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Let $S_{\Bbb N}$ be the countable symmetric group of all permutations of the naturals with finite support and $A_{\Bbb N}$ --- the corresponding alternating group. How to describe all maximal subgroups of these groups which are isomorphic to $S_{\Bbb N}$? Is it possible to obtain the answer from well-known answers on the same question for the finite case?

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    $\begingroup$ What do you mean with "of type $S_{\Bbb N}$"? $\endgroup$
    – Wojowu
    Commented Jul 24, 2023 at 12:30
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    $\begingroup$ Can the 2nd sentence in the question be formulated as follows: I'd like to describe all maximal subgroups of $S_{\mathbb{N}}$ (and also of $A_{\mathbb{N}}$) that are isomorphic to $S_{\mathbb{N}}$ . $\endgroup$ Commented Jul 24, 2023 at 13:42
  • $\begingroup$ But then for $S_\mathbb{N}$ this would only be the whole group. Any other subgroup cannot be maximal in the poset of subgroups isomorphic to $S_\mathbb{N}$. Maybe we only have to look at proper subgroups ? $\endgroup$ Commented Jul 24, 2023 at 13:57
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    $\begingroup$ According to en.wikipedia.org/wiki/Maximal_subgroup "a maximal subgroup H of a group G is a proper subgroup, such that ..." $\endgroup$ Commented Jul 24, 2023 at 14:08
  • $\begingroup$ @HenrikRüping Why couldn't a maximal subgroup be isomorphic to $S_{\mathbb{N}}$? In $\mathbb{Z}$, all the maximal subgroups ($p\mathbb{Z}$ for $p$ prime) are isomorphic to $\mathbb{Z}$, aren't they? $\endgroup$ Commented Jul 24, 2023 at 15:58

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Here I will follow the notation from Dixon--Mortimer, rather than OP's, because it seems to be more standard, and clearly distinguishes the full and finitary symmetric groups.

Let $\Omega$ be an infinite set. By Dixon--Mortimer (1996), Lemma 8.3A, the only primitive subgroups of $\operatorname{FSym}(\Omega)$ are $\operatorname{FSym}(\Omega)$ and $\operatorname{Alt}(\Omega)$ (briefly, by a classical result of Jordan, if a primitive group $G$ contains an element of support $m$ then $|\Omega| \le (m-1)^{2m}$ unless $G \ge \operatorname{Alt}(\Omega)$). Moreover, for any imprimitive (transitive) subgroup of $\operatorname{FSym}(\Omega)$, the blocks must be finite. Therefore the maximal subgroups of $\mathrm{FSym}(\Omega)$ are:

  • maximal intransitive groups $\operatorname{FSym}(X) \times \operatorname{FSym}(Y)$, where $\Omega = X \sqcup Y$ is a nontrivial partition of $\Omega$ into proper nonempty subsets $X$ and $Y$,
  • maximal imprimitive groups $\bigoplus_{i \in I} \operatorname{Sym}(\Delta_i) \rtimes \operatorname{FSym}(I)$, where $\Omega = \sqcup_{i \in I} \Delta_i$ is an equipartition of $\Omega$ into a collection of finite nonempty subsets $\Delta_i$ of equal cardinality,
  • $\operatorname{Alt}(\Omega)$.

The only groups on this list $\cong \operatorname{FSym}(\Omega)$ are the point stabilizers $\operatorname{FSym}(\Omega)_x$.

The same list holds for maximal subgroups of $\operatorname{Alt}(\Omega)$, taking the intersection with the alternating group. The only further groups we get $\cong \operatorname{FSym}(\Omega)$ are stabilizers of a pair of points $\operatorname{Alt}(\Omega)_{\{x,y\}}$.


Old answer, really more about the full symmetric group rather than the finitary one:

Some information is in Dixon--Mortimer (1996), Chapter 8.5, "Maximal subgroups of the symmetric groups". Unfortunately:

The situation for infinite symmetric groups is more complicated, and it seems unlikely that there is a satisfactory description of the maximal subgroups in this case.

I do not think the situation has changed dramatically since 1996.

These lecture notes of Peter Neumann are also worth looking at: https://arxiv.org/abs/2307.11564

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    $\begingroup$ I think this section of Dixon & Mortimer is about the full symmetric group, not the finitary one. $\endgroup$ Commented Jul 24, 2023 at 14:56
  • $\begingroup$ @DaveBenson It is principally, yes, but they also discuss the finitary symmetric group and my reading is that that line also includes that case (but I would be happy to be proved wrong). $\endgroup$ Commented Jul 24, 2023 at 15:03
  • $\begingroup$ Until the question was editted I did not understand that we are restricting here $G \cong S_{\mathbb N}$. Is it possible that every such maximal subgroup is a point stabilizer? Any other example must be primitive. $\endgroup$ Commented Jul 24, 2023 at 15:29
  • $\begingroup$ Similarly in $A_{\mathbb N}$ the natural question is if every maximal subgroup isomorphic to $S_{\mathbb N}$ is the stabilizer of a pair of points. $\endgroup$
    – Will Sawin
    Commented Jul 24, 2023 at 15:34
  • $\begingroup$ I think the answer is yes. Editting now. $\endgroup$ Commented Jul 24, 2023 at 15:35

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