!

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    $\begingroup$ can you include in the above post the article title for context? $\endgroup$ Commented Sep 28, 2023 at 16:16

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