Let $k$ be an algebraically closed field of characteristic $0$ and $G$ a semisimple simply-connected group over $k$. Consider a symmetric variety of the form $X=G/H$, for $H=G^\theta$ the fixed point subgroup of an involution $\theta \in \mathrm{Aut}_2(G)$.
There are several root systems that can be attached to the symmetric variety $X$.
The restricted roots. These are the roots of the form $\tfrac{1}{2}(\alpha-\alpha^\theta)$, for $\alpha$ the roots of $G$. (Here $\alpha^\theta$ denotes the image of $\alpha$ under the natural action of $\theta$ on the roots. I will denote this root system by $\Phi_\theta$ (and the corresponding simple roots by $\Delta_\theta$). This root system is not reduced in general, but one can take the "shortest" elements to make it reduced.
The spherical root system. Following Sakellaridis-Venkatesh (Section 2.1), the spherical root system of $X$ is spanned by the generators of the intersections of the extremal rays of the dual cone to the valuation cone of $X$ with the weight lattice of $X$. Sakellaridis and Venkatesh denote this set of simple roots by $\Sigma_X$.
Sakellaridis and Venkatesh further construct from $\Sigma_X$ another system of simple roots, that they denote by $\Delta_X$, and write $\Phi_X$ for the corresponding root system. I think this is what is called the "minimal root system" in Timashev's book, and the one originally considered by Brion and later generalized by Knop.
Conjecturally (from Knop-Schalke), the Gaitsgory-Nadler dual group $G^\vee_X$ of the variety $X$ is a reductive group with root system $\Phi_X^\vee$, the dual of $\Phi_X$. According to Gaitsgory-Nadler, since $X$ is a symmetric variety, $G^\vee_X$ coincides with the dual group $\check{H}_\theta$ associated to the real form $G_\mathbb{R}$ of $G$ corresponding to $\theta$.
I am confused about these root systems, when they are equal and when they differ, and how do they differ. In particular, I am trying to understand some simple examples, where the computations should be quite explicit.
I would like to understand the example where $G=\mathrm{SL}_n$, for $n=2m$ and $\theta$ is the inner involution given by conjugation by the diagonal matrix with $m$ $1$'s and $m$ $-1$'s. This involution is quasi-split, so the Levi subgroup appearing in Nadler's paper should be the entire Langlands dual group $G^\vee=\mathrm{PSL}_n$. The restricted root system $\Phi_\theta$ associated to this $\theta$ is a reduced root system of type $C_m$, and thus its Langlands dual is $B_m$. However, in Nadler's table, the dual group of this $G/G^\theta$ is precisely of type $C_m$, so $\Phi_\theta$ cannot be isomorphic to the minimal root system $\Phi_X$ yielding the dual group (in fact it is its dual). How can I obtain the system $\Phi_X$ in this case?