I'm not aware of litterature on this, but this is something I have thought about several years ago and never ended-up using or publishing. What is below is me trying to remind myself how it works - unfortunately without my notes.
So,I think a good way to understand the dissolution of a topos is in terms of its universal property. First let me recall how it works from locales (This is done in C1 in the elephant, and I think also in Stone in space but I can't check now)
The frame homomorphism $X \to N(X)$ is universal for frame homomorphism $X \to Y$ that sends all elements of $X$ to complemented element of $Y$.
Note that it is also easy to construct "partial dissolution" where you start form a set $S \subset F$ and construct $N_S(F)$ which is universal for making the element of $S$ complemented. THis can be for example constructed as a subframe of N(F).
The analogous construction for a topos $T$, is:
Definition For T a topos, and I a collection of subobject inclusion $(U_i \subset V_i)_{i\in I}$ in $T$, the dissolution of $T$ at $I$ is (if it exists) a topos $N_I(T)$ endowed with an algebraic morphism $T \to N_I(T)$ which is universal for algebraic morphisms $T \to E$ sending all $U_i \subset V_i$ to complemented subobject inclusion in $E$.
By "algebraic morphism" I just mean "Geometric morphism" but in the $f^*$ direction.
It is easy to construct such $N_I(T)$ when $T$ is a Grothendieck topos and $I$ is a set as a classyfing topos: represent $T$ as a classyfing topos in a way so that all the $V_i$ are sorts and all the $U_i$ are definable subsets and then add sort $C_i$ for the complement of $U_i$ with axioms that forces $C_i$ to be the complement of $U_i$ in $V_i$.
An easy but key lemma is the following:
Lemma Let $T$ be a Grothendieck topos, $(X_i \to Y)_{i\in I}$ be a covering family, $S \subset Y$ a subobject and $S_i = X_i \times_Y S$. Let $f:T \to E$ be an algebraic morphism. each each $f(S_i) \subset f(X_i)$ is complemented then $f(S) \subset f(Y)$ is complemented.
It follows that
Proposition: Let $T$ be a Grothendieck topos, then the dissolution $N(T)$ at all subobject inclusion in $T$ exists.
Proof Take a site of a definition for $T$ and construct the dissolution of $T$ at all subobject inclusion $S \subset c$ where $c$ is representable.
Proposition: $N(Sh(X)) = Sh(N(X))$
Proof Sh(N(X)) is clearly universal for making all $V \subset 1$ complemented in $Sh(X)$. This implies that it also makes all $U \subset V$ for $U,V$ subterminal objects complemented. But as in $Sh(X)$ every object is covered by subterminal objects, this imply that it makes all subobject inclusion complemented because of the lemma.
Finally:
Proposition The dissolution $N(T)$ of a Grothendieck topos can also be constructed internally as sheaves over the internal frame $N(\Omega)$ as suggested in the question.
Proof Reasoning internally in $T$, an algebraic morphism $Sh_T(N(\Omega)) \to E$ for a $T$-topos $E$ is the same as an (so... the unique) algebaic morphism $* \to E$ such that internally it sends every sub-object inclusion to a complemented one. Expressing this externally, $E$ corresponds to a topos with an algebraic morphism $T \to E$ and an extension to $Sh_T(N(\Omega))$ eaxclty means that it sends every subobject to a complemented one, which is exactly the universal property of $N(T)$.