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Let $A$ and $B$ be $R$-algebras. A Hasse-Schmidt $m$-derivation $D : A \to B$ is a tuple $(D_0, D_1, \dots, D_m)$ of $R$-linear maps $A \to B$ satisfying the generalized Leibniz law,

$$ D_k(xy) = \sum_{p + q = k} D_p(x) D_q(y) $$

If $M$ is an $A$-module, an $R$-linear map $D : A \to M$ is an $n$-th-order differential operator (in the sense of EGA) if, for each $x \in A$ the $R$-linear map,

$$ a \mapsto D(xa) - x D(a) $$

is an $(n-1)$-th-order differential operator. Also, a zeroth order differential operator is by definition an $A$-module map $A \to M$.

Now it is easy to show that if $D$ is a Hasse-Schmidt $m$-derivation then each $D_k$ is a $k$-th-order differential operator. In characteristic zero, I believe these operators (ranging over all $D$) generate the entire space of $n$-th-order differential operators. Is this true in positive characteristic?

These operators arise when studying jet schemes. If $X$ is a $k$-scheme, one definition of $J_m(X)$ is the scheme representing the functor,

$$ T \mapsto \mathrm{Hom}(T \times \Delta^m, X) $$

where $\Delta^m = \mathrm{Spec}(k[t]/(t^{m+1}))$. If $X = \mathrm{Spec}(A)$ then this functor restricted to affine schemes $\mathrm{Spec}(B)$ is exactly the functor,

$$ B \mapsto \mathrm{Der}_{\text{HS}}^m(A, B) $$

of Hasse-Schmidt $m$-derivations over $k$ as these correspond to $k$-algebra maps $A \to B[t]/(t^{m+1})$.

Another reasonable definition of the jet scheme is the total space of the jet bundle, $J^m(\mathcal{O}_X)$ which is defined as $\mathcal{O}_{X \times X} / \mathcal{I}_\Delta^{m+1}$ where $\mathcal{I}_{\Delta}$ is the ideal of the diagonal. This bundle is universal for $m$-th order differential operators meaning, $$ \mathrm{Hom}_{\mathcal{O}}(J^m(\mathcal{O}_X), -) = \mathrm{Diff}^m(\mathcal{O}, -) $$

In the case $m = 1$ we see that $J_1(X)$ is the total space of the tangent bundle of $X$ and $J^1(\mathcal{O})$ is a trivial extension of $\Omega_X$ by $\mathcal{O}$ so its total space is just a trivial extension of $J_1(X)$.

What, in general, is the relationship between these two schemes? There are obvious maps from the fact that Hasse-Schmidt derivations are differential operators but I don't see what more can be said.

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  • $\begingroup$ I was asking myself exactly the same question. Thank you for spelling this out. I am also confused. As a side note, it is shown in Vojta's paper "Jets via Hasse-Schmidt derivations", p. 4 that when $X$ is smooth over $k$, $J_1(X)$ is isomorphic to the relative spectrum of the graded sheaf of algebras associated with $J^1({\cal O})$ (for the natural filtration). This only seems to add to the confusion though... $\endgroup$ Commented Feb 15, 2023 at 14:46

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