Let $(R,\mathfrak m)$ be a local Cohen-Macaulay reduced ring of dimension at least $2$. Then, can we find a non-zero-divisor $x\in \mathfrak m$ such that $R/xR$ is again a reduced ring?

If needed, I am willing to assume $R$ is excellent https://en.m.wikipedia.org/wiki/Excellent_ring.

Note: $\dim R\ge 2$ is needed, otherwise $R$ must be regular. Indeed, if $\dim R=1$ and $R/xR$ is reduced for some non-zero-divisor $x$, then $R/xR$ is also Artinian. So $R/xR$ is a field, hence $\mathfrak m=xR$, so $R$ is regular.