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Let $\lambda\in(0,1)$ be an irrational number such that its continued fraction expansion is bounded (for example, an irrational quadratic number, whose continued fraction is periodic). It is known that the bound $$\left|\lambda-\frac{p}{q}\right|\leq \frac{C}{q^2},$$ where $\frac{p}{q}$ is a convergent (best rational approximation) of $\lambda$, is optimal for some positive constant $C$, namely $$\mathop{\liminf_{p,q\,\in\,\mathbb{Z}}}_{(p,q)=1}\,q |q\lambda-p|>0.$$ Consider now pairs of the form $(\theta,\theta\lambda)$, with $\theta>0$. I would like to understand whether there is a choice of $\theta$ such that $(\theta,\theta\lambda)$ is simultaneously approximabile by rationals with a slightly better bound than $1/q^2$. More precisely, my question is:

does there exists $\theta>0$ such that $$\mathop{\liminf_{p_1,p_2,q\,\in\,\mathbb{Z}}}_{(p_1,q)=(p_2,q)=1}\,\max\{q |q\theta-p_1|,q |q\theta\lambda-p_2|\}=0$$ holds true?

Equivalently, we are asking the following. Let $$W:=\big\{(x_1,x_2)\in \mathbb{R}^+\times \mathbb{R}^+\,\mbox{such that}\mathop{\liminf_{p_1,p_2,q\,\in\,\mathbb{Z}}}_{(p_1,q)=(p_2,q)=1}\,\max_{i=1,2} q |qx_i-p_i|=0\big\},$$ which is a fractal set with Hausdorff dimension $\frac32$. Is it true that $W$ intersects the line passing through $(0,0)$ and $(1,\lambda)$?

A natural candidate for $\theta$ could be a Liouville number, since Liouville numbers have good properties of simultaneous approximation with other irrationals.

It would be already interesting to prove that such a choice of $\theta$ exists for some specific $\lambda$ with bounded continued fraction.

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    $\begingroup$ I believe this is true, depending on whether we can find a number with good continued fraction expansion on the trajectory of rescaling. $\endgroup$
    – katago
    Feb 16, 2023 at 2:45
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    $\begingroup$ I agree, still it is unclear to me how to find a pair in the rescaling trajectory which has simultaneous good approximation. Do you have any suggestion? $\endgroup$ Feb 16, 2023 at 9:43
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    $\begingroup$ I think it is hard to imagine how the continued fraction expansion varies on the trajectory, maybe a good understanding of the gauss map $G(x)=\left\{\frac{1}{x}\right\}=\frac{1}{x}-\left\lfloor\frac{1}{x}\right\rfloor$ will help imagine it, I may not be able to make constructive suggestions because I haven't thought about it before. $\endgroup$
    – katago
    Feb 16, 2023 at 9:52

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