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Jacobi’s formula says: $\frac{d}{dt}\text{det}(A(t))=\text{det}(A(t)) \cdot \text{tr}(\text{Ad}(A(t))\cdot\frac{d}{dt}(A(t))$.

Exists maybe a variation of the Jacobi’s formula where $\text{det}(\frac{d}{dt}(A(t))$ is involved (For a relation between $\frac{d}{dt}\text{det}(A(t))$, $\text{det}(A(t))$ and $\text{det}(\frac{d}{dt}(A(t))$?

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  • $\begingroup$ I think either your adjugate should be the inverse, or you should drop the $\det A(t)$. $\endgroup$
    – Fred Hucht
    Commented Aug 30, 2022 at 19:05

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