$\DeclareMathOperator\Sp{Sp}\DeclareMathOperator\PSp{PSp}\DeclareMathOperator\USp{USp}\DeclareMathOperator\BSp{BSp}\DeclareMathOperator\BUSp{BUSp}\DeclareMathOperator\BPSp{BPSp}$Let $\USp(n,\mathbb{C})$ and $\Sp(n,\mathbb{C})$ be the compact symplectic group and the symplectic group, respectively. This is, $$ \Sp(n,\mathbb{C})=\left\{A\in M(2n,\mathbb{C}): A^{tr}J_{2n}A=J_{2n}\right\} $$ where $M(n,\mathbb{C})$ is the set of $n\times n$ matrices with entries in $\mathbb{C}$, $$ J_{2n}=\begin{pmatrix} 0 & I_{n}\\ -I_{n} & 0\\ \end{pmatrix}, $$ and $\USp(n,\mathbb{C})$ is isomorphic to $\Sp(n,\mathbb{C})\cap \mathrm{U}(2n,\mathbb{C})$. Let $\PSp(n,\mathbb{C})$ be the projective symplectic group, i.e. $\Sp(n,\mathbb{C})/\{\pm I_{2n}\}$.
It can be shown that the inclusion $\USp(n,\mathbb{C}) \to \Sp(n,\mathbb{C})$ is a homotopy equivalence.
[Hatcher, AT, pg 271 and 381] says that the quaternionic Grassmannian $G_{m}(\mathbb{H}^{\infty})$ is a model for $\BUSp(n,\mathbb{C})$, and that the integral cohomology $H^{*}(G_{m}(\mathbb{H}^{\infty}))\cong \mathbb{Z}[\alpha_{1},\alpha_{2},\dots,\alpha_{m}]$ with $|\alpha_{i}|=4i$.
This result makes you think that $\BSp(n,\mathbb{C})$ has a CW structure with cells only in degrees $4i$. I would like to find such structure for $\BSp(n,\mathbb{C})$ and also, know whether this structure induces one of the same kind in $\BPSp(n,\mathbb{C})$.
The closest thing I know about their CW structures is that $G_{m}(\mathbb{H}^{\infty})$ has a CW structure with each $G_{m}(\mathbb{H}^{k})$ a finite subcomplex, [Hatcher, VB and Kthy, pg 31-34].
Thank you for your ideas.