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I'm doing some archeology and trying to understand a claim. As summed up by David Roberts, on the FOM list in 2011:

Let the statement "every infinite sequence of rationals in [0,1] has an infinite Cauchy 1/n subsequence" be denoted CSR. I have seen [Friedman] make this similar statements involving CSR several times…

In this MO answer, Andrej Bauer notes that CSR is false in the effective topos:

Consider a Specker sequence which has no accumulation point in a strong sense, so it cannot have a convergent subsequence.

What I'm currently puzzling over is that CSR appears false classically, too. Let $F$ be the Fibonacci sequence, and let $p$ be the sequence of Padé approximants to the golden ratio $\phi$, or rather to the conjugate golden ratio $\phi - 1$:

$$p_i = \frac{F_i}{F_{i+1}}$$

$p$ satisfies CSR; it converges to $\phi - 1$. But now define the sequence $q$:

$$q_i = \sum_{0}^{i}{p_i} \pmod{1}$$

$q$ is quasirandom and should visit every Cauchy bucket infinitely often, just like $\phi$. I wrote some Python code to verify this claim; try something like asBuckets(f, 400, 8) to take $q_{400}$ with $2^8$ binary Cauchy buckets. At the same time, $q : \mathbb{N} \to \mathbb{Q}$ is an infinite sequence of rationals.

I think that Friedman knew all of this. So, what hidden assumptions are not stated in Friedman's wording of CSR?

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    $\begingroup$ I don’t follow why you think $(q_i)$ should be a counterexample to CSR. Here’s the simple classical proof outline for CSR: (1) any infinite sequence in $[0,1]$ has a convergent subsequence; then (2) for any specified modulus of converegence/Cauchyness, any Cauchy sequence has a subsequence converging at the specified rate. It seems clear how to apply these steps to your $(q_i)$? $\endgroup$ May 15, 2022 at 16:12
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    $\begingroup$ Visiting every Cauchy bucket makes it easier to find convergent subsequences. $\endgroup$ May 15, 2022 at 18:15
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    $\begingroup$ To clarify my previous comment: CSR doesn't assert that there is a unique such subsequence - in any sense. Having the initial sequence be "randomly spread out" just means it has lots of such rapidly-convergent subsequences, converging to lots of different things. (Separately, I think this would be more appropriate for MSE.) $\endgroup$ May 16, 2022 at 17:30
  • $\begingroup$ @NoahSchweber: I have no problem with this being moved to MSE; I thought MO was the proper place for archeological queries, but I don't really care either way. $\endgroup$
    – Corbin
    May 16, 2022 at 18:39
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    $\begingroup$ @Corbin It doesn't matter that they don't stay (and AoC plays no role here). For example: pick the first element that lands in the first "level-1" Cauchy box $B_1$; now pick the first element after that one that lands in the first "level-2" Cauchy subbox $B_2$ of $B_1$; now pick the first element after that one that lands in the first "level-3" Cauchy subbox $B_3$ of $B_2$; etc. This process is totally choice-free due to the "pick the first" bit, and is quickly convergent. I think you might be thinking of "subsequence" in the more restrictive sense of just throwing away an initial segment? $\endgroup$ May 16, 2022 at 18:50

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