Is there a general formula that sums up all values of $ζ′(2n)$, such that $n\in\mathbb{N}$?

  • $\begingroup$ Other than $-2 \sum_{n=2}^\infty (\log n)n^{-2}/ (1 -n^{-2})^2$? $\endgroup$
    – Will Sawin
    Mar 21 at 12:19
  • $\begingroup$ Yes. I want close form. $\endgroup$
    – L.L
    Mar 21 at 12:24
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    $\begingroup$ Well, it is a real constant completely determined by its definition. But so are $\pi$ and $e$, so what will change if we find some fancy relation between them? Of course, if it were rational, that would make some difference, but I don't think that this will be proved any time soon and I would rather bet that the number is transcendental. In other words, what exactly are you intending to do with that closed form that cannot be done with the series representation? $\endgroup$
    – fedja
    Mar 21 at 13:23
  • $\begingroup$ I think the general expectation is that there is no such "closed form" ... unless we perhaps allow considerably more exotic notions of "closed form", akin to conjectural things about $\zeta(\mathrm{odd})$ (aiming in a different direction than Apery, et al). $\endgroup$ Mar 21 at 17:12
  • $\begingroup$ @fedja Finding closed form expressions for infinite sums is a pretty crucial thing to want to do. You might just have simply asked the OP the motivation for the problem. $\endgroup$ Mar 21 at 22:37

1 Answer 1


Partial answer: in my book Springer Graduate Texts in Math 240 page 142 Exercise 92, I give six equivalent formulas for the very similar sum $\sum_{n\ge2}\zeta'(n)$. I suggest first that you prove the equivalence of the six, and second that you adapt this proof to your sum, which should probably also give you six equivalent formulas.

  • 1
    $\begingroup$ Totally off topic, but that's a wonderful book that I found very useful to me both in learning number theory and learning to love number theory. $\endgroup$
    – anomaly
    Mar 21 at 22:52
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    $\begingroup$ Just for completeness, the title of the book is "Number Theory: Volume II: Analytic and Modern Tools". $\endgroup$
    – Wojowu
    Mar 22 at 1:41

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