4
$\begingroup$

For points $x,y,z$ of a metric space $(X,d)$ we write $\mathbf Mxyz$ and say that $y$ is a midpoint between $x$ and $z$ if $d(x,z)=d(x,y)+d(y,z)$ and $d(x,y)=d(y,z)$.

Definition: A metric space $(X,d)$ is called

$\bullet$ medial if for any points $a,b\in X$ there exist unique points $x,y\in X$ such that $\mathbf Maxb$ and $\mathbf Maby$;

$\bullet$ symmetric if $\forall a,b,c,\alpha,\beta\in X\quad(\mathbf Mac\alpha\wedge \mathbf Mbc\beta)\Rightarrow d(a,b)=d(\alpha,\beta)$;

$\bullet$ a line space if $(X,d)$ is nonempty, medial and every bounded sequence in $X$ has a convergent subsequence.

It can be shown that for any distinct points $a,b\in X$ of a medial complete metric space $(X,d)$ there exists a unique isometric embedding $f:\mathbb R\to X$ such that $f(0)=a$ and $f(d(a,b))=b$. This fact implies that line metric spaces are Busemann G-spaces (but not vice versa).

Example: Every strictly convex finite-dimensional Banach space is a symmetric line space (and is homeomorphic to a Euclidean space $\mathbb R^n$).

The famous Busemann Conjecture claims that every Busemann G-space is a topological manifold. This conjecture is known to be true for Busemann G-spaces of topological dimension $\le 4$.

On the other hand, for symmetric line spaces the Busemann Conjecture seems to be true for all dimensions and in the following stronger form:

Conjecture: Every symmetric line space is homeomorphic to a Euclidean space $\mathbb R^n$.

I strongly believe that this Conjecture is true and can be derived from the known theory of homogeneous spaces of Lie groups and the Cartan classification of symmetric Riemannian manifolds. Nonetheless, I cannot find a precise reference in the literature.

So, my question:

Question. Is the Conjecture indeed true? And if yes, what is a proper reference?

Remark: The Conjecture is true if the answer to this MO-question (on contractible homogeneous spaces of Lie groups) is affirmative.

Concerning the "non-symmetric" version of the Conjecture, I am not so optimistic, so ask it as an open

Problem: Is every line metric space homeomorphic to a Euclidean space?

Added in Edit: According to the answer of Shijie Gu to this problem, the Conjecture is indeed true, so the Question has an affirmative answer. Only the Problem remains open (up to my current knowldge). Since this problem is a modification of the Busemann Conjecture which is true for Busemann G-spaces of small dimension, I expect that the answer to Problem is affirmative at least for spaces of small topological dimension, say $\le 4$.

$\endgroup$
7
  • $\begingroup$ I am confused by the definition. Certainly uniqueness in "medial" points out to a more restrictive definition of midpoints (adding $d(x,y)=d(y,z)$ maybe?), right? $\endgroup$ Commented Mar 28, 2023 at 21:16
  • $\begingroup$ I do not think Cartan is relevant here, but Montgomery-Zippin et al should do the job. But maybe you'll have to add the assumption of finite dimension. $\endgroup$ Commented Mar 28, 2023 at 21:31
  • $\begingroup$ @BenoîtKloeckner Thank you for the comment. Indeed, I forgot to add this equality, which is added now. $\endgroup$ Commented Mar 29, 2023 at 3:27
  • $\begingroup$ @MoisheKohan As far as I can understand, Montgomery-Zippin can help in proving that the symmetric Busemann G-space is a homogeneous space $G/H$ of a Lie group $G$, so has a structure of a smooth manifold. But how to prove (from Montgometry-Zippin) that it is homeomorphic to an Euclidean space? Exactly for this task I had an idea to apply Cartan's classification of symmetric spaces. Finite dimension should follow from the compactness of closed balls in the symmetry of a Busemann G-space, namely, from the local compactness of its isometry group. $\endgroup$ Commented Mar 29, 2023 at 3:33
  • $\begingroup$ It is still unclear to me how to get finite dimension (I am worried about some versions of the Hilbert-cube-manifolds). I do not see how one can use Cartan in your setting since he only classifies Riemannian symmetric spaces. $\endgroup$ Commented Mar 29, 2023 at 13:47

0

You must log in to answer this question.