Is there a name/reference for the following object? We have a vector space $V$ over some field with two associative bilinear operations $\circ,*:V \times V \to V$ which satisfy the interchange law, i.e., $$(a*b)\circ(c*d) = (a\circ c)*(b\circ d) $$ for all $a,b,c,d$ in $V$. My first instinct was to search for "bialgebra" but of course that is an algebra and a coalgebra structure rather than two algebra structures...

3$\begingroup$ If we ignore the requirement that V is a vector space and $\circ,*$ are associative and bilinear, then this question gives some examples of such structures: mathoverflow.net/q/154550/22277 $\endgroup$– Joseph Van NameNov 23 at 21:42

$\begingroup$ There's a related notion in Definition 1 of my paper arxiv.org/pdf/0912.5307.pdf $\endgroup$– André HenriquesNov 29 at 11:06

$\begingroup$ Thanks, @AndréHenriques! Serves me right for asking here before walking over to ask you or Chris :) In my case there is no unital structure to the two algebras, so I am saved from Eckmann Hilton through other means... $\endgroup$– Vidit NandaNov 29 at 13:14
1 Answer
If the operations have units ($a * 1 = a$ etc), then that is simply called a commutative algebra: https://en.wikipedia.org/wiki/Eckmann%E2%80%93Hilton_argument Indeed in that case, $a*b = a \circ b = b * a = b \circ a$.
Otherwise, I don't know if there is an established name. This is an algebra over the BoardmanVogt tensor product of operads $\mathrm{Ass} \otimes_{BV} \mathrm{Ass}$, where $\mathrm{Ass}$ is the operad encoding associative algebras. This is not an uninteresting structure, and it exhibits nontrivial hidden commutativity properties. Here is a summary taken from BoardmanVogt tensor products of absolutely free operads (BremnerDotsenko)
The quoted results are from:
 J. Kock: Note on commutativity in double semigroups and twofold monoidal categories. Journal of Homotopy and Related Structures 2 (2007) no. 2, 217–228.
 M. Bremner, S. Madariaga: Permutation of elements in double semigroups. Semigroup Forum 92 (2016), no. 2, 335–360.
If I had to choose a name, I would call them "double algebras", but I do not believe this is standard. "Double semigroup" certainly is standard terminology, but there is not requirement of linearity.

4$\begingroup$ I will confess that I had to read Prop 1.6 about 5 times before I realized that the two sides of the equality were actually different! For others suffering similarly, note that $x_6$ and $x_7$ are swapped. (And yes, I was indeed aware of EckmannHilton but none of my products are unital). I will wait a bit to see if anyone else has seen the structure and given it a catchy name, and will happily accept this answer otherwise :) $\endgroup$ Nov 24 at 0:42