Hello:

Suppose $A$ is a finite free $B$-algebra and $B$ is a finite free $C$-algebra. Does anyone know a coordinate-free proof (i.e. without choosing bases) of the identity:

$N_{A/C} = N_{B/C}\circ N_{A/B}$?

Where $N_{A/C}(a)$ is the determinant of mulitiplication by an element $a\in A$, etc...

Thanks!

casting a vote for the question to remain open. $\endgroup$ – Pete L. Clark Nov 6 '10 at 0:094more comments