Suggested by this problem:
Do the sets of all odious / evel numbers meet every infinite arithmetic progression?
A number is odious if it contains an odd number of digits $1$ in its binary representation; otherwise, it is evel. Alternatively, the odious numbers specify the positions of the nonzero values in the Thue–Morse sequence.
Equivalently:
Is it true that any arithmetic progression $an+b$, with $a>0$ and $b$ integers, has a term with an odd number of $1$'s and a term with an even number of $1$'s?
I expect that the answer is in the affirmative unless I am overlooking some simple obstruction.
Without loss of generality, one can assume that the progression is of the form $(an+1)b$ with $a=2^k-1$. Another potentially useful observation: the parity of the number of $1$'s in the binary representation of the integer $z$ is the same as the parity of the sum $z + \lfloor z/2\rfloor + \lfloor z/4\rfloor + \lfloor z/8\rfloor + \dotsb$