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Definition. I say a topological space $Y$ has finite-type if $Y$ is a finite union of open sets $Y=U_1\cup \dotsb \cup U_N$ such that each possible intersection of the $U_i$ is either empty or is contractible to a point.

If $Y$ is finite-type, I am trying to figure out if it is possible to prove the Künneth decomposition formula for $X\times Y$ (where $X$ is an arbitrary topological space) using induction on $N$ above and Mayer–Vietoris.

To do so, the natural path is to consider the MV long-exact sequence of $Y=(U_1\cup \dotsb \cup U_{N-1})\cup U_N$, tensor it with the cohomology of $X$, and then use the Five-Lemma.

The issue is that tensoring with $H^i(X)$ could destroy the exactness. (That's, of course, not an issue if we work over a field.) Is there any way to fix this argument and make the desired conclusion?

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  • $\begingroup$ In general you won't get an isomorphism (for the reason you mentioned) but just a spectral sequence. $\endgroup$
    – user43326
    Commented Nov 1, 2022 at 9:24
  • $\begingroup$ Is this spectral sequence discussed somewhere? Is it possible to prove Kunneth theorem using that? $\endgroup$ Commented Nov 2, 2022 at 0:48
  • $\begingroup$ Presumably you can find reference somewhere, but I don't know where. Yes, the Kunneth theorem is just the case when the spectral sequence degenerates. Just consider spectral sequences as a generalizaion of long exact sequences, and see what you can do with an appropriate long exact sequence when $N=2$ (and what gets messed up by torsion). $\endgroup$
    – user43326
    Commented Nov 3, 2022 at 14:22

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